=<br class="Apple-interchange-newline"><div id="inner-editor"></div>12,48:0,5.6,25.4.22.3,12.1,25:0,25.10 = 12,48.2.6.25.4.22.3,12.1,25.4.10 = 3,12.4.2.1,25.5.4.22.3,12.1,25.4.5.2 = 4

Ghi đề dấu nhân rõ ràng ra nha

\(\dfrac{12,48:0,5\times6,25\times4\times2}{2\times3,12\times1,25:0,25\times10}\\ =\dfrac{12,48\times2\times6,25\times4\times2}{2\times3,12\times1,25\times4\times10}\\ =\dfrac{12,48}{3,12}\times\dfrac{2}{2}\times\dfrac{2}{10}\times\dfrac{6,25}{1,25}\times\dfrac{4}{4}\\ =4\times1\times\dfrac{1}{5}\times5\times1=4\)

12

=12

12

12,48x17,29-12,48x2,48

=12,48x(17,29-2,48

=12,48 x 24,81

=309,6288

\(\text{12,48×17,29-12,48×2,48}\)

\(=12,48.\left(17,29-2,48\right)\)

\(=12,48.14,81\)

\(=184,8288\)

=12,48*(17,29 - 2,48)

=12,48*14,81

=184,8288

12,48 : 0,5 * 6,25 * 4 * 2 = 12,48 * 2 * 6,25 * 4 * 2

                                    = 12,48 * 2 * ( 6,25 * 4 ) * 2

                                    = 12,48 * 2 * 25 * 2

                                    = 12,48 * 25 * ( 2 * 2 )

                                    = 12,48 * 25 * 4

                                    = 12,48 * ( 25 * 4)

                                    = 12,48 * 100

                                    = 1248

2 * 3,12 * 1,25 : 0,25 * 10 = 2 * 3,12 * 1,25 * 4 * 10

                                      = 3,12 * 1,25 * ( 4 * 2 ) * 10

                                      = 3,12 * 1,25 * 8 * 10

                                      = 3,12 * ( 1,25 * 8 ) * 10

                                      = 3,12 * 10 * 10

                                      = 3,12 * ( 10 * 10 )

                                      = 3,12 * 100

                                      = 312

64896

Đáp án nha bạn, bạn muốn mình giải ra luôn không?

=64896 nha BẠN

a) \(m_{CuSO_4}=0,3.160=48\left(g\right)\)

b) \(n_{CaCO_3}=\dfrac{9.10^{23}}{6.10^{23}}=1,5\left(mol\right)=>m_{CaCO_3}=1,5.100=150\left(g\right)\)

c) \(n_{MgCl_2}=\dfrac{1,5.10^{22}}{6.10^{23}}=0,025\left(mol\right)=>m_{MgCl_2}=0,025.95=2,375\left(g\right)\)

e) \(n_{CO_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)=>m_{CO_2}=0,1.44=4,4\left(g\right)\)

f) \(n_{NaOH}=\dfrac{0,25.10^{24}}{6.10^{23}}=\dfrac{5}{12}\left(mol\right)=>m_{NaOH}=\dfrac{5}{12}.40=16,667\left(g\right)\)

\(12,49\times12,47=155,7503\)

\(12,48\times12,48=155,7504\)

Vay 12,49.12,47<12,48.12,48

12,47x12,47<12,48x12,48

12,49x12,47 và 12,48x12,48

155.7503    <       155,7504

\(\Rightarrow\)12,49x12,47<12,48x12,48