1. \(4:3:2\)

2. \(4:1:2\)

3. \(2:1:3\)

4. \(1:6:2:3\)

5. \(2:6:2:3\)

6. \(1:2:1:1\)

7. \(1:3:1:3\)

8. \(1:2:2:1\)

9. \(3:2:3:2\)

10. \(1:1:2:1\)

Câu 1:

\(1,CO_2+Ca(OH)_2\to CaCO_3\downarrow+H_2O\\ 2,Na+H_2O\to NaOH+\dfrac{1}{2}H_2\\ 4,Al_2O_3+6HCl\to 2AlCl_3+3H_2O\\ 5,4P+5O_2\xrightarrow{t^o}2P_2O_5\\ 6,FeO+2HCl\to FeCl_2+H_2O\\ 7,Fe_2O_3+3H_2SO_4\to Fe_2(SO_4)_3+3H_2O\\ 8,2NaOH+H_2SO_4\to Na_2SO_4+2H_2O\\ 9,3Ca(OH)_2+2FeCl_3\to 2Fe(OH)_3\downarrow+3CaCl_2\\ 10,Fe(OH)_3+3HCl\to FeCl_3+3H_2O\\ 11,N_2O_5+H_2O\to 2HNO_3\\ 12,Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O\)

Câu 2:

\(1,CaO+CO_2\to CaCO_3\\ 1:1:1\\ 2,Al_2O_3+6HCl\to 2AlCl_3+3H_2O\\ 1:6:2:3\\ 3,3KOH+AlCl_3\to 3KCl+Al(OH)_3\downarrow\\ 3:1:3:1\\ 4,Mg+2HCl\to MgCl_2+H_2\\ 1:2:1:1\)

1/ 2Al + 3O2 → 2Al2O3

2/ 4K + O2 → 2K2O

3/ 2Al(OH)3 t0 → Al2O3 + 3H2O

4/ Al2O3 + 6HCl → 2AlCl3 + 3H20

5/ 2Al + 6HCl → 2AlCl3 + 3H2↑

6/ Fe0 + 2HCl → FeCl2 + H20

7/ Fe203 + 3H2S04 → Fe2(S04)3 + 3H20

8/ 2Na0H + H2S04 → Na2S04 + 2H20

9/ 3Ca(0H)2 + 2FeCl3 → 3CaCl2 + 2Fe(0H)3 ↓

10/ BaCl2 + H2S04 → BaS04↓ + 2HCl

11/ 2Fe(0H)3 t0→ Fe203 + 3H20

12/ Fe(0H)3 + 3HCl → FeCl3 + 3H20

13/ CaCl2 + 2AgN03 → Ca(N03)2 +2 AgCl ↓

14/4P +502 t0→2P205

15/ N2O5 + H2O →2HNO3

16/ Zn +2HCl → ZnCl2 + H2↑

17/2Al +3CuCl2 →2AlCl3 +3Cu

18/ C02 + Ca(0H)2 → CaC03↓ + H20

19/ S02 + Ba(0H)2 → BaS03↓ + H20

20/2KMn04 t0 → K2Mn04 + Mn02 + 02↑

1/ 4Al + 3O2 → 2Al2O3

2/ 4K + O2 → 2K2O

3/ 2Al(OH)3 t0 → Al2O3 + 3H2O

4/ Al2O3 + 6HCl → 2AlCl3 + 3H20

5/ 2Al + 6HCl → 2AlCl3 + 3H2↑

6/ Fe0 + 2HCl → FeCl2 + H20

7/ Fe203 + 3H2S04 → Fe2(S04)3 + 3H20

8/ 2Na0H + H2S04 → Na2S04 + 2H20

9/ 3Ca(0H)2 + 2FeCl3 → 3CaCl2 + 2Fe(0H)3 ↓

10/ BaCl2 + H2S04 → BaS04↓ + 2HCl

11/ 2Fe(0H)3 t0→ Fe203 + 3H20

12/ Fe(0H)3 + 3HCl → FeCl3 + 3H20

13/ CaCl2 + 2AgN03 → Ca(N03)2 + 2AgCl ↓

14/ 4P + 502 t0→ 2P205

15/ N205 + H20 → 2HN03

16/ Zn + 2HCl → ZnCl2 + H2↑

17/ 2Al + 3CuCl2 → 2AlCl3 + 3Cu

18/ C02 + Ca(0H)2 → CaC03↓ + H20

19/ S02 + Ba(0H)2 → BaS03↓ + H20

20/ 2KMn04 t0 → K2Mn04 + Mn02 + 02↑

a, 2Na  +  2H20  ---------> 2NaOH   +   H₂ 

b,H2  +  CuO  ----------->   H₂O + Cu  

c,CaO +  H20 -------------> Ca(0H)2  

d, SO2  +  H20 ------> H₂S0₃ 

\(\overset{0}{Cu}+\overset{+1+5-2}{HNO_3}\rightarrow\overset{+2+5-2}{Cu\left(NO_3\right)_2}+\overset{+4-2}{NO_2}+\overset{+1-2}{H_2O}\)

Chất khử : \(Cu\)

Chất oxi hóa : \(N\)

Tiến trình oxi hóa : \(\overset{0}{Cu}\rightarrow\overset{+2}{Cu}+2e\)    \(|\)  \(\times1\)

Tiến trình khử : \(\overset{+5}{N}+1e\rightarrow\overset{+4}{N}\)            \(|\)  \(\times2\)

Cân bằng pt : \(Cu+4HNO_3\rightarrow Cu\left(NO_3\right)_2+2NO_2+2H_2O\)

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Để số phân tử bằng nhau thì số mol cũng phải bằng nhau từ đó tính khối lượng

\(n_{H_2SO_4}=\frac{98}{98}=1mol\)

Có: \(n_{H_2O}=n_{H_2SO_4}=1mol\rightarrow m_{H_2O}=1.18=18g\)

a, \(4P+5O_2\underrightarrow{t^o}2P_2O_5\)

b, \(Na_2O+H_2O\rightarrow2NaOH\)

a,4P+5O2--->2P2O5

b,Na2O+H2O --->2NaOH

_ Tác dụng với H₂O.

PT: \(P_2O_5+3H_2O\rightarrow2H_3PO_4\)

\(N_2O_5+H_2O\rightarrow2HNO_3\)

\(SO_3+H_2O\rightarrow H_2SO_4\)

_ Tác dụng với NaOH.

PT: \(P_2O_5+6NaOH\rightarrow2Na_3PO_4+3H_2O\)

\(N_2O_5+2NaOH\rightarrow2NaNO_3+H_2O\)

\(SO_3+2NaOH\rightarrow Na_2SO_4+H_2O\)

_ Tác dụng với HCl.

PT: \(MgO+2HCl\rightarrow MgCl_2+H_2O\)

\(Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)

\(CuO+2HCl\rightarrow CuCl_2+H_2O\)

Bạn tham khảo nhé!

1. \(Mg+2HCl\rightarrow MgCl_2+H_2\)

2. \(P_2O_5+3H_2O\rightarrow2H_3PO_4\)

3. \(Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\)

4. \(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

5. \(Cu+2AgNO_{3\rightarrow}Cu\left(NO_3\right)_2+2Ag\)