B= 1/1.3.5 + 1/3.5.7 + 1/5.7.9 + ... + 1/95.97.99(vì ko bít viết gạch ngang nên mik viết bằng / mn hiểu là phân số)
Tìm B
Ai trả lời đầy đủ và đúng nhất mik sẽ like
A= 1/1.3.5+ 1/3.5.7+1/5.7.9+.....+1/95.97.99
\(A=\frac{1}{1.3.5}+\frac{1}{3.5.7}+\frac{1}{5.7.9}+...+\frac{1}{95.97.99}\)
\(A=4.\left(\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+\frac{1}{5.7}-\frac{1}{7.9}+...+\frac{1}{95.97}-\frac{1}{97.99}\right)\)
\(A=4.\left(\frac{1}{1.3}-\frac{1}{97.99}\right)\)
\(A=4.\frac{3200}{9603}=\frac{12800}{9603}\)
\(A=\frac{1}{1.3.5}+\frac{1}{3.5.7}+\frac{1}{5.7.9}+...+\frac{1}{95.97.99}\)
\(A=\frac{1}{4}.\left(\frac{1}{1.3.5}+\frac{1}{3.5.7}+\frac{1}{5.7.9}+...+\frac{1}{95.97.99}\right)\)
\(A=\frac{1}{4}.\left(\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+\frac{1}{5.7}-\frac{1}{7.9}+...+\frac{1}{95.97}-\frac{1}{97.99}\right)\)
\(A=\frac{1}{4}.\left(\frac{1}{1.3}-\frac{1}{97.99}\right)\)
\(A=\frac{1}{4}.\frac{3200}{9603}\)
\(A=\frac{800}{9603}\)
Bài trc mik làm lộn :)))
~ Hok tốt ~
Giup mk .Mk like bn nào trả lời sóm nhất , đúng nhất .
A=6/1.3.7 + 6/3.7.9 + 6/7.9.13 + 6/9.13.15 + 6/13.15.19
Nếu các bn ko biết giải cách tiểu học thì giải theo sau
B=4/1.3.5 + 4/3.5.7 + 4/5.7.9 + 4/7.9.11 + 4/9.11.13
B=5-1/1.3.5 + 7-3/3.5.7 +........+ 13-9/9.11.13
B=5/1.3.5 - 1/1.3.5 + 7/3.5.7 - 3/3.5.7 +............... + 13/9.11.13 - 9/9.11.13
B=1/1.3 - 1/3.5 + 1/3.5 - 1/5.7 + ............. + 1/9.11 - 1/11.13
B=1/1.3-1/11.13
B= 11.13/3.11.13 - 3/3.11.13 = 140/425
tính
A= 1/1.3.5+ 1/3.5.7+1/5.7.9+.....+1/95.97.99
A = 1/4.( 4/1.3.5 + 4/3.5.7+ ....+ 4/95.97.99)
= 1/4 .( 1/ 1.3 - 1/3.5 + 1/3.5 - 1/5.7 + .......+ 1/95.97 - 1/97.99)
= 1/4( 1/1.3 - 1/97.99)
= 1/4 . 9499/29397
Tính tổng
a) 9+99+999+...+999999
b) 1+11+111+...+1111111
c)1.2 + 2.3+3.4+4.5+...+98.99
d) 1.3.5 + 3.5.7+5.7.9+...+95.97.99
a) 9 + 99 + 999 + ... + 999999
= (10 - 1) + (100 - 1) + (1000 - 1) + ... + (1000000 - 1)
= (101 + 102 + 103 + ... + 106) - (1.6)
= 1111110 - 6 = 1111104
b) 1 + 11 + 111 + ... + 1111111
= 1 + (101 + 1) + (102 + 101 + 1) + ... + (106 + 105 + 104 + 103 + 102 + 101 + 1)
= 101 . 6 + 102 . 5 + 103 . 4 + ... + 106. 1) + (1 + 1.6)
= 60 + 500 + 4000 + ... + 1000000 + 7
= 1234560 + 7 = 1234567
c) C = 1.2 + 2.3 + 3.4 + 4.5 + ... + 98.99
3C = 1.2.3 + 2.3.3 + 3.4.3 + 4.5.3 + ... + 98.99.3
3C = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 98.99.(100 - 97)
3C = 1.2.3 + 2.3.4 - 2.3.1 + 3.4.5 - 3.4.2 +...+ 98.99.100 - 98.99.97
3C = 98.99.100
C = \(\dfrac{98.99.100}{3}\) = 323400
d) D = 1.3.5 + 3.5.7 + 5.7.9 + ... + 95.97.99
8D = 1.3.5.8 + 3.5.7.8 + 5.7.9.8 + ... + 95.97.99.8
8D = 1.3.5.(7 + 1) + 3.5.7.(9 - 1) + 5.7.9.(11 - 3) + ... + 95.97.99.(101 - 93)
8D = 1.3.5.7 + 1.3.5.1 + 3.5.7.9 - 3.5.7.1 + 5.7.9.11 - 5.7.9.3 + ... + 95.97.99.101 - 95.97.99.93
8D = 1.3.5.1 + 95.97.99.101
D = \(\dfrac{1.3.5.1+95.97.99.101}{8}=15517600\)
1.3.5+3.5.7+5.7.9+...+93.95.97+95.97.99
(.) là x
Đặt A = \(1.3.5+3.5.7+5.7.9+..+93.95.97+95.97.99\)
\(8A=1.3.5.8+3.5.7.8+...+93.95.97.8+95.97.99.8\)
\(8A=1.3.5.\left(1+7\right)+3.5.7.\left(9-1\right)+...+95.97.99\left(101-93\right)\)
\(8A=1.3.5.7+15+3.5.7.9-1.3.5.7+...+95.97.99.101-93.95.97.99\)
\(8A=15+95.97.99.101\)
\(\Rightarrow\) \(A=\frac{15+95.97.99.101}{8}\)
\(KL:........\)
Tính tổng : C = 1.3.5 + 3.5.7 + 5.7.9 + .... + 93.95.97 + 95.97.99
Tính tổng
a)A=1/5+1/5^2+1/5^3+...+1/5^25
b)H=5+55+555+...+{5555555555} 10 chữ số 5
f)D=1.3.5+3.5.7+5.7.9+...+95.97.99
Ai giải được mình cảm ơn =))
a)\(A=\frac{1}{5}+\frac{1}{5^2}+....+\frac{1}{5^2^5}\) <=>\(5A=1+\frac{1}{5}+\frac{1}{5^2}+....+\frac{1}{5^{24}}\)
<=>\(5A-A=(1+\frac{1}{5}+...+\frac{1}{5^{24}})-(\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{25}})\)
<=>\(4A=1-\frac{1}{5^{25}}\) <=>\(A=\frac{(5^{25^{ }}-1)}{5^{25}}\div4\)
G=1.3.5+3.5.7+5.7.9+...+95.97.99
Tính tổng G
\(G=1.3.5+3.5.7+5.7.9+...+95.97.99\)
\(G=1+99.\left(3+5+7+...+97\right)\)\
\(G=100.\left[\left(3+97\right)+\left(5+95\right)+...+\left(49+51\right)\right]\)
\(G=100.\left(100.24\right)\)
\(G=100.2400=240000\)
Tính
1/1.3.5 + 1/3.5.7 + 1/5.7.9 + ... + 1/99.101.103
CÁC BẠN GIÚP MIK VỚI
1/1.3.5 + 1/3.5.7 + 1/5.7.9 +.....+ 1/99.101.103
= 1/4. [4/1.3.5 + 4/3.5.7 + 4/ 5.7.9 +....+ 4/99.101.103]
=1/4. [1/1.3 - 1/3.5 + 1/3.5 - 1/5.7 +....+ 1/99.101 - 1/101.103]
= 1/4. [1/1.3 - 1/101.103]
=1/4. 10406/31209
= 5230/62418
\(A=\frac{1}{1\cdot3\cdot5}+\frac{1}{3\cdot5\cdot7}+....+\frac{1}{99\cdot101\cdot103}\)
\(2A=\frac{1}{1\cdot3}-\frac{1}{3\cdot5}+\frac{1}{3\cdot5}-\frac{1}{5-7}+....+\frac{1}{99\cdot101}-\frac{1}{101\cdot103}\)
\(2A=\frac{1}{1\cdot3}-\frac{1}{101\cdot103}\)
Tính nốt