Tính
a) ( 325 - 47 ) + ( 175 - 53 )
b) ( 756 - 217 ) - ( 183 - 53 )
c) ( -5 ) . 6 . ( -2 ) . 7
d) 24 . 36 - ( -24 ) . 64
e) 24 . 36 - ( -24 ) . 64
1/ Tính
a/ 7-20+313 b/ (-163)+177-(377-263)
c/ (325-47)+(175-53) d/ (217-756)-(41-183)
a/ \(7-20+313\)
\(=\left(-13\right)+313\)
\(=300\)
b/ \(\left(-163\right)+177-\left(377-263\right)\)
\(=\left(-163\right)+177-114\)
\(=14-114\)
\(=-100\)
c/\(\left(325-47\right)+\left(175-53\right)\)
\(=278+122\)
\(=400\)
d/\(\left(217-756\right)-\left(41-183\right)\)
\(=\left(-539\right)-\left(-142\right)\)
\(=-397\)
\(=-100\)
a/ 7 - 20 + 313
= - 13 + 313
= 300
b/ (-163) + 177 - (377 - 263)
= (-163) + 177 - 377 + 263
= [(-163) + 263] + (177 - 377)
= 100 + (-200)
= -100
c/ (325 - 47) + (175 - 53)
= 325 - 47 + 175 - 53
= (325 + 175) - (47 + 53)
= 500 - 100
= 400
d/ (217 - 756) - (41 - 183)
= 217 - 756 - 41 + 183
= (217 + 183) - ( 756 + 41)
= 400 - 797
= -397
a,\(7-20+313=300\)
b,\(\left(-163\right)+177-\left(377-263\right)\)
\(=14-114=-100\)
c,\(\left(325-47\right)+\left(175-53\right)\)
\(=325-47+175-53\)
\(=500-100=400\)
d,\(\left(217-756\right)-\left(41-183\right)\)
\(=217-756-41+183\)
\(=-397\)
tính nhanh;
1,(325-47)+(175-53)
2,(756-217)-(183-44)
1,
(325-47)+(175-53)
=325-47+175-53
=(325+175)-(47+53)
=500-100
=400
2,
(756-217)-(183-44)
=756-217-183+44
=(756+44)-(217+183)
=800-400
=400
a) 2×24×25+3×41×16+6×2×8×17
b)15×360+15×2×27+1500
c)47×63+53×21+47×37+53
d)2×169×12-3×68×8-24
e)2×56×24-3×36×16+4×12×95-6×3×8×5
f)(36×15×169)÷(5×18×13)
h)(112+2×28-5×28)÷28
i)1448-(448+500)
So sánh:
a) ( a - b ) + ( c - d ) với ( a + c ) - ( b + d )
b) ( a - b ) - ( c - d ) với ( a + d ) - ( b + c )
Áp dụng tính:
1/ ( 325 - 47 ) + ( 175 - 53 )
2/ ( 756 - 217 ) - ( 183 - 44 )
Hướng dẫn : Áp dụng quy tắc bỏ dấu ngoặc.
Tính nhanh
a (-4) x (-3) x 25 x (-8)
b 7x(-25).(-3)2.(-4)
c [93-(20-7)] : 16
d 53-(-51)+(-53)+49
e 168 - (49)+(-68)+4
f 53 -(-7)+(-53)-49
g 25.(-124)+124.25
h (-11).36+64.(-11)
i 125.(-24) +24.125
k 125.(-23)+23.225
l (-11).36+64.(-11)
Giúp mk với!
Bài 1. Tính hợp lý
1) (–12) +6.(–3)
2) (36 -2020) + (2019 -136) – 27
3) (144 – 97) – (244 – 197)
4) (–24).13 – 24.( –3)
5) 54+55+56+57+58-(64+65+66+67+68)
6) 24(16 – 5) – 16(24 – 5)
7) 47.(23 + 50) – 23.(47 + 50)
8) (-31). 47 + (-31). 52 + (-31)
Bài 2: Tìm số nguyên x, biết:
1)-17-(2x-5)=-6
2) 10-2(4-3x)=-4
3)-12+3(-x+7)=-18
4)-45:[5.(-3-2x)]=3
5) x.(x+3)=0
6) (x-2).(x+4)=0
7) x.(x+1).(x-3)=0
Bài 1:
1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)
\(=-12-18\)
=-30
2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)
\(=36-2020+2019-136-27\)
\(=1-100-27\)
\(=-126\)
3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)
\(=144-97-244+197\)
\(=-100+100=0\)
4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)
\(=-24\cdot13+24\cdot3\)
\(=24\cdot\left(-13+3\right)\)
\(=24\cdot\left(-10\right)=-240\)
5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)
\(=54+55+56+57+58-64-65-66-67-68\)
\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)
\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)
=-50
6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)
\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)
\(=-24\cdot5+16\cdot5\)
\(=5\cdot\left(-24+16\right)\)
\(=-5\cdot8=-40\)
7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)
\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)
\(=47\cdot50-23\cdot50\)
\(=50\cdot\left(47-23\right)\)
\(=50\cdot24=1200\)
8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)
\(=-31\cdot\left(47+52+1\right)\)
\(=-31\cdot100=-3100\)
Bài 2:
1) Ta có: \(-17-\left(2x-5\right)=-6\)
\(\Leftrightarrow-17-2x+5+6=0\)
\(\Leftrightarrow-2x-6=0\)
\(\Leftrightarrow-2x=6\)
hay x=-3
Vậy: x=-3
2) Ta có: \(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow10-8+6x+4=0\)
\(\Leftrightarrow6x+6=0\)
\(\Leftrightarrow6x=-6\)
hay x=-1
Vậy: x=-1
3) Ta có: \(-12+3\left(-x+7\right)=-18\)
\(\Leftrightarrow-12-3x+21+18=0\)
\(\Leftrightarrow-3x+27=0\)
\(\Leftrightarrow-3x=-27\)
hay x=9
Vậy: x=9
4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)
\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)
\(\Leftrightarrow-2x-3=-3\)
\(\Leftrightarrow-2x=0\)
hay x=0
Vậy: x=0
5) Ta có: x(x+3)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-3\right\}\)
6) Ta có: (x-2)(x+4)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-4\right\}\)
7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-1;3\right\}\)
Bài 1:
1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)
=−12−18=−12−18
=-30
2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27
=36−2020+2019−136−27=36−2020+2019−136−27
=1−100−27=1−100−27
=−126
Tớ chcs cậu học thật giỏi nha !
Tính nhanh
24.(16-5) +16.(24-5)
b) 31.(-18) +31.(-81) - 31
c) 13.(23+22) -3 . (17+ 28)
d) 11/53+(32/47+-10/53)+-64/94+1/-53+1/3
e) (-1+45/115+47/51)+(-9/23+-1/3)
f) -13/15+(-4/5+7/18)+-5/12+1/16
Ai giúp mk vs ạ cảm ơn nhiều ạ ( mk cần nộp gấp ạ)
1:tính nhanh
a) (325-47)+(175-53)
b) (756-217)-(183-44)
2: chứng minh:
a) (a-b)+(c-d) = (a+c) - (b+d)
b) (a-b)-(c-d) = (a+d) - (b+c)
c) - (-a+c-d)-(c-a+d)=0
d) -(a+b-c+d)+(a-b-c-d) =0
(325 - 47) + (175 - 53)
=325 - 47 + 175 -53
=(325 + 175 ) - (47 + 53)
= 500 - 100
= 400
b)(756-217)-(183-44)
=756-217-183+44
=(756+44)-(217+183)
=800-400
=400
a)(325-47)+(175-43)
=325-47+175-53
=(325+175)-(47+53)
=500-100
=400
Tìm x: a,|2x+1|=7 b, 3.|x+1|+1=28 c, (x-1)(x-2)=0 d,(x+4)(x-5)=0 Bài 2:CMR a,(a-b)+(c-d)=(a+c)-(b+d) áp dụng tính (325-47)+(175-53) b,(756-217)-(143-44) giúp mk với mk đang cần gấp