\(\left(x-1\right)^3=125\)

\(\left(x-1\right)^3=5^3\)

\(=>x-1=5\)

\(x=6\)

Tương tự các câu cn lại

a) ( x - 1 ) ³ = 125

( x - 1 ) ³ = 5³

x - 1 = 5

x = 5 + 1

 x = 6

tích nha

Bạn giúp mình làm hết với !  Mình còn nhiều bài tập chưa làm nữa. 

a)\(\left(x-1\right)^3=8\)

\(\Leftrightarrow\left(x-1\right)^3=\left(2\right)^3\)

\(\Leftrightarrow x-1=2\)

\(\Leftrightarrow x=3\)

b)\(2^{x+2}-2^x=96\)

\(\Leftrightarrow2^x.2^2-2^x=96\)

\(\Leftrightarrow2^x\left(2^2-1\right)=96\)

\(\Leftrightarrow2^x=32=2^5\)

\(\Leftrightarrow x=5\)

c)\(\left(2x+1\right)^3=343\)

\(\Leftrightarrow\left(2x+1\right)^3=7^3\)

\(\Leftrightarrow\left(2x+1\right)=7\)

\(\Leftrightarrow x=3\)

d)\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(\Leftrightarrow720:\left[46-2x\right]=40\)

\(\Leftrightarrow46-2x=18\)

\(\Leftrightarrow2x=28\)

\(\Leftrightarrow x=14\)

Nếu bài dễ thì cố gắng tự làm bạn nhé.

Bài 1:

a) \(2x+3=5\)

\(\Leftrightarrow2x=5-3=2\)

\(\Leftrightarrow x=2:2=1\)

Vậy: x=1

b) \(\left(2x-3\right)^2=9\)\(=3^2=\left(-3\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\left(3+3\right):2=3\\x=\left(-3+3\right):2=0\end{matrix}\right.\)

Vậy: \(x\in\left\{3;0\right\}\)

c) \(3x+4=2x-7\)

\(\Leftrightarrow2x-3x=7+4\)

\(\Leftrightarrow-1x=11\)

\(\Leftrightarrow x=-11\)

Vậy: x=-11

d) \(\left(4x-1\right)^3=27\)\(=3^3\)

\(\Rightarrow4x-1=3\)

\(\Leftrightarrow4x=3+1=4\)

\(\Leftrightarrow x=4:4=1\)

Vậy: x=1

e) \(\left(x-7\right).2=3.\left(2x+4\right)\)

\(\Leftrightarrow2x-14=6x+12\)

\(\Leftrightarrow2x-6x=12+14\)

\(\Leftrightarrow-4x=26\)

\(\Leftrightarrow x=\frac{26}{-4}=\frac{13}{-2}\)

Vậy: \(x=\frac{13}{-2}\)

Giải như sau.

(1)+(2)⇔x2−2x+1+√x2−2x+5=y2+√y2+4⇔(x2−2x+5)+√x2−2x+5=y2+4+√y2+4⇔√y2+4=√x2−2x+5⇒x=3y(1)+(2)⇔x2−2x+1+x2−2x+5=y2+y2+4⇔(x2−2x+5)+x2−2x+5=y2+4+y2+4⇔y2+4=x2−2x+5⇒x=3y

⇔√y2+4=√x2−2x+5⇔y2+4=x2−2x+5, chỗ này do hàm số f(x)=t2+tf(x)=t2+t đồng biến ∀t≥0∀t≥0
Công việc còn lại là của bạn ! 

\(\left(x+6\right)\left(2x+1\right)=0\)

<=>  \(\orbr{\begin{cases}x+6=0\\2x+1=0\end{cases}}\)

<=>  \(\orbr{\begin{cases}x=-6\\x=-\frac{1}{2}\end{cases}}\)

Vậy....

hk tốt

^^

a) 12 ( 2x - 6 ) - 43= 5³

12 ( 2x - 6 ) - 43= 125

12 ( 2x - 6 ) =125+43

12 ( 2x - 6 ) =168

2x - 6=168:12

2x - 6=14

2x=14+6

2x=20

x=20:2

x=10

b) 7 ( 25 - 3x ) = 3⁴ - 2⁵

 7 ( 25 - 3x ) = 49

25 - 3x =49:7

25 - 3x =7

3x=25-7

3x=18

x=18:3

x=6

c) ( 3x - 5 ) + 3⁴ + 6⁰ = 5³

( 3x - 5 ) + 81 + 1 = 125

( 3x - 5 ) + 81=125-1

( 3x - 5 ) + 81=124

3x - 5=124-81

3x - 5=43

3x=43+5

3x=48

x=48:3

x=16

d) 3x + 2x ( 2³ . 5 - 3² . 4 ) + 5² = 4⁴

3x + 2x ( 8 . 5 - 9 . 4 ) + 25 = 256

3x + 2x.4 + 25 = 256

3x + 2x.4=256-25

3x + 2x.4=231

(3+2).x.4=231

5x.4=231

5x=231:4

5x=57,75

x=57,75:5

x=11,55

e) 720 : [ 41 - (2x - 5 ) ] = 2³ .5

720 : [ 41 - ( 2x - 5 ) ] =40

41 - ( 2x - 5 )=720:40

41 - ( 2x - 5 )=18

 2x - 5=41-18

 2x - 5=23

2x=23+5

2x=28

x=28:2

x=14

a, 36:(x–5) =  2 2

(x–5) = 9

x = 14

b, [3.(70–x)+5]:2 = 46

[3.(70–x)+5] = 92

70–x = 29

x = 41

c, 450:[41–(2x–5)] =  3 2 .5

41–(2x–5) = 10

2x–5 = 31

2x = 36

x = 18

d, 230+[ 2 4 +(x–5)] = 315. 2018 0

16+(x–5) = 315–230

x–5 = 85–16

x = 69+5

x = 74

e,  2 x + 2 x + 1  = 48

2 x .(2+1) = 48

2 x = 16 =  2 4

x = 4

f,  3 x + 2 + 3 x  = 2430

3 x . 3 2 + 1 = 2430

3 x = 2430:10 = 243 =  3 5

x = 5

a: =>41-(2x-5)=720:40=18

=>2x-5=23

=>2x=28

=>x=14

b: =>100x+5050=5750

=>100x=700

=>x=7

a: =>41-(2x-5)=720:40=18

=>2x-5=23

=>2x=28

=>x=14

b: =>100x+5050=5750

=>100x=700

=>x=7