\(x^{10}=x\)
\(\Rightarrow x^{10}-x=0\)
\(\Rightarrow x\left(x^9-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x^9-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
Vậy x \(\in\left\{0;1\right\}\)
\(x^{10}=x\)
\(\Rightarrow x^{10}-x=0\)
\(\Rightarrow x\left(x^9-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x^9-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
Vậy x \(\in\left\{0;1\right\}\)
Tim x € N biet :
a / x + 16 = 25
b / 156 - 2x = 82
c / 150 -150 : ( 18 - x ) = 125
d / 62 : x = 23 - 4
e / x + 3x + 5x + ................. +99x = 75 × 102
tim min
A=/X5-32/-17
B=/X-9/-X+15
C=/X-5/+X-3
tim max
D=17-/ /X/-2 /
Tim x biet :
a)X+X:0,5+X:0,25+X:0,125=15
tim x : gia tri tuyet doi cua x = -3 + 5
tim x,biet:a,x2+3x+1⋮ x-1
b,18x+⋮7
c,4x-5⋮13
tim x y ϵ N
(X+1)+(2y-1)
Tim x : a/ gia tri tuyet doi cua x < 5 b/ 2 be hon hoac bang gia tri tuyet doi cua x < 7
x/2-x/3=25%. Tim x. please help me. tớ cần ngay trong hôm nay và sáng ngày mai
tim x,y 56x3y chia hetcho 90