Tính
A=\(\dfrac{2^{19}\cdot27^3-15\cdot\left(-4\right)^9\cdot9^4}{6^9\cdot2^{10}+\left(-12\right)^{10}}\)
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Tính: \(\dfrac{2^{19}\cdot27^3-15\cdot\left(-4\right)^9\cdot9^4}{6^9\cdot2^{10}+\left(-12\right)^{10}}\)
\(=\dfrac{2^{19}\cdot3^9+3\cdot5\cdot2^{18}\cdot3^8}{2^9\cdot2^{10}\cdot3^9+2^{20}\cdot3^{10}}\)
\(=\dfrac{2^{19}\cdot3^9+3^9\cdot2^{18}\cdot5}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}\)
\(=\dfrac{2^{18}\cdot3^9\left(2+5\right)}{2^{19}\cdot3^9\cdot\left(1+2\cdot3\right)}=\dfrac{1}{2}\)
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Thực hiện phép tính sau :
A=\(\frac{2^{19}\cdot27^3-15\cdot\left(-4\right)^9\cdot9^4}{6^9\cdot2^{10}+\left(-12\right)^{10}}\)
\(A=\frac{2^{19}.\left(2^3\right)^3+15.\left(2^2\right)^9.\left(3^2\right)^4}{2^9.3^9.2^{10}+\left(2^2.3\right)^{10}}=\frac{2^{19}.3^9+15.2^{18}.3^8}{2^{19}.3^9+2^{20}.3^{10}}=\frac{2^{18}.3^8.\left(2.3+15\right)}{2^{19}.3^9.\left(1+2.3\right)}\)
\(=\frac{2^{18}.3^8.21}{2^{19}.3^9.7}=\frac{21}{2.3.7}=\frac{1}{2}\)
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sao lại ko có dấu âm vậy bn ??????????????
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Rút gọn:
a) \(\dfrac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+2^{10}}\)
b) \(\dfrac{\left(-\dfrac{1}{2}\right)^3-\left(\dfrac{3}{4}\right)^3\cdot\left(-2\right)^2}{2\cdot\left(-1\right)+\left(\dfrac{3}{4}\right)^2-\left(\dfrac{3}{8}\right)}\)
a: \(=\dfrac{2^{19}\cdot3^9+3^9\cdot5\cdot2^{18}}{2^{19}\cdot3^9+2^{10}}\)
\(=\dfrac{3^9\cdot2^{18}\cdot\left(2+5\right)}{2^{10}\cdot\left(2^9\cdot3^9+1\right)}=\dfrac{3^9\cdot7\cdot2^8}{6^9+1}\)
b: \(=\dfrac{\dfrac{-1}{8}-\dfrac{27}{64}\cdot4}{-2+\dfrac{9}{16}-\dfrac{3}{8}}=\dfrac{-29}{16}:\dfrac{-29}{16}=1\)
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tính giá trị :
A=\(\frac{2^{19}\cdot27^3-15\cdot\left(-4\right)^9\cdot9^4}{^{6^9\cdot2^{10}+\left(-12\right)}^{^{10}}}\)
B= \(\left(\frac{1}{2^2}-1\right)\cdot\left(\frac{1}{3^2}-1\right)...\left(\frac{1}{98^2}-1\right)\cdot\left(\frac{1}{99^2}-1\right)\)
Tính \(A=\left(\frac{1}{4\cdot9}+\frac{1}{9\cdot14}+\frac{1}{14\cdot19}+...+\frac{1}{44\cdot49}\right)\cdot\frac{1-3-5-7-...-49}{89}\)
\(B=\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6}-\frac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\)
bài này không khó. Nhưng đánh máy để giải cho bạn thì thực sự khó
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Tinh
A=\(\frac{15\cdot3^{11}+4\cdot27^1}{9^7}\)
B=\(\frac{5\cdot2^{13}+4^{11}-1}{\left(3\cdot2^{17}\right)^2}\)
C=\(\frac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\)
\(A=\frac{15.3^{11}+4.27^1}{9^7}\)
\(\Rightarrow A=\frac{3.5.3^{11}+4.3^{3^1}}{\left(3^2\right)^7}\)
\(\Rightarrow A=\frac{3^{12}.5+4.3^3}{3^{14}}\)
\(\Rightarrow A=\frac{3^3.\left(5.3^8+4.3^3\right)}{3^{14}}\)
\(\Rightarrow A=\frac{32805+4}{177147}\)
\(\Rightarrow A=\frac{32809}{177147}\)
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Rút gọn :
\(\frac{2^9\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^0}\) \(\frac{\left(\frac{-1}{2}\right)^3-\left(\frac{3}{4}\right)^3\cdot\left(-2\right)^3}{2\cdot\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
Bài 2
a) \(\dfrac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\)
\(\dfrac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}=\dfrac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9+3^{10}.2^{20}}\)
\(=\dfrac{2^{19}.3^9+3^9.5.2^{18}}{2^9.3^9+3^{10}.2^{20}}=\dfrac{3^9.2^{18}.\left(2+5\right)}{2^9.3^9.\left(1+6\right)}\)
\(=\dfrac{3^9.2^{18}}{2^9.3^9}=2^9=512\)
~ Học tốt ~
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A=\(\frac{15\cdot3^{11}+4.27^4}{9^7}\)
B=\(\frac{2^{19}\cdot2^{73}+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\)
C=\(\frac{5\cdot12^3\cdot4^{11}-16^8}{\left(3\cdot2^{17}\right)^2}\)
D=\(\frac{4^7\cdot2^8}{3\cdot2^{15}\cdot16^2-5\cdot2^2\cdot\left(2^{10}\right)^2}\)