3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + .... + 2015.2016.2017

3A=2015.2016.2017

A=\(\frac{2015.2016.2017}{3}=.........................\)

A=1.2+2.3+3.4+......+2015.2016

=>3A=1.2.3+2.3.3+3.4.3+....+2015.2016.3

=>3A=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+.....+2015.2016.(2017-2014)

=>3A=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+.....+2015.2016.2017-2014.2015.2016

=>3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+......+2015.2016.2017-2014.2015.2016

=>3A=2015.2016.2017

=>\(A=\frac{2015.2016.2017}{3}=2731179360\)

2731179360 k mk , mk k lại

gọi tổng là S ta có

3S=1.2.3-0.1.2+2.3.4-1.2.3+......+99.100.101-98.99.100

=>3S=98.99.100

=>S=\(\frac{98.99.100}{3}=323400\)

333300

A = 1.2 + 2.3 + 3.4 + ....... + 99.100

3A = 1.2.3 + 2.3.3 + 3.4.3 + ....... + 99 . 100 . 3

3A = 1.2.3 + 2.3.(4-1) + 3.4.(5-2)  +.... + 99.100.(101-98)

3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ..... + 99 . 100 . 101 - 98 . 99 . 100

3A = (1.2.3 - 1.2.3) + (2.3.4-2.3.4) + ... + (98.99.100 - 98.99.100) + 99  . 100 . 101

3A = 99 . 100 . 101 = 999900

A = 999900 : 3 = 333300

A=1*2+2*3+3*4+...+99*100

A=100*101*102:3

A=343400(công thức)

http://olm.vn/hoi-dap/question/96300.html

Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
 3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101  3S = 3.33.100.101 
 S=33.100.101= 333300

Đặt

S= 1.2 + 2.3 + 3.4 + ...+ 99.100  

3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3

3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)

3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100

3S = 99.100.101  3S = 3.33.100.101  

S=33.100.101= 333300

M = 1.2 + 2.3 + 3.4 + 4.5 + 5.6 + ..... + 2002.2003

3.M = 1.2.3 + 2.3.3 + 3.4.3 + 4.5.3 + 5.6.3 + ..... + 2002.2003.3

3.M = 1.2.3 +  2.3. ( 4 - 1 ) + 3.4. ( 5 - 2 ) + 4.5. ( 6 - 3 ) + 5.6. ( 7 - 4 ) + ......... + 2002.2003. ( 2004 - 2001 )

3.M = 1.2.3 + 2.3.4 -1.2.3 + 3.4.5 - 2.3.4 + 4.5.6 - 3.4.5 + 5.6.7 - 4.5.6 + ...... + 2002.2003.2004 - 2001.2002.2003

3.M = 2002.2003.2004

Vậy M = 2002.2003.2004 : 3

M = 2678684008

Dùng công thức \(\frac{n.\left(n+1\right).\left(n+2\right)}{3}\) là ra nha bạn 
Tức \(\frac{2002.2003.2004}{3}=2678684008\)

A = 1.2+2.3+3.4+......+99.100 
Gấp A lên 3 lần ta có: 
A . 3 = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3 
A . 3 = 1.2.3 + 2.3.(4 - 1) + 3.4.( 5 - 2) + … + 99.100. (101 - 98) 
A . 3 = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … + 99.100.101 - 98.99.100 
A . 3 = 99.100.101 
A = 99.100.101 : 3 
A = 33.100.101 
A = 333 300

Đặt A = 1.2 + 2.3 + 3.4 + ..... + 2008.2009

<=> 3A = 1.2.3 + 2.3.3 + 3.4.3 + .... + 2008.2009.3

<=> 3A = 1.2.3 + 2.3.( 4 - 1 ) + 3.4.( 5 - 2 ) + ...... + 2008.2009.( 2010 - 2007 )

<=> 3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + .... + 2008.2009.2010 - 2007.2008.2009

<=> 3A = 2008.2009.2010

=> A = ( 2008.2009.2010 ) : 3

=132546879

kho

A=49,5

\(A=1.2+2.3+3.4+...+9.10\)

\(3A=1.2.3+2.3.3+3.4.3+...+9.10.3\)

\(=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+9.10.\left(11-8\right)\)

\(=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5+...-8.9.10+9.10.11\)

\(=9.10.11\)

\(\Rightarrow A=\frac{9.10.11}{3}=330\)

A = 1.2 + 2.3 + 3.4 + 4.5 + ... + 99.100 + 100.101

3.A = 1.2.3 + 2.3.3 +3.4.3 + ... + 100.101.3

3A= 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 100.101.(102 - 99)

3A = 1.2.3 + 2.3.4 - 1.2.3 + 2.3.4 -3.4.5 + ... +99.100.101 -100.101.102

3A = 99.100.101

A = 99.100.101 : 3

A = 33.100.101

Vậy A = 33. 100 .101 (Tự tính)

A=1.2+2.3+3.4+.....+99.100+100.101

333300