a/ \(\frac{x}{2}+\frac{x}{3}+\frac{x}{4}=180\)

\(\Leftrightarrow x\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)=180\)

\(\Leftrightarrow\frac{13}{12}x=180\)

\(\Leftrightarrow x=\frac{2160}{13}\)

b/ \(\frac{1}{x.2}+\frac{2}{x.3}+\frac{3}{x.4}=120\)

\(\Leftrightarrow\frac{1}{x}\left(\frac{1}{2}+\frac{2}{3}+\frac{3}{4}\right)=120\)

\(\Leftrightarrow\frac{1}{x}.\frac{23}{12}=120\)

\(\Leftrightarrow\frac{1}{x}=\frac{1440}{23}\)

\(\Leftrightarrow x=\frac{23}{1440}\)

ý b của mik là 23/12

mình đag rất cần gấp

a,1/4

b,8

a, 1/4
b,8

a) x=1/4

b) -12

c) 50

d)Vậy x e thuộc {-3, -2, -1}

# Tính lũy thừa
a = 3
n = 2
power = a ** n
print(power)  # Kết quả: 9

# Tính giai thừa
n = 5
factorial = 1
for i in range(1, n+1):
    factorial *= i
print(factorial)  # Kết quả: 120

(10 - 4.x) + 120 : 8 = 5 mũ 2

 (10-4.x) +120 : 8 = 25

 (10-4.x)+120 = 25.8

(10-4.x)=200

4.x=200+10

x=210:4

x=52,5

sai rồi bạn ơi

(10-4.x) + 120 : 2 mũ 3 = 1+4 mũ 2

<=> (10-4.x) + 120 : 8 = 5 mũ 2

<=> ( 10-4.x) + 120 :8 = 25 

<=> (10-4.x ) + 15 = 25

<=> (10-4.x) + 15 = 25

<=> 10-4.x = 25-15

<=> 10-4.x =10

<=> 4.x = 10-10

<=> 4.x=0

x = 0 :4

x= 0

Vậy x=0

Mình học lớp 6 nhé , làm quen đc ko , tớ ở BG

1) \(\dfrac{120\left(x-10\right)}{x\left(x-10\right)}-\dfrac{120x}{x\left(x-10\right)}=1\)

=> \(\dfrac{120x-1200-120x}{x\left(x-10\right)}=1\)

=> x(x-10)=-1200

=> x²-10x+1200=0

=> (x²-10x+25)+1175=0

=> (x-5)²+1175>0

=> pt vo nghiem

\(\dfrac{1}{120}\cdot120+x:\dfrac{1}{3}=-4\)

\(\Leftrightarrow1+x\cdot3=-4\)

\(\Leftrightarrow3x=-5\)

\(\Leftrightarrow x=-\dfrac{5}{3}\)

\(\dfrac{1}{120}.120+x:\dfrac{1}{3}=-4\) 

            \(1+x:\dfrac{1}{3}=-4\) 

                  \(x:\dfrac{1}{3}=-4-1\) 

                  \(x:\dfrac{1}{3}=-5\) 

                        \(x=-5.\dfrac{1}{3}\) 

                        \(x=\dfrac{-5}{3}\)

\(=\left(x^2+5x+4\right)\left(x^2+5x+6\right)-120\)

\(=\left(x^2+5x\right)^2+10\left(x^2+5x\right)-96\)

\(=\left(x^2+5x+16\right)\left(x^2+5x-6\right)\)

\(=\left(x^2+5x+16\right)\left(x+6\right)\left(x-1\right)\)

Ta có: 

10 - 4x + 120:2³ = 1 + 4²

=> 10 - 4x + 15 = 1 + 16

=> 4x - 5 = 17

=> 4x = 17 + 5 = 22

=> x = 22/4

Vậy: x = 22/4

\(\left(10-4x\right)+120:2^3=1+4^2\)

\(\Rightarrow\left(10-4x\right)+120:8=1+16\)

\(\Rightarrow\left(10-4x\right)+15=17\)

\(\Rightarrow\left(10-4x\right)=17-15=2\)

\(\Rightarrow4x=10-2=8\)

\(\Rightarrow x=8:4=2\)

(10-4.x)+120:2³=1+4²

(10-4.x)+15=17

10-4.x=17-5

10-4.x=2

4.x=10-2

4.x=8

x=8:4

x=2