?

412 - 15 x (27 - X) = 97

                         X   = 27 - (412 - 97) : 15

                         X   = 27 - 315 : 15

                         X   = 27 - 21

                         X   = 6.

x= 6

412-15.[27-x]=97

15.[27-x]=412-97

15.[27-x]=315

27-x=315:15

27-x=21

x=27-21

x=6

Bài 1:

a) Ta có: \(82-7\left(3x-4\right)=47\)

\(\Leftrightarrow82-21x+28-47=0\)

\(\Leftrightarrow-21x+63=0\)

\(\Leftrightarrow-21x=-63\)

hay x=3(nhận)

Vậy: x=3

b) Ta có: \(97+4\left(5x-7\right)=129\)

\(\Leftrightarrow97+20x-28-129=0\)

\(\Leftrightarrow20x-60=0\)

\(\Leftrightarrow20x=60\)

hay x=3(nhận)

Vậy: x=3

c) Ta có: \(\left(7x-13\right)\cdot27-12=15\)

\(\Leftrightarrow189x-351-12-15=0\)

\(\Leftrightarrow189x-378=0\)

\(\Leftrightarrow189x=378\)

hay x=2(nhận)

Vậy: x=2

d) Ta có: \(\left(2x+3\right)\cdot13+23=140\)

\(\Leftrightarrow26x+39+23-140=0\)

\(\Leftrightarrow26x-78=0\)

\(\Leftrightarrow26x=78\)

hay x=3(nhận)

Vậy: x=3

đ) Ta có: \(52x+8x-5x=70\)

\(\Leftrightarrow55x=70\)

\(\Leftrightarrow x=\frac{70}{55}\)(loại)

Vậy: x∈∅

e) Ta có: \(19x-3x-x=60\)

\(\Leftrightarrow15x=60\)

hay x=4(nhận)

Vậy: x=4

g) Ta có: \(7\left(3x+1\right)-5\left(3x+1\right)=74\)

\(\Leftrightarrow2\left(3x+1\right)=74\)

\(\Leftrightarrow3x+1=37\)

\(\Leftrightarrow3x=36\)

hay x=12(nhận)

Vậy: x=12

h) Ta có: \(5\left(3x-1\right)+7\left(3x-1\right)=96\)

\(\Leftrightarrow12\left(3x-1\right)=96\)

\(\Leftrightarrow3x-1=8\)

\(\Leftrightarrow3x=9\)

hay x=3(nhận)

Vậy: x=3

A/ 15+(3-x)=-10

      15+3-x=-10

       18-x=-10

         -x=-10-18=-8

Suy ra x= 8 

a, 15 + (3-x) = -10

            3-x  = -10 - 15

            3-x  = -25

               x  = 3 - (-25)

               x  = -28

b, 11 - ( 53 + x ) = 97

          53 + x     = 11 - 97

          53 + x     = -86

                 x      = -86 - 53

                 x      =   -139

c, 5x - (-25) = 35

    5x          =35 + ( -25)

    5x          =   10

     x           = 10 : 5

     x           = 2

a,

15 + ( 3 - x ) = - 10

          3 - x   = - 10 - 15

          3 - x = - 25

               x = 3 - ( - 25 )

               x = 28

b, 11 - ( 53 + x ) = 97

            53 + x   = 11 - 97

            53 + x   = - 86

                    x   = - 86 - 53

                    x   = - 139

c, 5x - ( - 25 ) = 35

    5x             = 35 + ( - 25 )

    5x             = 10

      x             = 10 : 5

      x             = 2

x - ( 81 + 5x ) = 19

=> x - 81 - 5x = 19

=> ( x - 5x ) - 81 = 19

=> -4x = 19 + 81

=> -4x = 100

=> x = 100 : ( -4 )

=> x = -25

2x - ( 8 + 3x ) = 92

=> 2x - 8 - 3x = 92

=> ( 2x - 3x ) = 8 + 92

=> -x = 100

=> x = -100

a) (x – 45).27 = 0

=>   x -  45  =  0

=>  x  =  45

 b) 23.(42- x) = 23 

=>  42- x  =  1

=>   x  =  41

c. 3x – 5=7

=>  3x  =  12

=>  x  =  4

e. 15 – 5x=10

=>  5x  =  5

=>  x  =  1

a: =>x/27+1=-2/3

=>x/27=-5/3

=>x=-45

b: \(\Leftrightarrow x-4=\dfrac{2}{5}:\dfrac{20}{21}=\dfrac{2}{5}\cdot\dfrac{21}{20}=\dfrac{42}{100}=\dfrac{21}{50}\)

=>x=221/50

c: \(\Leftrightarrow x+\dfrac{2}{3}=\dfrac{4}{60}=\dfrac{1}{15}\)

=>x=1/15-2/3=1/15-10/15=-9/15=-3/5

d: \(\Leftrightarrow x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{15}{14}\cdot\dfrac{21}{20}\)

=>\(x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{3}{2}\cdot\dfrac{3}{4}=\dfrac{1}{5}-\dfrac{9}{8}=\dfrac{-37}{40}\)

=>x=-37/24

e: =>-3/7x=84/45

=>x=-196/45

f: =>11/10x=-2/3

=>x=-20/33

3) \(-12+2x-9+x=0\\ -21+3x=0\\ 3x=21\\ x=7\)

4)
\(11+\left(15-x\right)=1\)
\(15-x=1-11\)
\(15-x=-10\)
\(x=15-\left(-10\right)\)
\(x=25\)

5) 
\(4-\left(27-3\right)=x-\left(13-4\right)\)
\(4-24=x-9\)
\(x-9=-20\)
\(x=-20+9\)
\(x=-11\)
 

\(3.-12+\left(2x-9\right)+x=0.\)

\(\Leftrightarrow-12+2x-9+x=0.\Leftrightarrow3x=21.\Leftrightarrow x=7.\)

Vậy \(x=7.\)

\(4.11+\left(15-x\right)=1.\Leftrightarrow11+15-x=1.\Leftrightarrow26-x=1.\Leftrightarrow x=25.\)

Vậy \(x=25.\)

\(5.4-\left(27-3\right)=x-\left(13-4\right).\Leftrightarrow4-24=x-9.\Leftrightarrow-20=x-9.\Leftrightarrow x=-11.\)

Vậy \(x=-11.\)

\(6.8-\left(x-10\right)=23-\left(-4+12\right).\Leftrightarrow8-x+10=23-8.\Leftrightarrow18-x=15.\Leftrightarrow x=3.\)

Vậy \(x=3.\)

\(7.105-5\left(10-5x\right)=-20.\Leftrightarrow105-50+25x=-20.\Leftrightarrow25x=-75.\Leftrightarrow x=-3.\)

Vậy \(x=-3.\)

\(8.\left(x-1\right)\left(8-2x\right)\left(3x+123\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0.\\8-2x=0.\\3x+123=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1.\\x=4.\\x=-41.\end{matrix}\right.\)

Vậy \(x\in\left\{1;4;-41\right\}.\)

\(9.\left(x^2-25\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left(x-5\right)\left(x+5\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=0.\\x+5=0.\\x+10=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5.\\x=-5.\\x=-10.\end{matrix}\right.\)

Vậy \(x\in\left\{5;-5;-10\right\}.\)

\(10.x\left(x^2+5\right)=0.\Leftrightarrow x=0.\)

Mình không viết lại đề nhé!

a) 27 - x + 15 + x = x + 2

-x + x - x = 2 - 15 - 27

-x = -40

x = 40

b) 8x - 75 = 5x +21

8x - 5x = 21 + 75

3x = 96

x = 32

c) 15 - |2x - 1| = |-8|

15 - 2x + 1 = 8

-2x = 8 -1 -15

-2x = -8

x = 4 

d) 9x + 25 = -(2x - 58)

9x + 25 = -2x + 58

9x +2x = 58 - 25

7x = 33

x = 33/7