Cho \(S=\dfrac{2}{2005+1}+\dfrac{2^2}{2005^2+1}+.......+\dfrac{2^{n+1}}{2005^{2^n}+1}+........+\dfrac{2^{2006}}{2005^{2^{2005}}+1}\)
So sánh \(S\) với \(\dfrac{1}{1002}\)
Hồng Phúc Nguyễn
Các bạn ơi giải hộ mình !
\(Cho\) \(S=\dfrac{2}{2005+1}+\dfrac{2^2}{2005^2+1}+\dfrac{2^3}{2005^{2^2}+1}+...+\dfrac{2^{n+1}}{2005^{2^n}+1}+....+\dfrac{2^{2006}}{2005^{2^{2005}}+1}\)
SO SÁNH S với \(\dfrac{1}{1002}\)
Cho \(S=\dfrac{2}{2005+1}+\dfrac{2^2}{2005^2+1}+\dfrac{2}{2005^{2^2}+1}+................+\dfrac{2^{n+1}}{2005^{2^n}+1}+..........+\dfrac{ }{2005^{2^{2005}}+1}\)
So sánh \(S\) với \(\dfrac{1}{1002}\)
Help me!!!!!!!!!!!!
Chứng minh rằng :
\(S=\dfrac{2006}{2005^2+1}+\dfrac{2006}{2005^2+2}+\dfrac{2006}{2005^2+2005}\)
Không phải là số nguyên dương.
so sánh 2 phân số,giúp mk với
:A=\(\dfrac{2005^{2005}+1}{2005^{2006}+1};B=\dfrac{2005^{2004}+1}{2005^{2005}+1}\)
Ta có:
\(2005A=\dfrac{2005^{2006}+2005}{2005^{2006}+1}=1+\dfrac{2004}{2005^{2006}+1}\)
\(2005B=\dfrac{2005^{2005}+2005}{2005^{2005}+1}=1+\dfrac{2004}{2005^{2005}+1}\)
Vì \(\dfrac{2004}{2005^{2006}+1}< \dfrac{2004}{2005^{2005}+1}\Rightarrow1+\dfrac{2004}{2005^{2006}+1}< 1+\dfrac{2004}{2005^{2005}+1}\)
\(\Rightarrow2005A< 2005B\Rightarrow A< B\)
Vậy A < B
Cho \(S=\frac{2}{2005+1}+\frac{2^2}{2005^2+1}+...+\frac{2^{n+1}}{2005^{^{2^n}}+1}+...+\frac{2^{2006}}{2006^{2^{2005}}+1}\). So sánh S với \(\frac{1}{1002}\)
Cho S= \(\frac{2}{2005+1}+\frac{2^2}{2005^2+1}+\frac{2^3}{2005^{2^2}+1}+........+\frac{2^{n+1}}{2005^{2^n}+1}+.......+\frac{2^{2006}}{2005^{2^{2006}}+1}\)
So sánh S với \(\frac{1}{1002}\)
Cho S=\(\frac{2}{2005+1}+\frac{2^2}{2005^2+1}+\frac{2^3}{2005^{2^2}}+...\)\(..+\frac{2^{n+1}}{2005^{2^n}}+...+\frac{2^{2006}}{2005^{2^{2005}}+1}\)
So sánh S với \(\frac{1}{1002}\)
a,tính tổng : \(S=\dfrac{27+4500+135+550+2}{2+4+6+...+14+16+18}\)
b, So sánh : \(A=\dfrac{2006^{2006}+1}{2006^{2007}+1}v\text{à }B=\dfrac{2006^{2005}+1}{2006^{2006}+1}\)
- Mình dùng cách lớp 8 để làm câu b được không :)?
- Tham khảo câu b:
https://olm.vn/hoi-dap/tim-kiem?q=+++++++++++A=2006%5E2005+1/2006%5E2006+1B=2006%5E2006+1/2006%5E2007+1so+s%C3%A1nh+A+v%C3%A0+B&id=520258
Cho \(S=\frac{2}{2005+1}+\frac{2^2}{2005^2+1}+\frac{2^3}{2005^{2^2}+1}+...+\frac{2^{n+1}}{2005^{2^{n+1}}+1}+...+\frac{2^{2006}}{2005^{2^{2006}}+1}\)
So sánh S với \(\frac{1}{1002}\)