Từ GT ; ta có :  \(\left(x-1\right)\left(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}\right)=224\)

\(\Rightarrow\left(x-1\right)\left(\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{7.8}+\dfrac{1}{8.9}\right)=224\)

\(\Rightarrow\left(x-1\right)\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}\right)=224\)

\(\Rightarrow\left(x-1\right)\left(\dfrac{1}{3}-\dfrac{1}{9}\right)=224\)

\(\Rightarrow\left(x-1\right).\dfrac{2}{9}=224\)

\(\Rightarrow\left(x-1\right)=1008\)

\(\Rightarrow x=1009\)

Vậy ... 

Gọi biểu thức đó là A

\(A=\dfrac{1}{x}.\left(\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+..+\dfrac{1}{49.50}\right)=1\)

\(\Rightarrow A=\dfrac{1}{x}.\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{49.50}\right)=1\)

Ta có công thức : \(\dfrac{a}{b.c}=\dfrac{a}{c-b}.\left(\dfrac{1}{b}-\dfrac{1}{c}\right)\)

Dựa vào công thức trên ta có :

\(\dfrac{1}{2.3}=\dfrac{1}{2}-\dfrac{1}{3}\)

\(\dfrac{1}{3.4}=\dfrac{1}{3}-\dfrac{1}{4}\)

......................

\(\dfrac{1}{49.50}=\dfrac{1}{49}-\dfrac{1}{50}\)

\(\Rightarrow A=\dfrac{1}{x}.\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+.....+\dfrac{1}{49}-\dfrac{1}{50}\right)=1\)

\(\Rightarrow A=\dfrac{1}{x}.\left(\dfrac{1}{2}-\dfrac{1}{50}\right)=1\)

\(\Leftrightarrow A=\dfrac{1}{x}.\left(\dfrac{12}{25}\right)=1\)

\(\Rightarrow\) \(\dfrac{1}{x}=A:\dfrac{12}{25}=1:\dfrac{12}{25}=\dfrac{25}{12}\)

Vậy x = 12.

Mink nghĩ vậy, ai thấy đúng thì ủng hộ mink nha !!!

Phân tích phân số ra 

Mình Đi học đã gợi ý đó

A = 1/90 - 1/72 - 1/56 - 1/42 - 1/30 - 1/20 - 1/12 - 1/6 - 1/2

A = 1/90 - ( 1/72 + 1/56 + 1/42 + 1/30 + 1/20 + 1/12 + 1/6 + 1/2)

A = 1/90 - ( 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72)

A = 1/90 - ( 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9)

A = 1/90 - ( 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/8 - 1/9)

A = 1/90 - ( 1 - 1/9)

 A = 1/90 - 8/9

A = 1/90 - 80/90 = -79/90

A=1/90-1/72-1/56-1/42-1/30-1/20-1/12-1/6-1/2

A=1/90-(1/72+1/56+1/42+1/30+1/20+1/12+1/6+1/2)

A=1/90-(1-1/9)

A=1/90-8/9=1/90-80/90=-79/90

ta có

x-1/12+x-1/20+x-1/30+x-1/42+x-1/56+x-1/72=16/9

=>x-1(1/12+1/20+1/30+1/42+1/56+1/72)=16/9

=>x-1(1/3*4+1/4*5+1/5*6+1/6*7+1/7*8+1/8*9)=16/9

=>x-1(1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9)=16/9

=>x-1*(1/3-1/9)=16/9

=>(x-1)*2/9=16/9

=>x-1=9

=>x=8

kb và like cho mình nhé

này hà nhi đề ni dễ rữa mà ko bt

\(\dfrac{23}{9}\)

em lớp 6  nha

B= 1/2 + 1/6 + 1/12 +1/20 + 1/30 + 1/42 + 1/56 + 1/72

B= 1/1*2 + 1/2*3 + 1/3*4 + 1/4*5 + 1/5*6 + 1/6*7 + 1/7*8 + 1/8*9

B=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9

B=1+0-0-0-0-0-0-0-1/9

B=1-1/9

B=8/9

k em nha

phần A em chịu

còn câu dưới đó e

b)575- [(-6)x+70]=445

-6x+70=575-445=130

-6x=130-70=60

x= 60:(-6)

x=-10

Vậy x=-10

c)

315+(125-x)=435

125-x= 435-315= 120

x=125-120

x=5

Vậy x= 5

\(\frac{20}{9}-x=\frac{1}{12}+\frac{1}{20}+.........+\frac{1}{72}\)

\(\Rightarrow\frac{20}{9}-x=\frac{1}{3.4}+\frac{1}{4.5}+.......+\frac{1}{8.9}\)

\(\Rightarrow\frac{20}{9}-x=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+........+\frac{1}{8}-\frac{1}{9}\)

\(\Rightarrow\frac{20}{9}-x=\frac{1}{3}-\frac{1}{9}\)

\(\Rightarrow\frac{20}{9}-x=\frac{2}{9}\)

\(\Rightarrow x=\frac{20}{9}-\frac{2}{9}\)

\(\Rightarrow x=\frac{18}{9}=2\)

20/9 -x= 1/3.4 +1/4.5+1/5.6+ 1/6.7+1/7.8+1/8.9
          =1/3+1/4+1/4+1/5+1/5+1/6+1/6+1/7+1/7+1/8+1/8+1/9+1/9
   20/9 -x= 1/3
          x=20/9-1/3
          x= 17/9
Nhớ tích (đúng) cho mình nha

20/9-x=1/12+1/20+1/30+1/42+1/56+1/72 

20/9-x=1/3.4+1/4.5+1/5.6+.............+1/8.9

20/9-x=1/3-1/4+1/4-1/5+................+1/8-1/9

20/9-x=1/3-1/9

20/9-x=2/9

       x=20/9-2/9

       x=18/9

Chọn (k) đúng cho mình nha !!!!!!!!!!!

\(\frac{20}{9}x=\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\)

\(\frac{20}{9}x=\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)

\(\frac{20}{9}x=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-.....-\frac{1}{9}\)

\(\frac{20}{9}x=\frac{1}{3}-\frac{1}{9}=\frac{2}{9}\)

\(x=\frac{2}{9}:\frac{20}{9}=\frac{1}{10}\)

20/9 . x = 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72

20/9 . x = 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9

20/9 . x = 1/3 - 1/4 + 1/4 - 1/5 + ... + 1/8 - 1/9

20/9 . x  = 1/3 - 1/9 = 2/9

x = 2/9 : 20/9 = 2/9 . 9/20 = 1/10

Vậy x = 1/10