96 - 3(x + 1) = 42

<=> 96 - 3x - 3 = 42

<=> 96 - 3 - 42 = 3x

<=> 3x = 51

<=> x = 17

\(96-3\left(x+1\right)=42\)

\(3\left(x+1\right)=96-42=54\)

\(x+1=54:3=18\)

\(x=18-1=17\)

Sửa đề: 3/91*96

\(B=\dfrac{3}{1\cdot6}+\dfrac{3}{6\cdot11}+...+\dfrac{3}{91\cdot96}\)

=3/5(5/1*6+5/6*11+...+5/91*96)

=3/5(1-1/6+1/6-1/11+...+1/91-1/96)

=3/5*95/96=57/96=19/32

Đề sai rồi bạn

đề sai rồi bạn ơi 

đề sai rồi bạn ơi

a) 2.(x-1)=4/3

<=> (X-1)= 4/3 :2 = 2/3

<=> X= 2/3+1=5/3

b) (x-1)^2= 4

<=> X-1=2 hoặc x-1=-2

<=> X= 3 hoặc x= -1

c) 2.|x+1|=3

<=> Ix+1| = 3/2

<=> X+1= 3/2 hoặc x+1= -3/2

<=> X= 1/2 hoặc x= -5/2

a) Ta có: \(2\left(x-1\right)=\dfrac{4}{3}\)

\(\Leftrightarrow x-1=\dfrac{4}{3}:2=\dfrac{4}{6}=\dfrac{2}{3}\)

hay \(x=\dfrac{5}{3}\)

Vậy: \(x=\dfrac{5}{3}\)

b) Ta có: \(\left(x-1\right)^2=4\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

Vậy: \(x\in\left\{3;-1\right\}\)

a) 2.(x-1)=4/3

<=> (X-1)= 4/3 :2 = 2/3

<=> X= 2/3+1=5/3

b) (x-1)^2= 4

=> X-1=2 hoặc x-1=-2

=> X= 3 hoặc x= -1

c) 2.|x+1|=3

=> Ix+1| = 3/2

=> X+1= 3/2 hoặc x+1= -3/2

=> X= 1/2 hoặc x= -5/2

96 - 3(x+1)= 42

3(x+1) = 96 - 42 = 54

x + 1 = 54 : 3 = 18

x = 18 - 1 = 17

x=18-1=17

96-3.(x+1)=4²

96-3.(x+1)=16

93   .(x+1)=16

        (x+1)= 93-16

        (x+1)=77

         x      = 77-1

         x     =  76

c)96 - 3.(x + 1) = 42

3.(x + 1)= 96 - 42

3.(x + 1) = 54

x + 1= 54:3

x + 1= 18

x = 18 - 1

x = 17

Hzh

96-3(x+1)=42

3(x+1)=96-42

3(x+1)=54

x+1 = 54 : 3

x+1 = 18

 x   = 18 - 1

 x   = 17

96 - 3(x + 1) = 42

\(\Rightarrow\)3x + 3 = 54

\(\Rightarrow\)3x = 51

\(\Rightarrow\)x = 17