Bạn Nguyễn Đoan Hạnh cho mình bổ sung nhé 

Ư(9)={+-1;+-3;+-9}

Nếu x+1=-1 => x=-2

Nếu x+1=-3 => x = -4

Nếu X+1=-9 => x = -10

x+10 la boi cua x+1 

suy ra (x+1)+9 la boi cua x+1

suy ra 9 la boi cua x+1

U(9)={1;3;9}

Neu x+1=1 thi x=0

Neu x+1=3 thi x=2

Neu x+1=9 thi x=8

Vay x thuoc {0;2;8}

Ta có X x 2/5 + X x17/10=1113/10

         X x ( 2/5 + 17/10) = 1113/10

         X x 21/10 = 1113/10

               X = 1113/10 : 21/10

               X = 53

Ta có X x 2/5 + X x17/10=1113/10

         X x ( 2/5 + 17/10) = 1113/10

         X x 21/10 = 1113/10

               X = 1113/10 : 21/10

               X = 53

D nha

D

d nha

\(x:x^{10}=x\)

\(\Rightarrow x^{10}=x:x=1\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)

Nhầm đề nha.

\(x^{10}=x\)

\(\Rightarrow x=\left\{-1;0;1\right\}\)

tc \(x^{10}\ge0\)

mà \(x^{10}=x\)

=> x=0;x=1

12va 1

12 và 1

12 và 1

=>

\(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}-\frac{x+2}{12^{12}}-\frac{x+2}{13^{13}}=0\)

=>\(\left(x+2\right).\left(\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}=0\right)\)

vì \(\frac{1}{10^{10}}>\frac{1}{11^{11}}>\frac{1}{12^{12}}>\frac{1}{13^{13}}=>\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\ne0\)

=>x+2=0

=>x=-2

tick nhé

\(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}=\frac{x+2}{12^{12}}+\frac{x+2}{13^{13}}\)

\(=>\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}-\frac{x+2}{12^{12}}-\frac{x+2}{13^{13}}=0\)

\(=>\left(x+2\right).\left(\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\right)=0\)

Vì \(\frac{1}{10^{10}}>\frac{1}{11^{11}}>\frac{1}{12^{12}}>\frac{1}{13^{13}}\)

Nên \(\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\)khác 0

Suy ra:  x+2=0

             x   =0 - 2

             x = -2

                              TICK NHA

\(x\) \(\times\) 5,2 - \(x\) = 4,2 \(\times\) 10

\(x\) \(\times\) 5,2 - \(x\) \(\times\) 1 = 42

\(x\) \(\times\) ( 5,2 - 1) =  42

\(x\) \(\times\) 4,2 = 42

\(x\) = 42 : 4,2

\(x\) = 10