a) 7(2x-1)=(346.124)-346

14x-7=42558

14x=42551

x=42551/14

b) 4/3+2(5+7x)=23

2(5+7x)=65/3

5+7x=65/6

7x=35/6

x=5/6

a) 346.124-7.(2x-1)=343

346.124-14x+7=343

42904-14x+7=343

-14x=343-42904-7

-14x=-42568

x=\(\dfrac{-42568}{-14}\)=\(\dfrac{42568}{14}\)=3,04

vậy x = 3,04

b)\(\dfrac{4}{3}\)+2(5+7x)=115:5

\(\dfrac{4}{3}\)+10+14x=23

14x=23-10-\(\dfrac{4}{3}\)

14x= \(\dfrac{35}{3}\)

x=\(\dfrac{35}{3}\):14

x=\(\dfrac{35}{42}\)=\(\dfrac{5}{6}\)

Tìm x :

346 . 124 - 7 . ( 2x - 1 ) = 346

7 . ( 2x - 1 ) = ( 346 . 124 ) - 346

7. ( 2x - 1 ) = 346 . 123

7 . 2x - 7 .1 = 42558

7 . 2x = 42558 - 7

7.2. x = 42551

14 . x = 42551

=> x = \(\dfrac{42551}{14}\)
Vậy : x = \(\dfrac{42551}{14}\)

b) \(\dfrac{4}{3}\) +2 . ( 5 + 7x ) = 115 : 5

\(\dfrac{4}{3}\) + 2. 5 + 2 . 7.x = 23

\(\dfrac{4}{3}\) + 10 + 14 . x = 23

\(\dfrac{4}{3}\) + 24 . x = 23

=> \(\dfrac{76}{3}\) . x = 23

=> x = 23 : \(\dfrac{76}{3}\)

=> x = \(\dfrac{69}{76}\)

Vậy x = \(\dfrac{69}{76}\)

giao cho mik

a)346.124 - 7.(2x - 1 ) = 346

      42904 - 7.(2x - 1 ) = 346

                  7.(2x - 1 ) = 42904 - 346

                  7.(2x - 1 ) = 42558

                        2x - 1 = 42558 :7

                        2x - 1 = 42558/7

                             2x = 42558/7+1 

                             2x = 42565/7

                               x = 42565/7:2

                               x = 42565/14

a)346.124 - 7.(2x - 1 ) = 346

      42904 - 7.(2x - 1 ) = 346

                  7.(2x - 1 ) = 42904 - 346

                  7.(2x - 1 ) = 42558

                        2x - 1 = 42558 :7

                        2x - 1 = 42558/7

                             2x = 42558/7+1 

                             2x = 42565/7

                               x = 42565/7:2

                               x = 42565/14

346.124-7.(2x-1)=346

Suy ra: 7.(2x-1)=346.123-346

Nên: 7.(2x-1)=346.(123-1)

7.(2x-1)=346.122

2x-1=42212:7

2x-1=42212 phần 7

2x=42212 phần 7+1

2x=42219 phần 7

x=42219 phần 7:2

Vậy x=42219 phần 14

4 phần 3+2.(5+7x)=115:5

4 phần 3+2.(5+7x)=23

2.(5+7x)=23:4 phần 3

2.(5+7x)=69 phần 4

5+7x=69 phần 4:2

5+7x=69 phần 8

7x=69 phần 8 -5

7x=29 phần 8

x=29 phần 8:7

Vậy x=29 phần 56

\(1,\\ a,=7x^3-49x^2+21x\\ b,=x^2-x-42\\ c,=x^2-16x+64\\ d,=9x^2+12x+4\\ e,=x^2-16-25+10x-x^2=10x-41\\ 2,\\ a,\Rightarrow2\left(x-7\right)=19\\ \Rightarrow x-7=\dfrac{19}{2}\Rightarrow x=\dfrac{33}{2}\\ b,\Rightarrow4x^2-20x+25-4x^2+3x-2x=50\\ \Rightarrow-19x=25\Rightarrow x=-\dfrac{25}{19}\)

`a,4x-10=0   `

`<=> 4x=10`

`<=>x=10/4`

`<=>x=5/2`

`b, 7-3x=9-x     `

`<=>-3x+x=9-7`

`<=>-2x=2`

`<=>x=-1`

`c, 2x-(3-5x) = 4(x+3)`

`<=>2x-3+5x=4x+12`

`<=>2x+5x-4x=12+3`

`<=>3x=15`

`<=>x=5`

`d, 5-(6-x)=4(3-2x)     `

`<=>5-6+x=12-8x`

`<=>x+8x=12-5+6`

`<=>9x=13`

`<=>x=13/9`

`e, 4(x+3)=-7x+17   `

`<=>4x+12=-7x+17`

`<=>4x+7x=17-12`

`<=>11x=5`

`<=>x=5/11`   

`f, 5(x-3) - 4=2(x-1)+7`

`<=>5x-15-4=2x-2+7`

`<=>5x-2x=15+4-2+7`

`<=>3x=24`

`<=>x=8`

`g, 5(x-3)-4=2(x-1)+7       `

`<=>5x-15-4=2x-2+7`

`<=>5x-2x=15+4-2+7`

`<=>3x=24`

`<=>x=8`

`h,4(3x-2)-3(x-4)=7x+20`

`<=>12x-8-3x+12=7x+20`

`<=>12x-3x-7x=20+8+12`

`<=>2x=40`

`<=>x=20`

a) ( 2x - 3 ) - ( x - 5 ) = ( x + 7 ) - ( x + 2 ) 

<=> 2x - 3 - x + 5 = x + 7 - x - 2

<=> x = 3

b)(7x-5)-(6x+4)=(2x+3)-(2x+1)

<=> 7x - 5 - 6x - 4 = 2x + 3 - 2x - 1

<=> x = 11

c)(9x-3)-(8x+5)=(3x+2)

<=> 9x - 3 - 8x - 5 = 3x + 2

<=> -2x = 10

<=> x = -5

d)(x+7)-(2x+3)=(3x+5)-(2x+4)

<=> x + 7 - 2x - 3 = 3x + 5 - 2x - 4

<=> -2x = -3

<=> x = 3/2

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Mài ngu

a) 2x-5=3+2x-7x

2x-2x+7x=3+5

7x=8

  x=8/7

vậy x=8/7

a) 2x - 5 = 3 + 2x - 7x

=> 2x - 2x + 7x = 3 +5 

=> 7x = 8

=> x = 8/7

b) \(\left(2x-1\right)^2=\left(2x-1\right)^5\)

=> \(\left(2x-1\right)^2-\left(2x-1\right)^5=0\)

=> \(\left(2x-1\right)^2\left[1-\left(2x-1\right)^3\right]=0\)

=> \(\orbr{\begin{cases}\left(2x-1\right)^2=0\\1-\left(2x-1\right)^3=0\end{cases}}\)

=> \(\orbr{\begin{cases}2x-1=0\\\left(2x-1\right)^3=1\end{cases}}\)

=> \(\orbr{\begin{cases}2x=1\\2x-1=1\end{cases}}\)

=> \(\orbr{\begin{cases}x=\frac{1}{2}\\2x=2\end{cases}}\)

=> \(\orbr{\begin{cases}x=\frac{1}{2}\\x=1\end{cases}}\)