\(F=\frac{\left(\frac{53}{4}-2\frac{5}{27}-\frac{65}{6}\right).\left(230+\frac{1}{25}\right)+46\frac{3}{4}}{\left(\frac{24}{7}+3\frac{1}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)

giúp mình nhé các bạn

\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)

Giúp mình với, mình đang cần gấp lắm nhé các bạn!

A= \(\frac{\left(81,624:\frac{16}{3}-4,505\right)^2+125.\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:\frac{13}{25}}\)        B= \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)

\(\frac{\left(81,624:4\frac{4}{3}-4,505\right)^2+125\frac{3}{4}}{\left(\left(\left(\frac{11}{25}\right)^2:0,88+3,53\right)^2-\left(2,75\right)^2\right):\frac{13}{25}}\)

\(\frac{\left(81,624:4\frac{4}{3}-4,505\right)+125\frac{3}{4}}{\left(\left(\left(\frac{11}{25}\right)^2:0,08+3,53\right)^2-\left(2,75^2\right)\right):\frac{13}{25}}\)

\(B=\dfrac{\left(81,624:4\dfrac{4}{3}-4,505\right)^2+125\dfrac{3}{4}}{\left\{\left[\left(\dfrac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}.\dfrac{13}{25}}\)

\(B=\frac{\left(81,624:4\frac{4}{3}-4,505\right)^2+125\frac{3}{4}}{\left\{\left[\left(\frac{11}{25}\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}.\frac{13}{25}}\)

Chứng minh rằng:

a)\(12^8.9^{12}=18^{16}\)

b)\(\frac{\left(5^4-5^3\right)^3}{125^5}=\frac{64}{25^5}\)

c)\(\frac{9^3}{\left(3^4-3^3\right)^2}=\frac{1}{4}\)

Làm nhanh giúp mình nhá. Thanks. ^_^

Tính \(C=\left(\frac{1}{125}-\frac{1}{1^3}\right)\left(\frac{1}{125}-\frac{1}{2^3}\right)\left(\frac{1}{125}-\frac{1}{3^3}\right)...\left(\frac{1}{125}-\frac{1}{25^3}\right)\)

tính hợp lí

\(\left[\left(25\frac{12}{67}+9\frac{13}{41}\right)_{ }-\left(8\frac{12}{67}-3\frac{28}{41}\right)\right]X\frac{21}{-13}\)

làm ơn giúp mk nhanh nhé mai mk đi học rồi