(-39)4:134
(0,125)3.83
Những câu hỏi liên quan
1. Tìm y :
Y x 7:5 + 4x 8 = 134
2. Tính nhanh
\(\dfrac{1}{4}\): 0,25 - \(\dfrac{1}{8}\) : 0,125 + \(\dfrac{1}{2}\) : 0,5 -\(\dfrac{1}{10}\)
1)\(y\times7:5+4\times8=134\)
\(\Leftrightarrow y\times7:5+32=134\)
\(\Leftrightarrow y\times7:5=102\)
\(\Leftrightarrow y\times7=510\)
\(\Leftrightarrow y=72,86\)
2) \(\dfrac{1}{4}:0,25-\dfrac{1}{8}:0,125+\dfrac{1}{2}:0,5-\dfrac{1}{10}\)
\(=0,25:0,25-0,125:0,125+0,5:0,5-\dfrac{1}{10}\)
\(=1-1+1-\dfrac{1}{10}\)
\(=\dfrac{9}{10}\)
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a) (0,125)mũ 3. 8 mũ 3
b) (-39)mũ 4: 13 mũ 4
a) 0,1253.83
=(0,125.8)3
=13
=1.
b)(-39)4:134
=394:134
=(39:13)4
=34
=81
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a)0,1253 . 83 = (0,125 . 8)3 = 13 = 1
b) (-39)4 : 134 = ((-39 ): 13 )4 = 34 = 81
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?5:tinh
\(a,\left(0,125\right)^3.8^3\)
\(b,\left(-39\right)^4:13^4\)
a, (0,125.8)3 =13 =1
b. (-39 :13)4 = (-3)4 =81
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\(a,\left(0,125\right)^3.8^3\)
\(=\left(0,125.8\right)^3\)
\(=1^3\)
\(=1\)
\(b,\left(-39\right)^4:13^4\)
\(=\left(-39:13\right)^4\)
\(=-3^4\)
\(=81\)
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a (0,125)3.83
b (-39)4\(\div\)134
a,(0,125.8)3=13=1
b,(-39:13)4=(-3)4=81
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Cho A=1/1.21+1/1.22+1/3.23+...+1/80.100
B=1/1.81+1/2.82+1/3.83+...+1/20.100
Tính A/B
A=20/1.21+20/2.22+...+20/80.100
=1-1/21+1/2-1/22+...+1/80-1/100
=(1+1/2+...+1/80)-(1/21+1/22+...+1/100)
80B=80/1.81+80/2.82+...+8/20.100
=1-1/81+1/2-1/82+...+1/20-1/100
=(1+1/2+...+1/20)-(1/81+1/82+...+1/100)
=(1+1/2+1/3+...+1/20+1/21+1/22+...+1/80)-(1/21+1/22+...1/80+1/81+1/82+...1/100)
=>20A=80B
=>A=4B
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18 tháng 4 2022 lúc 14:54
Câu 24 : Cho A = 1.21 + 1/2.22 + 1/3.23 + ... + 1/80.100 ; B = 1/1.81 + 1/2.82 + 1/3.83 + ... + 1/20.100 . Tính A/B
(0,125+40%-3/40):[80/7+17/2(13/12-39/7)]
\(=\left(\dfrac{1}{8}+\dfrac{2}{5}-\dfrac{3}{40}\right):\left[\dfrac{80}{7}+\dfrac{17}{2}\cdot\dfrac{-877}{84}\right]\)
\(=\dfrac{5+16-3}{40}\cdot\dfrac{168}{-4489}=\dfrac{9}{20}\cdot\dfrac{-168}{4489}=\dfrac{-378}{22445}\)
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(-25) +(-58)-(-21)
tính nhanh
(-39)+67+(-19)+(-67)
b) 246-(357-246)
c)-111-(987-111)
d) (1234-4567)-(1234-67)
e) (134-388)-(12+134)
Cho \(A=\dfrac{1}{1.21}+\dfrac{1}{2.22}+\dfrac{1}{3.23}+...+\dfrac{1}{80.100}\);
\(B=\dfrac{1}{1.81}+\dfrac{1}{2.82}+\dfrac{1}{3.83}+...+\dfrac{1}{20.100}\).
Tính \(\dfrac{A}{B}\).
A=20/1.21+20/2.22+...+20/80.100
=1-1/21+1/2-1/22+...+1/80-1/100
=(1+1/2+...+1/80)-(1/21+1/22+...+1/100)
80B=80/1.81+80/2.82+...+8/20.100
=1-1/81+1/2-1/82+...+1/20-1/100
=(1+1/2+...+1/20)-(1/81+1/82+...+1/100)
=(1+1/2+1/3+...+1/20+1/21+1/22+...+1/80)-(1/21+1/22+...1/80+1/81+1/82+...1/100)
=>20A=80B
=>A=4B
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