\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\left(a+5\right).\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)

\(\Rightarrow ab-6a+5b-30=ab+6a-5b-30\)

\(\Rightarrow\left(ab-6a+5b-30\right)-\left(ab+6a-5b-30\right)=0\)

\(\Rightarrow ab-6a+5b-30-ab-6a+5b+30=0\)

\(\Rightarrow-12a+10b=0\)

\(\Rightarrow-12a=10b\Rightarrow\frac{a}{b}=\frac{-10}{12}\Rightarrow\frac{a}{b}=\frac{-5}{6}\)

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow ab+5b-6a-30=ab+6a-5b-30\)

\(\Rightarrow5a-6b=6a-5b\)

\(5a-6a=-5b+6b\)

\(-a=b\)

\(\frac{a}{b}=-1\)

a/b = 5/6.

1.Tìm x, biết:

=>x=6; y=10

2.Cho

CMR:

Lại có: (*)=a+5-a+5/b+6-b+6=10/12=5/6 (2)

Từ 1 và 2 suy ra a/b=5/6 (đpcm)

Có \(\dfrac{a+5}{a-5}=\dfrac{b+6}{b-6}\)

\(\Rightarrow\left(a+5\right)\left(b-6\right)=\left(b+6\right)\left(a-5\right)\)

ab-6a+5b-30=ab-5b+6a-30

12a=10b

\(\dfrac{a}{b}=\dfrac{5}{6}\)

ta có :\(\dfrac{a+5}{a-5}=\dfrac{b+6}{b-6}\)\(=>\dfrac{a+5}{b+6}=\dfrac{a-5}{b-6}=\dfrac{a+5+a-5}{b+6+b-6}=\dfrac{2a}{2b}=\dfrac{a}{b}\left(1\right)\)

Mặt khác:\(\dfrac{a+5}{b+6}=\dfrac{a-5}{b-6}=\dfrac{a+5-a+5}{b+6-b+6}=\dfrac{10}{12}=\dfrac{5}{6}\left(2\right)\) Từ (1),(2)=>\(\dfrac{a}{b}=\dfrac{5}{6}\left(đpcm\right)\)

\(Cho \frac{a+5}{a-5}=\frac{b+6}{b-6} \)

⇔\(\left(a+5\right)\cdot\left(b-6\right)=\left(a-5\right)\cdot\left(b+6\right)\)

⇔\(\frac{a+5}{b+6}=\frac{a-5}{b-6}\)⇒ \(\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{a}{b}=\frac{5}{6}\)

Vậy \(\frac{a}{b}=\frac{5}{6}\)

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\(\left(a+5\right)\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)

\(\Leftrightarrow ab-6a+5b-30=ab+6a-5b-30\)

\(\Leftrightarrow ab-ab+5b+5b-30+30=6a+6a\)

\(\Leftrightarrow10b=12a\)

\(\Rightarrow\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\left(đpcm\right)\)

a+5/a-5=b+6/b-6=a+5/b+6=b+6/b-69 (giao hoán trung tỉ)=>(a+5)-5/(b+6)-6=(a+5)-a/(b+6)-6=a/b=5/6

BẠN ƠI CÁI MÀ '/' LÀ PHẦN NHA

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)

<=> \(\frac{a-5+10}{a-5}=\frac{b-6+12}{b-6}\)

<=> \(1+\frac{10}{a-5}=1+\frac{12}{b-6}\)

<=> \(\frac{10}{a-5}=\frac{12}{b-6}\)

<=> 10( b - 6 ) = 12( a - 5 )

<=> 5( b - 6 ) = 6( a - 5 )

<=> 5b - 30 = 6a - 30

<=> 5b = 6a

<=> \(\frac{6}{5}=\frac{b}{a}\)hay \(\frac{a}{b}=\frac{5}{6}\)( đpcm )

Ta có: \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)

\(\Rightarrow\left(a+5\right).\left(b-6\right)=\left(a-5\right).\left(b+6\right)\)

\(ab-6a+5b-30=ab+6a-5b-30\)

\(\Rightarrow5b-6a=6a-5b\)

\(5b+5b=6a+6a\)

\(10b=12a\)

\(\Rightarrow\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\)

Vậy \(\frac{a}{b}=\frac{5}{6}\)

Tham khảo nhé~

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)

\(\Leftrightarrow\frac{a-5+10}{a-5}=\frac{b-6+12}{b-6}\)

\(\Leftrightarrow1+\frac{10}{a-5}=1+\frac{12}{b-6}\)

\(\Leftrightarrow\frac{10}{a-5}=\frac{12}{b-6}\)

\(\Rightarrow10.\left(b-6\right)=12.\left(a-5\right)\)

\(10b-60=12a-60\)

\(10b=12a\)

\(\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\)

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)

\(=>\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{a+5-\left(a-5\right)}{b+6-\left(b-6\right)}=\frac{a+5-a+5}{b+6-b+6}=\frac{10}{12}=\frac{5}{6}\)

\(\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{a+5+\left(a-5\right)}{b+6+\left(b-5\right)}=\frac{a+5+a-5}{b+6+b-6}=\frac{2a}{2b}=\frac{a}{b}\)

=>\(\frac{a}{b}=\frac{a+5}{b+5}=\frac{5}{6}\)

=>\(\frac{a}{b}=\frac{5}{6}\)