Question

a,tính tổng : \(S=\dfrac{27+4500+135+550+2}{2+4+6+...+14+16+18}\)

b, So sánh : \(A=\dfrac{2006^{2006}+1}{2006^{2007}+1}v\text{à }B=\dfrac{2006^{2005}+1}{2006^{2006}+1}\)

Answer 1

- Mình dùng cách lớp 8 để làm câu b được không :)?

Answer 2

- Tham khảo câu b:

https://olm.vn/hoi-dap/tim-kiem?q=+++++++++++A=2006%5E2005+1/2006%5E2006+1B=2006%5E2006+1/2006%5E2007+1so+s%C3%A1nh+A+v%C3%A0+B&id=520258

Answer 3

:< dễ lém á , mng giúp mìn ii 

Answer 4

b)

Ta có:

\(A=\dfrac{2006^{2006}+1}{2006^{2007}+1}=\dfrac{2006^{2006}+1}{2006^{2006}.2006+1}=\dfrac{1+1}{2006+1}=\dfrac{2}{2007}\)

\(B=\dfrac{2006^{2005}+1}{2006^{2006}+1}=\dfrac{2006^{2005}+1}{2006^{2005}.2006+1}=\dfrac{1+1}{2006+1}=\dfrac{2}{2007}\)

Vì\(\dfrac{2}{2007}=\dfrac{2}{2007}\Rightarrow A=B\)

Answer 5