Tìm x:

a, 96 - 3 . ( x + 1 ) = 42

           3 . ( x + 1 ) = 96 - 42

           3 . ( x + 1 ) = 54

             x + 1 = 54 : 3

             x + 1 = 18

                   x = 18 -1 

                   x = 17

 b, 12x - 33 = 32.33

      12x - 33 =9 . 27

      12x - 33 = 243

             12x = 243 + 33

             12x = 276

               x=276:12

               x=23

a, 96 - 3 . ( x + 1 ) = 42

3 . ( x + 1 ) = 96 - 42

3 . ( x + 1 ) = 54

x + 1 = 54 : 3

x + 1 = 18

x = 18 - 1

x = 17

b, 12x - 33 = 3² . 3³

12x - 33 = 9 . 27

12x - 33 = 243

12x = 243 + 33

12x = 276

x = 276 : 12

x = 23

a)96-3.(x+1)=42

3.(x+1) = 96 - 42

3 . (x+1) = 54

x + 1 = 54 : 3

x + 1 = 18

x = 18-1

x = 17

a: Ta có: \(7x+25=144\)

\(\Leftrightarrow7x=119\)

hay x=17

b: Ta có: \(33-12x=9\)

\(\Leftrightarrow12x=24\)

hay x=2

c: Ta có: \(128-3\left(x+4\right)=23\)

\(\Leftrightarrow3\left(x+4\right)=105\)

\(\Leftrightarrow x+4=35\)

hay x=31

d: Ta có: \(71+\left(726-3x\right)\cdot5=2246\)

\(\Leftrightarrow5\left(726-3x\right)=2175\)

\(\Leftrightarrow726-3x=435\)

\(\Leftrightarrow3x=291\)

hay x=97

e: Ta có: \(720:\left[41-\left(2x+5\right)\right]=40\)

\(\Leftrightarrow41-\left(2x+5\right)=18\)

\(\Leftrightarrow2x+5=23\)

\(\Leftrightarrow2x=18\)

hay x=9

Bn cần bài nào vậy

f: Ta có: \(10-4x+120:8=16+1\)

\(\Leftrightarrow4x=17-25=-8\)

hay x=-2

g: Ta có: \(x+9x+7x+5x=2244\)

\(\Leftrightarrow22x=2244\)

hay x=102

h: Ta có: \(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)

\(\Leftrightarrow100x+5050=5750\)

\(\Leftrightarrow100x=700\)

hay x=7

96 - 3( x + 1 ) = 42

      3( x + 1 )  = 96 - 42

      3( x + 1 )  = 54

          x + 1    = 54 : 3 = 18

                 x   = 18 - 1 

                 x   = 17 

cau 1 

96-3(x+1)=42

=> 3(x-1)=54

=> x-1=18

=> x=19

cau 2 

12x-33=3².3³

=> 12x-33=243

=> 12x=276

=> x=23

12x - 33 = 3² . 3³

12x - 33 = 3⁵ = 243

      12x  = 243 + 33

       12x = 276

          x  = 276 : 12

          x  = 23

Bài 2: 

a: Ta có: \(2^{x+1}\cdot3^y=12^x\)

\(\Leftrightarrow2^{x+1}\cdot3^y=2^{2x}\cdot3^x\)

\(\Leftrightarrow\left\{{}\begin{matrix}x+1=2x\\x=y\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=1\end{matrix}\right.\)

a ) 5(x + 35 ) = 515                               

       x + 35 = 515 : 5

       x + 35 = 103

              x = 103 - 35

              x = 68

a) x+35=515:5

   x+35=103

   x= 103-35=68

b) 96-3(x+1)=42

3(x+1)=96-42=54

x+1=54:3=18

x=18-1=17

c)  12x-33=3².3³

  12x - 33 = 9 . 27

  12x - 33=243

12x = 243 +33 

12x = 276

x= 276:12

x=23

a)  5(x + 35) = 515
=>    x + 35 = 103
=>    x         = 68

b)  96 - 3(x + 1) = 42
=>       3(x + 1) = 54
=>          x + 1  = 18
=>          x        = 17

c)  12x - 33 = 3² . 3³
=> 3(4x - 11) = 3⁵
=>    4x - 11  = 3⁴
=>    4x - 11  = 81
=>    4x        = 92
=>      x        = 23

a) 5 ( x + 35 ) = 515

         x + 35 = 103

         x         = 68

b) 96 - 3(x+1) = 49 

           3(x+1) = 47

              x + 1 = 47/3

              x = 44/3

c) 12x - 33 = 3^2 * 3^3

     12x - 33 = 243

      12x = 276

          x = 23

5 ( x + 35 ) = 515

     x + 35  = 515 : 5

      x + 35 = 103

      x        = 103 - 35

      x         = 68

96 - 3( x + 1 ) = 49

       3( x + 1 ) = 96 - 49

        3( x + 1 ) = 47

            x + 1   = 47/3

            x         = 47/3 - 1 

             x        = 44/3

12x - 33 = 3² . 3³

12x - 33 = 3⁵

12x - 33 = 243

12x        = 243 + 33

12x        = 276

    x       = 276 : 12

     x       = 23

\(a.5\cdot\left(x+35\right)=515\)         

\(x+35=515:5\)

\(x+35=103\)

\(x=103-35\)      

x=68

\(b.96-3\left(x+1\right)=49\)  

\(3\left(x+1\right)=96-49\)         

\(3\left(x+1\right)=47\)

\(x+1=\frac{47}{3}\) 

\(x=\frac{47}{3}-1\)

\(x=\frac{44}{3}\)

\(c.12x-33=3^2\cdot3^3\)

\(12x-33=243\)

\(12x=243+33\)

\(12x=276\)

\(x=276:12\)

\(x=23\)

(2-x)^3+(2+x)^3-12x(x+1)=0

=>\(8-12x+6x^2-x^3+8+12x+6x^2+x^3-12x\left(x+1\right)=0\)

=>\(12x^2+16-12x^2-12x=0\)

=>16-12x=0

=>4-3x=0

=>x=4/3