Ta có : A= x^0+ x^1+ x^2+...+x^n => \(A=\frac{x^{n+1}-1}{x-1}\)

Chứng minh: xA=x¹+x²+...+x^ⁿ⁺¹

xA-A=A(x-1)=xⁿ⁺¹-x⁰=xⁿ⁺¹-1

Từ đó => điều trên

Vậy Ta có:

\(S=\frac{\left(-\frac{1}{7}\right)^{2017}-1}{-\frac{1}{7}-1}\)

S= -(1/7^0 + 1/7^1+ 1/7^2 + 1/7^3 +...+ 1/7^2016)

Xét A = 1/7^0 + 1/7^1 + 1/7^2 + 1/7^3 +...+ 1/7^2016

     =>7A= 7 + 1/7^0 + 1/7^1 + ...+ 1/7^2015   

=> 6A = 7 - 1/7^2016

=>  A  = (7 - 1/7^2016)/6

=>S=-(7-1/7^2016)/6

mk ko chép đề đâu nha

\(S=1+\dfrac{-1}{7}+\dfrac{1}{7^2}+...+\dfrac{1}{7^{2016}}\)

đặt \(7S=7-1+\dfrac{1}{7}+...+\dfrac{1}{7^{2015}}\)

=>\(7S+S=\left(7-1+\dfrac{1}{7}+...+\dfrac{1}{7^{2015}}\right)+\left(1-\dfrac{1}{7}+\dfrac{1}{7^2}+...+\dfrac{1}{7^{2016}}\right)\)

=>\(8S=7-1+\dfrac{1}{7}+...+\dfrac{1}{7^{2015}}+1-\dfrac{1}{7}+\dfrac{1}{7^2}+...+\dfrac{1}{7^{2016}}\)

=>\(8S=7+\left(-1+1\right)+\left(\dfrac{1}{7}-\dfrac{1}{7}\right)+...+\left(\dfrac{1}{7^{2015}}-\dfrac{1}{7^{2015}}\right)+\dfrac{1}{7^{2016}}\)

=> \(8S=7+\dfrac{1}{7^{2016}}\)

\(\Rightarrow S=\dfrac{7+\dfrac{1}{7^{2016}}}{8}\)

Gỉa sử : \(-\dfrac{1}{7}=a\)

Thay vào S ,có :

\(a^0+a^1+a^{2^{ }}+.........+a^{2016}\) (1)

=> a.S = a( \(a^0+a^1+a^{2^{ }}+.........+a^{2016}\) )

= \(a^1+a^2+a^3+.........+a^{2016}+a^{2017}\) (2)

Lấy (2) - (1) ,CÓ :

aS-S = a²⁰¹⁷ -1 => S(a-1) = a²⁰¹⁷ -1

=> S = \(\dfrac{a^{2017}-1}{a-1}\)

Thay a= -1/7 vào S = \(\dfrac{a^{2017}-1}{a-1}\) ,có :

S = \(\dfrac{\left(\dfrac{-1}{7}\right)^{2017}-1}{-\dfrac{1}{7}-1}=\dfrac{\left(-\dfrac{1}{7}\right)^{2017}}{-\dfrac{8}{7}}\)

Ta có: \(S=\left(-\dfrac{1}{7}\right)^0+\left(-\dfrac{1}{7}\right)^1+\left(-\dfrac{1}{7}\right)^2+...+\left(-\dfrac{1}{7}\right)^{2014}\)

\(\Leftrightarrow\dfrac{-1}{7}\cdot S=\left(-\dfrac{1}{7}\right)^1+\left(-\dfrac{1}{7}\right)^2+\left(-\dfrac{1}{7}\right)^3+...+\left(-\dfrac{1}{7}\right)^{2015}\)

\(\Leftrightarrow S-\dfrac{-1}{7}\cdot S=\left(-\dfrac{1}{7}\right)^0-\left(-\dfrac{1}{7}\right)^{2015}\)

\(\Leftrightarrow\dfrac{8}{7}\cdot S=1+\dfrac{1}{7^{2015}}\)

\(\Leftrightarrow S=\left(1+\dfrac{1}{7^{2015}}\right):\dfrac{8}{7}=\dfrac{\left(1+\dfrac{1}{7^{2015}}\right)\cdot7}{8}\)

Cười cái gì mà cười

7S=7+7^2+7^3+7^4+...+7^2016

=>7S-S=(7+7^2+7^3+7^4+...+7^2016)-(1+7+7^2+7^3+...+7^2015)

=>6S=7^2016-1

=>6S+1=7^2016-1+1=7^2016(đpcm)