( 64 - 2.x ) . ( 3.x - 153 ) = 0
2x . 4 = 128
Tìm x thuộc N
( 64 - 2.x ) . ( 3.x - 153 ) = 0
2x . 4 = 128
Tìm số tự nhiên x
231-(x-8)=1339:13
(64.2.x)(3.x-153)=0
2x.4=128
(X-2) mũ 2 = 9.16
X15=x
(2x1) mũ 2 = 25
Giúo nhanh m tịckkk
Tìmx,y biết x^2-25=0 b, (x+1)^2=4 c, (x-3)^3-64=0 d, 2^x+1-128=0 e, x^2 +(y-2)^2=0
a: =>(x-5)(x+5)=0
=>x=5 hoặc x=-5
b: \(\Leftrightarrow\left[{}\begin{matrix}x+1=2\\x+1=-2\end{matrix}\right.\Leftrightarrow x\in\left\{1;-3\right\}\)
c: =>x-3=4
hay x=7
d: =>x+1=7
hay x=6
e: =>x=0 và y-2=0
hay x=0 và y=2
( 64 - 2.x ) . ( 3.x - 153 ) =0
tìm x thuộc số tự nhiên
a)2 mũ x=16 , 2 mũ x =128
b)3 mũ x =27 , 3 mũ x =81
c)4 mũ x=64
d)5 mũ 2x=625
e)6 mũ 2x +1=216
\(2^x=16\Leftrightarrow2^x=2^4\Leftrightarrow x=4\)
\(2^x=128\Leftrightarrow2^x=2^7\Leftrightarrow x=7\)
b), c) tương tự
d) \(5^{2x}=625\Leftrightarrow5^{2x}=5^4\Leftrightarrow2x=4\Leftrightarrow x=2\)
e) tương tự d
Tìm x
a. 2x^3+3x^2-2x-3=0
b. 3x(x-1)+7x^2(x-1)=0
c. x(x+4)×(x+6)×(x+10)+128=0
b, <=> (x-1)(3x+7x^2)=0
<=> x(x-1)(7x+3)=0
<=> x=0;x=1;x=-3/7
a, 2x^3+3x^2-2x-3=0
<=> 2x^3-2x^2+5x^2-5x+3x-3=0
<=> 2x^2(x-1)+5x(x-1)+3(x-1)=0
<=> (x-1)(2x^2+5x+3)=0
<=> (x-1)(2x^2+2x+3x+3)=0
<=> (x-1)[2x(x+1)+3(x+1)]=0
<=> (x-1)(x+1)(2x+3)=0
<=>x=1;x=-1;x=-3/2
<=>
a)2x – 12.4 = 28
b)128-3(x +4)= 23
c) 20 + 8.(x + 3) = 52 .4
d) (12x -4 3 ).83= 4.84
e) 720: [41-(2x-5)]=23 .5
f) (2x- 4)(x – 3) = 0
g) (2x +1)3= 5.25
h) 2 x . 4 = 128
i) 5x-2 = 1
k)2x + 2x + 3= 144
giúp me được ko
1.Tìm x biết
a,2^x=128 b,8^x-1=64
c,3+3^x=30 d,(x+2)=64
e,3^2.x=3^5 f,(2x-1^3)=343
Giải nhanh giúp mik vs mik sắp đi hc r ai nhanh mik tick cho
1.
a) \(2^x=128\)
\(2^x=2^7\)
\(=>x=7\)
b) \(8^{x-1}=64\)
\(8^{x-1}=8^2\)
\(=>x-1=2\)
\(x=2+1\)
\(=>x=3\)
c) \(3+3^x=30\)
\(3^x=30-3\)
\(3^x=27=3^3\)
\(=>x=3\)
d) \(\left(x+2\right)=64\) -> đề có thiếu không vậy?
e) \(3^2.x=3^5\)
\(x=3^5:3^2\)
\(=>x=3^3=27\)
f) \(\left(2x-1\right)^3=343\)
\(\left(2x-1\right)^3=7^3\)
\(=>2x-1=7\)
\(2x=7+1\)
\(2x=8\)
\(x=8:2\)
\(=>x=4\)
\(#Wendy.Dang\)
a,\(2^x\)=128 b,\(8^{x-1}\)=64 c,3+\(3^x\)=30 d,x+2=64
\(2^7\)=128 \(8^{x-1}\)=\(8^2\) \(3^x\)=30-3 x=64-2
=>x=7 =>x-1=2 \(3^x\)=27 x=62
x=2+1=3 \(3^x\)=\(3^3\)
=>x=3
e,\(3^2\).x=\(3^5\) f,(2x-\(1^3\))=343
x=\(3^5\):\(3^2\) 2x=1+343
x=27 2x=344
x=344:2
x=172
Tìm x:
a) 2x - 7 x 4 = 1283
b) ( 2x + 1 )3 x 27 = 2432 - 33
c) 2x + 2 + 2x+8 = 65 x 64