\(\dfrac{1}{3}-\left(1\dfrac{1}{2}-x\right)=0,3\\ \dfrac{1}{3}-\left(\dfrac{3}{2}-x\right)=\dfrac{3}{10}\\ \dfrac{3}{2}-x=\dfrac{1}{3}-\dfrac{3}{10}\\ \dfrac{3}{2}-x=\dfrac{1}{30}\\ x=\dfrac{3}{2}-\dfrac{1}{30}=\dfrac{44}{30}\)

Giải:

\(0,28-0,3:\left(50\%x-1\dfrac{1}{3}\right)=-1\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{7}{25}-\dfrac{3}{10}:\left(\dfrac{1}{2}x-\dfrac{4}{3}\right)=-\dfrac{5}{3}\)

\(\Leftrightarrow\dfrac{3}{10}:\left(\dfrac{1}{2}x-\dfrac{4}{3}\right)=\dfrac{7}{25}-\left(-\dfrac{5}{3}\right)\)

\(\Leftrightarrow\dfrac{3}{10}:\left(\dfrac{1}{2}x-\dfrac{4}{3}\right)=\dfrac{146}{75}\)

\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{4}{3}=\dfrac{3}{10}:\dfrac{146}{75}\)

\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{4}{3}=\dfrac{45}{292}\)

\(\Leftrightarrow\dfrac{1}{2}x=\dfrac{45}{292}-\dfrac{4}{3}\)

\(\Leftrightarrow\dfrac{1}{2}x=-\dfrac{1033}{876}\)

\(\Leftrightarrow x=-\dfrac{1033}{876}:\dfrac{1}{2}\)

\(\Leftrightarrow x=-\dfrac{1033}{438}\)

Vậy \(x=-\dfrac{1033}{438}\).

Chúc bạn học tốt!

mình trả lời bài 1 thôi nhé :

Gọi biểu thức trên là A.

Theo bài ra ta có:A=1/1.6+1/6.11+1/11.16+...+1/(5n+1)+1/(5n+6)

                           =1/5(1-1/6+1/6-1/11+1/11-1/16+...+1/5n+1-1/5n+6)

                           =1/5(1-1/5n+6)

                           =1/5( 5n+6/5n+6-1/5n+6)

                           =1/5(5n+6-1/5n+6)

                           =1/5.5n+5/5n+6

                           =n+1/5n+6

                           =ĐIỀU PHẢI CHỨNG MINH

x- 20/11.13 - 20/13.15 - 20/13.15 - 20/15.17 -...- 20/53.55=3/11

x-10.(2/11.13+2/13.15+2/15.17+...+2/53.55=3/11

x-10.(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)=3/11

x-10.(1/11-1/55)=3/11

x-10.4/55=3/11

x-8/11=3/11

x = 3/11+8/11

x=11/11=1

****

ban Optimus Prime sai dau bai rui

\(\dfrac{0,3.x+2,5}{x}-3=17\)

<=> \(\dfrac{0,3.x+2,5}{x}=20\)

<=> 0,3.x + 2,5 = 20x
<=> 2,5 = 20x - 0,3.x
<=> 2,5 = 19,7.x
<=> x = \(\dfrac{25}{197}\)
@Khánh Linh

\(\Leftrightarrow8^x\cdot6\cdot\dfrac{1}{8}+8^x\cdot8=8^{19}\left(6+8\right)\)

\(\Leftrightarrow8^x=8^{19}\cdot14:\left(\dfrac{3}{4}+8\right)=8^{19}\cdot\dfrac{8}{5}=\dfrac{8^{20}}{5}\)

\(\Leftrightarrow x\in\varnothing\)

Vì 56⋮x,70⋮x ➞ x∈ƯC(56;70)

Ta có:

56=2³.7

70=2.5.7

ƯCLN(56;70)=2.7=14

ƯC(56;70)=Ư(14)={1;2;7;14}

Vì 56⋮x,70⋮x và 10<x<20

⇔x=14

Tham khảo:

Ta có:

56 = 2³ . 7

70 = 2 . 5 . 7

⇒ ƯCLN ( 56 ; 70 ) = 2. 7 =14

⇒ ƯC ( 56 ; 70 ) = { 1 ; 2 ; 7 ; 14 }

mà 10<x<20

⇒ x = 14

Ư(56) = {1; 2; 4; 7; 8; 14; 28; 56}

Ư(70) = {1; 2; 5; 7; 10; 14; 35}

=>x ∈ ƯC (56; 70) = {1; 2; 7; 14}

Mà 10 < x < 20; x ∈ N nên x ∈ 14

\(\frac{x-20}{x-10}=\frac{x+40}{x+70}=\frac{-20-40}{-10-70}=\frac{6}{8}=\frac{3}{4}.\)

\(\Rightarrow4\cdot\left(x-20\right)=3\cdot\left(x-10\right)\Leftrightarrow4x-80=3x-30\Leftrightarrow x=50.\)

bn dinh thuy linh gioi that, toàn dung ngôn ngữ toán hoc nên bai lam rat ấn tuong