tinh rut gon
\(\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{2^2\cdot3^{28}}\)
Những câu hỏi liên quan
\(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
\(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
=\(\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}\)
=\(\frac{11\cdot3^{29}-3^{29}\cdot3}{2^2\cdot3^{28}}\)
=\(\frac{3^{29}\cdot\left(11-3\right)}{2^2\cdot3^{28}}\)
=\(\frac{3^{29}\cdot2^3}{2^2\cdot3^{28}}\)
=\(\frac{3\cdot2}{1}\)
=6
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\(A=\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
\(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)
\(A=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)
\(A=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}\)
\(A=\frac{3^{29}.8}{4.3^{28}}=3.2=6\)
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\(\Rightarrow A=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)
\(\Rightarrow A=\frac{11.3^{29}-3^{29}.3}{2^2.3^{28}}\)
\(\Rightarrow A=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(\Rightarrow A=\frac{3^{29}.2^3}{2^2.3^{28}}\)
\(\Rightarrow A=3.2\)
=> A=6
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A = 11 . 329 - ( 32)15 /22 .328
A= 329. ( 11 - 3 )/ 22 . 328
A = 329 . 23 / 22 . 328
A = 3 .2
A = 6
Mong cac ban ung ho minh nha
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Xem thêm câu trả lời
A= \(A=\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
tách mẫu ra: (2.314)2 = 22.(314)2 nha
duyệt đi
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A=(11.3^22.3^7-9^15)/ ( 2.3^14)
=(11.3^29-3^30) /(2.3^14)
=[3^29(11-3) / (2.3^14]
=(3^29.8) / (2.3^14)
=(3^29:3^14) /(8:2)
=3^15/4
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Tính giá trị biểu thức:
\(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(=\frac{3^{29}.2^3}{2^2.3^{28}}\)
\(=3.2=6\)
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bài 1
A =\(\frac{3^7\cdot17-3^9}{2^3\cdot3^5}\)
B=\(\frac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^9}\)
C =\(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
\(A=\frac{3^7\cdot17-3^9}{2^3\cdot3^5}=\frac{3^7\left(17-3^2\right)}{2^3\cdot3^5}=\frac{3^7\cdot2^3}{2^3\cdot3^5}=9\)
\(B=\frac{3^2\cdot4^2\cdot2^{32}}{11\cdot2^{13}\cdot4^{11}-16^9}=\frac{3^2\cdot2^{36}}{2^{35}\cdot11-2^{36}}=\frac{3^2\cdot2^{36}}{2^{35}\left(11-2\right)}=\frac{3^2\cdot2^{36}}{2^{35}\cdot3^2}=2\)
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\(\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2\cdot3^{28}}=\frac{3^{29}\cdot8}{2^2\cdot3^{28}}=6\)
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\(C=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-3^{30}}{4.3^{28}}=\frac{3^{29}\left(11-3\right)}{4.3^{28}}=\frac{3.8}{4}=6\)
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1:rút gọn
\(\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
2: tìm x
\(\dfrac{3\cdot\left(x-2\right)}{4}-\dfrac{2\cdot\left(1+2x\right)}{3}=1\dfrac{1}{4}-5\cdot\dfrac{\left(1+3x\right)}{6}-\dfrac{x-2}{12}\)
\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(=\dfrac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)
\(=\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(=\dfrac{3^{29}\left(11-3\right)}{2^2.3^{28}}\)
\(=\dfrac{3^{29}.2^3}{2^2.3^{28}}\)
\(=\dfrac{3.2}{1.1}=6\)
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17 tháng 8 2021 lúc 17:57
cái bài n á là mik đã hỏi và có bn trl cho mk rồi nhma mk k hiểu rõ lắm các bn gthich hộ mk nhé
= \(\dfrac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
Xong rồi các bn làm bước tiếp theo và gth sao ra zầy hộ mk nha cảm ơn nhiều lắm ạ
\(\dfrac{4^6\cdot9^5+6^9\cdot120}{-8^4\cdot3^{12}-6^{11}}\)
\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
\(=\dfrac{2^{12}\cdot3^{10}\cdot\left(1+5\right)}{2^{11}\cdot3^{11}\left(2\cdot3-1\right)}\)
\(=\dfrac{2\cdot6}{3\cdot5}=\dfrac{4}{5}\)
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N=\(\frac{5\cdot\left(2^2\cdot3^2\right)\cdot\left(2^2\right)^6-2\cdot\left(2^2\cdot3\right)^{14}\cdot3^6}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot2^{18}}\)
Tinh N
Tính:
a, \(\frac{7}{12}+\frac{5}{6}+\frac{1}{4}-\frac{3}{7}-\frac{5}{12}_{ }\)
b, \(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
c, \(\frac{3}{2^2}\cdot\frac{8}{3^2}\cdot\frac{15}{4^2}\cdot...\cdot\frac{899}{30^2}\)
Bài giải
a, \(\frac{7}{12}+\frac{5}{6}+\frac{1}{4}-\frac{3}{7}-\frac{5}{12}\)
\(=\left(\frac{7}{12}-\frac{5}{12}+\frac{5}{6}+\frac{1}{4}\right)-\frac{3}{7}=\left(\frac{7}{12}-\frac{5}{12}+\frac{10}{12}+\frac{3}{12}\right)-\frac{3}{7}=\frac{5}{4}-\frac{3}{7}=\frac{23}{28}\)
b, \(\frac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\frac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}=\frac{3^{29}\left(11-3\right)}{3^{28}\cdot4}=\frac{3\cdot8}{4}=6\)