\(\cdot\dfrac{10}{x}< \dfrac{x}{11}\Rightarrow x^2< 110\Rightarrow-\sqrt{110}< x< \sqrt{110}\\ \cdot\dfrac{x}{11}< \dfrac{12}{x}\Rightarrow x^2< 132\Rightarrow-\sqrt{132}< x< \sqrt{132}\)\(\Rightarrow-\sqrt{132}< x< \sqrt{132}\)

\(\dfrac{10}{x}< \dfrac{x}{11}< \dfrac{12}{x}\)

<=> \(\dfrac{110}{11x}< \dfrac{x^2}{11x}< \dfrac{132}{11x}\)

<=> 110 < x² < 132
<=> x² = 121
<=> x = 11
@Khánh Linh

\(\dfrac{x+8}{12}+\dfrac{x+9}{11}+\dfrac{x+10}{10}+3=0\\ \Leftrightarrow\dfrac{x+8}{12}+1+\dfrac{x+9}{11}+1+\dfrac{x+10}{10}+1=0\\ \Leftrightarrow\dfrac{x+20}{12}+\dfrac{x+20}{11}+\dfrac{x+20}{10}=0\\ \Leftrightarrow\left(x+20\right)\left(\dfrac{1}{12}+\dfrac{1}{11}+\dfrac{1}{10}\right)=0\\ \Leftrightarrow x+20=0\Leftrightarrow x=-20\\ KL:...\)

`<=>((x+8)/12+1)+((x+9)/11+1)+((x+10)/10+1)=0`

`<=>(x+20)/12+(x+20)/11+(x+20)/10=0`

`<=>(x+20)(1/12+1/11+1/10)=0`

Vì `1/12+1/11+1/10 ≠ 0`

`=>x+20=0`

`=>x=0-20`

`=>x=-20`

Bài 1 : 

\(=\dfrac{2}{11}+\dfrac{4}{11}-\dfrac{6}{11}-\dfrac{3}{8}-\dfrac{5}{8}=0-1=-1\)

Bài 2 : 

\(\Rightarrow3+x=8\Leftrightarrow x=5\)

Bài 3 : 

\(\Leftrightarrow x-\dfrac{5}{11}=\dfrac{5}{4}\Leftrightarrow x=\dfrac{35}{44}\)

Bài 4 : 

Trong 2 ngày An đọc được số quyên phần quyên sách 

\(\dfrac{1}{11}+\dfrac{8}{11}=\dfrac{9}{11}\)( quyển sách ) 

đs : 9/11 quyển sách 

\(\dfrac{1}{6}.x+\dfrac{1}{10}.x-\dfrac{4}{15}.x+1=0\)

=> \(\left(\dfrac{1}{6}+\dfrac{1}{10}-\dfrac{4}{15}\right).x+1\)= 0

=> \(0.x+1=0\)

=> 0 . x = 0 - 1

=> 0 . x = -1

=> x = 0 : -1

=> x = 0

~ Chúc bạn học giỏi ! ~

\(\dfrac{1}{6}x+\dfrac{1}{10}x-\dfrac{4}{15}x+1=0\)

\(\Leftrightarrow\left(\dfrac{1}{6}+\dfrac{1}{10}-\dfrac{4}{15}\right)x+1=0\)

\(\Leftrightarrow0x+1=0\)\(\)

Vì 0x luôn = 0 => 0x + 1 > 0

<=> x \(\in\varnothing\)

\(a,\dfrac{11}{12}x+\dfrac{3}{4}=-\dfrac{1}{6}\)

\(\Leftrightarrow\dfrac{11}{12}x=-\dfrac{1}{6}-\dfrac{3}{4}\)

\(\Leftrightarrow\dfrac{11}{12}x=-\dfrac{11}{12}\)

\(\Leftrightarrow x=-\dfrac{11}{12}:\dfrac{11}{12}\)

\(\Leftrightarrow x=-\dfrac{11}{12}.\dfrac{12}{11}\)

\(\Leftrightarrow x=-1\)

\(b,3-\left(\dfrac{1}{6}-x\right).\dfrac{2}{3}=\dfrac{2}{3}\)

\(\Leftrightarrow3-\dfrac{2}{3}.\left(\dfrac{1}{6}-x\right)=\dfrac{2}{3}\)

\(\Leftrightarrow3-\dfrac{1}{9}+\dfrac{2}{3}x=\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{2}{3}x=\dfrac{2}{3}-3+\dfrac{1}{9}\)

\(\Leftrightarrow\dfrac{2}{3}x=-\dfrac{20}{9}\)

\(\Leftrightarrow x=-\dfrac{20}{9}:\dfrac{2}{3}\)

\(\Leftrightarrow x=-\dfrac{10}{3}\)

a: =>x/10=-22/10

hay x=-22

b: =>-6/x=6/12

=>x=-12

\(a,\dfrac{x}{10}=\dfrac{-11}{5}\Rightarrow x.5=10.\left(-11\right)=-110\\ \Rightarrow-22\\ b,\dfrac{-6}{x}=\dfrac{30}{60}\Rightarrow-6.60=x.30=-120\\ \Rightarrow x=-4\)

\(\left(\dfrac{103}{8}-\dfrac{193}{18}\right):x-\dfrac{40}{33}:\dfrac{8}{11}=\dfrac{5}{3}\)

\(\dfrac{155}{72}:x-\dfrac{5}{3}=\dfrac{5}{3}\)

\(\dfrac{155}{72}:x=\dfrac{5}{3}+\dfrac{5}{3}=\dfrac{10}{3}\)

\(x=\dfrac{155}{72}:\dfrac{10}{3}=\dfrac{31}{48}\)

vaayj.....

5/3:x-5/3=5/3

5/3:x=5/3+5/3

5/3:x=10/3

x=5/3:10/3

x=1/2

\(\Leftrightarrow\left(\dfrac{x-9}{11}+1\right)+\left(\dfrac{x-10}{12}+1\right)+\left(\dfrac{x-11}{13}+1\right)=\left(\dfrac{x-12}{14}+1\right)+\left(\dfrac{x-28}{15}+2\right)\)

=>x+2=0

=>x=-2

1,

x+1/2+x+1/3+x+1/4-x+1/5-x+1/6=0

(x+1)(1/2+1/3+1/4-1/5-1/6)=0

vì 1/2+1/3+1/4-1/5-1/6 khác 0

suy ra x+1=0 suy ra x=-1