Câu 2: 

a: =>(x-1)(x+1)=0

=>x=1 hoặc x=-1

b: \(\Leftrightarrow\left(x-3\right)=0\)

=>x=3

c: =>x(x^2-5)=0

hay \(x\in\left\{0;\sqrt{5};-\sqrt{5}\right\}\)

d: \(\Leftrightarrow\left(3x-2-x-2\right)\left(3x-2+x+2\right)=0\)

=>(2x-4)(4x)=0

=>x=0 hoặc x=2

e: \(\Leftrightarrow x^2-x-4x-12=0\)

=>x^2-5x-12=0

=>\(x\in\left\{\dfrac{5+\sqrt{73}}{2};\dfrac{5-\sqrt{73}}{2}\right\}\)

f: \(\Leftrightarrow\left(x-2\right)\left(2-x+2\right)=0\)

=>(x-2)(4-x)=0

=>x=2 hoặc x=4

a) 500

b) 2303                

c) 537                  

d) 35000

e) 90000

f) 380

\(a,\left(4+32+6\right)+\left(10-32-2\right)\\ =\left(10+32\right)+\left(10-32-2\right)\\ =10+32+10-32-2\\ =20-2\\ =18\\ b,300:4+300:6-25\\ =300:\left(4+6\right)-25\\ =300:10-25\\ =30-25\\ =5\\ c,17.\left[29-\left(-111\right)\right]+29.\left(-17\right)\\ =17.\left(29+111\right)+29.\left(-1\right).17\\ =17.\left(29+111-29\right)\\ =17.111=1887\\ d,19.43+\left(-20\right).43-\left(-40\right)\\ =19.43+\left(-20\right).43+40\\ =43.\left(19-20\right)+40\\ =-43+40\\ =-3\)

a.$17\cdot (29-(-111\left)\right]+29\cdot (-17)$ 

$=17\cdot (29+111)-29\cdot 17$

$=17\cdot (29+111-29)$

$=17\cdot (29-29+111)$

$=17\cdot 111$

$=2997$

b.$19\cdot 43+(-20)\cdot 43-(-40)$

$=19\cdot 43-20\cdot 43+40$

$=43(19-20)+40$

$=43\cdot (-1)+40$

$=-43+40$

$=-3$

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kết quả là 3518

\(-582\)

a) (-12) + 25 + 75 + 12 = (-12) + 12 + 25 + 75 = 0 +100 = 100.

b) 60 +12 + (-17) + (-43) = 60 + [(-47) + (-43)] +12.

c) (-2) + (-87) + (-18) + 87 = [(-2) + (-18)] + [(-87) + 87].

d) (-1)+(-2) + 36 + (-17) = 36+[(-1) + (-2) + (-17)].

a, (-12) + 25 + 75 + 12

= [ (-12) + 12] + (25 + 75)

= 0 + 100

= 100

b, 60 + 12 + (-17) + (-43)

= -(17 + 43) + 60 + 12

= - 60 + 60  + 12

= 0 + 12

= 12