\(=\left(4x^2-7x-50\right)^2-x^2\left(16x^2+56x+49\right)\)

\(=\left(4x^2-7x-50\right)^2-x^2\left(4x+7\right)^2\)

\(=\left(4x^2-7x-50-4x^2-7x\right)\left(4x^2-7x-50+4x^2+7x\right)\)

\(=\left(-14x-50\right)\left(8x^2-50\right)\)

\(=-4\left(7x+25\right)\left(2x-5\right)\left(2x+5\right)\)

3x (5x² - 2x - 1)

= -2,5 nha chị

(x²+y²-5)²-4x²y²-16xy-16

\(\left(4x^2-7x-50\right)^2-16x^4-56x^3-49x^2\)

\(=\left(4x^2-7x-50\right)^2-\left(4x^2\right)^2-2.4x^2.7x-\left(7x\right)^2\)

\(=\left(4x^2-7x-50\right)^2-\left(4x^2-7x\right)^2\)

\(=\left(4x^2-7x-50-4x^2+7x\right)\left(4x^2-7x-50+4x^2-7x\right)\)

\(=-50\left(8x^2-14x-50\right)\)

\(\left(4x^2-7x-50\right)^2-16x^4-56x^3-49x^2\)

\(\text{Phân tích thành nhân tử}\)

\(\left(-4\right)\left(2x-5\right)\left(7x+25\right)\)

\(x^m+3.y-x^m+1.Y^3-x^3.y^m+1+xy^m+3\)

\(\text{Phân tích thành nhân tử}\)

\(-\left(x^3y^m-xy^m-y^3-3y-4\right)\)

Câu 3 ko hiểu >o<

hài bài khó quá mình cũng học lớp 8 nhưng kho lắm

a) \(3x^2-4y+4x-3y^2\)

\(=\left(3x^2-3y^2\right)-\left(4y-4x\right)\)

\(=3\left(x^2-y^2\right)-4\left(x+y\right)\)

\(=3\left(x-y\right)\left(x+y\right)-4\left(x+y\right)\)

\(=\left(x+y\right)\left(3\left(x-y\right)-4\right)\)

\(=\left(x+y\right)\left(3x-3y-4\right)\)

d) \(ax^2-5x^2-ax+5x+a-5=\left(ax^2-ax+a\right)+\left(-5x^2+5x-5\right)\)

\(=a\left(x^2-x+1\right)-5\left(x^2-x+1\right)=\left(a-5\right)\left(x^2-x+1\right)\)

e) \(ax-bx-2cx-2a+2b+4c=x\left(a-b-2c\right)-2\left(a-b-2c\right)\)

\(=\left(x-2\right)\left(a-b-2c\right)\)

ax^2 - 5x^2-ax+5x+a-5

=x^2(a-5) -x(a-5)+(a-5)

=(a-5)(x^2-x+1)

ax-bx-2cx-2a+2b+4c

=x(a-b-c) -2(a-b-c)

=(x-2)(a-b-c)

Nhập ĐT nên k tiện gõ công thức, thông cảm

d, \(ax^2-5x^2-ax+5x+a-5\)

\(=\left(ax^2-ax+a\right)-\left(5x^2-5x+5\right)\)

\(=a\left(x^2-x+1\right)-5\left(x^2-x+1\right)\)

\(=\left(a-5\right)\left(x^2-x+1\right)\)

e, \(ax-bx-2cx-2a+2b+4c\)

\(=a\left(x-2\right)-b\left(x-2\right)-2c\left(x-2\right)\)

\(=\left(x-2\right)\left(a-b-2c\right)\)

f, \(\left(4x^2-7x-50\right)^2-16x^4-56x^3-49x^2\)

\(=\left(4x^2-7x-50\right)\left(4x^2-7x-50\right)-16x^4-56x^3-49x^2\)

\(=16x^4-28x^3-200x^2-28x^3+49x^2+350x-200x^2+350x+2500-16x^4-56x^3-49x^2\)

\(=-112x^3-400x^2+700x+2500\)

\(=-\left(112x^2+400x^2-700x-2500\right)\)

\(=-\left(112x^3-280x^2+680x^2-1700x+1000x-2500\right)\)

\(=-\left[112x^2\left(x-2,5\right)+680x\left(x-2,5\right)+1000\left(x-2,5\right)\right]\)

\(=-\left[\left(x-2,5\right)\left(112x^2+680x+1000\right)\right]\)

\(=-\left[\left(x-2,5\right)\left(112x^2+280x+400x+1000\right)\right]\)

\(=-\left\{\left(x-2,5\right)\left[112x\left(x+2,5\right)+400\left(x+2,5\right)\right]\right\}\)

\(=-\left[\left(x-2,5\right)\left(x+2,5\right)\left(112x+400\right)\right]\)

\(=-\left[16\left(x-2,5\right)\left(x+2,5\right)\left(7x+25\right)\right]\)

Chúc bạn học tốt!!!