Ta có

a,    x²-x-y²-y

=x²-y²-(x+y)

=(x-y)(x+y) - (x+y)

=(x+y)(x-y-1)

b,   x²-2xy+y²-z²

=(x-y)²-z²

=(x-y-z)(x-y+z)

con bai 32, 33 neu ban tra loi duoc minh h them

nhanh nha

\(=\left(x^2+x\right)^2+3\left(x^2+x\right)+2-12\)

\(=\left(x^2+x\right)^2+3\left(x^2+x\right)-10\)

\(=\left(x^2+x+5\right)\left(x^2+x-2\right)\)

\(=\left(x^2+x+5\right)\left(x+2\right)\left(x-1\right)\)

x^2 + 7x -15

= x^2 + 7x +12,25  -27,25

= (x+3,5)^2 - 27, 25

= ( x+3,5 - \(\sqrt{27,25}\))(x+3,5+\(\sqrt{27,25}\))

4x² - 36x + 56

= 4x² - 28x - 8x + 56

= ( 4x² - 28x ) - ( 8x - 56 )

= 4x( x - 7 ) - 8( x - 7 )

= ( x - 7 )( 4x - 8 )

= 4( x - 7 )( x - 2 )

x^2-4+4xy-8y=x^2+4xy+4y^2-4y^2-8y-4=(x+2y)^2-(2y+2)^2=(x+2y-2y+2)(x+2y+2y-2)=(x+2)(x+4y-2)

\(=\left(3a-a^2\right)-\left(3b-ab\right)=\left(a-b\right)\left(3-a\right)\)

3a+3b-a²-ab

= 3a - a² + 3b - ab

= a( 3-a ) +b( 3- a)

= ( a+b)(3 - a )

3a + 3b - a² - ab

= 3a - a² + 3b - ab

= a( 3 - a ) + b( 3 - a )

= ( a + b )( 3 - a )

 4x^4 - 32x^2 +1 = 4x^4 + 4x^2 +1 - 36x^2 = (2x^2 + 1)^2 - 36x^2 = (2x^2 - 6x + 1)(2x^2 + 6x + 1) 

4 x⁴ - 32 x² + 1 

= ( 2 x² )² - 2 . 2x². 8 + 64 - 63 

= ( 2 x² - 8 )² - 63 

= ( 2x² - 8 + √63 ) ( 2x² - 8 - √63 )

Xong

=4x²-y²+8y-16

=4x²-(y² - 8y+16)

=4x²-(y-4)²

=(2x+y-4)(2x-y+4)

   4x²-y²+8(y-2)

=4x²-y²+8.y-8.2

=4x²-y²+8y-16

\(1-3x-x^3+3x^2\)\(=\left(1-x^3\right)+\left(3x^2-3x\right)\)

\(=\left(1-x\right)\left(x^2+x+1\right)+3x\left(x-1\right)\)

\(=\left(x-1\right)\left(3x-x^2-x-1\right)=\left(x-1\right)\left(2x-x^2-1\right)\)