Tìm x biết
a) |x + 4/3 | - |x - 5/2 | = 0
b, 1/6x+1/10x - 4/5x +1 = 0
1) TÌm x biết:
a) ( 1/7x - 2/7).(-1/5x + 3/5).(1/3x + 4/3) =0
b) 1/6x + 1/10x -4/15x +1 =0
b, \(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)
\(x\left(\frac{1}{6}+\frac{1}{10}-\frac{4}{15}\right)+1=0\)
\(x.0=-1\)
\(\Rightarrow x\in rỗng\)
Bài 3
1.(x-1)(x+2)+5x-5=0
2.(3x+5)(x-3)-6x-10=0
3.(x-2)(2x+3)-7x2+14x=0
4.(x+1)(x-3)-15+5x=0
5.5(2x-1)(x+3)+5x-10x2=0
Bài4
1.3x-6+(x+1)(x-2)=0
2.4x2+6x-(2x+3)(3x-x)=0
3.5x-10-(2-x)(4+x)=0
4.10-10x+(x-1)(x-3)=0
5.20x2+30x-2(x-5)(2x+3)=0
Bài 3:
1. \(\left(x-1\right)\left(x+2\right)+5x-5=0\)
\(\Rightarrow\left(x-1\right)\left(x+2\right)+5\left(x-1\right)=0\)
\(\Rightarrow\left(x-1\right)\left(x+2+5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-1=0\\x+7=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-7\end{matrix}\right.\)
Vậy.......................
2. \(\left(3x+5\right)\left(x-3\right)-6x-10=0\)
\(\Rightarrow\left(3x+5\right)\left(x-3\right)-2\left(3x+5\right)=0\)
\(\Rightarrow\left(3x+5\right)\left(x-3-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}3x+5=0\\x-5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\dfrac{5}{3}\\x=5\end{matrix}\right.\)
Vậy........................
3. \(\left(x-2\right)\left(2x+3\right)-7x^2+14x=0\)
\(\Rightarrow\left(x-2\right)\left(2x+3\right)-7x\left(x-2\right)=0\)
\(\Rightarrow\left(x-2\right)\left(2x+3-7x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-2=0\\-5x+3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{3}{5}\end{matrix}\right.\)
Vậy............................
4, 5 tương tự nhé bn!
bài 3
1 (x-1)(x+2)+5x-5=0
=>(x-1)(x+2)+(5x-5)=o
=>(x-1)(x+2)+5(x-1)=0
=>(x-1)(x+2+5)=0
=>(x-1)(x+7)=0
=>\(\left[{}\begin{matrix}x-1=0\\x+7=0\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=1\\x=-7\end{matrix}\right.\)
vậy x=1 hoặc x=-7
2. (3x+5)(x-3)-6x-10=0
=>(3x+5)(x-3)-(6x+10)=0
=>(3x+5)(x-3)-2(3x+5)=0
=>(3x+5)(x-3-2)=0
=>(3x+5)(x-5)=0
=>\(\left[{}\begin{matrix}3x+5=0\\x-5=0\end{matrix}\right.\)=>\(\left[{}\begin{matrix}x=-\dfrac{5}{3}\\x=5\end{matrix}\right.\)
a)1/6x + 1/10x - 4/15x + 1=0
b)(1/7x - 2/7)(-1/5x + 3/5)(1/3x + 4/3)=0
c)(x - 1/3)(y - 1/2)(z - 5)=0 và x + 2=y + 1=z + 3
a)\(\dfrac{1}{6}x+\dfrac{1}{10}x-\dfrac{4}{15}x+1=0\)
\(\left(\dfrac{1}{6}+\dfrac{1}{10}-\dfrac{4}{15}\right).x+1=0\)
\(\left(\dfrac{5}{30}+\dfrac{3}{30}-\dfrac{8}{30}\right).x+1=0\)
\(0.x+1=0\)
\(0.x=-1\)
=> Không có giá trị nào của x.
Vậy...
b)\(\left(\dfrac{1}{7}x-\dfrac{2}{7}\right).\left(-\dfrac{1}{5}x+\dfrac{3}{5}\right).\left(\dfrac{1}{3}x+\dfrac{4}{3}\right)=0\)
=> \(\dfrac{1}{7}x-\dfrac{2}{7}=0hoặc-\dfrac{1}{5}x+\dfrac{3}{5}=hoăc\dfrac{1}{3}x+\dfrac{4}{3}=0\)
+)\(~\dfrac{1}{7}x-\dfrac{2}{7}=0\) +) \(-\dfrac{1}{5}x+\dfrac{3}{5}=0\) +) \(\dfrac{1}{3}x+\dfrac{4}{3}=0\)
\(\dfrac{1}{7}x=-\dfrac{2}{7}\) \(-\dfrac{1}{5}x=-\dfrac{3}{5}\) \(\dfrac{1}{3}x=-\dfrac{4}{3}\)
\(x=2\) \(x=3\) \(x=-4\)
Vậy...
a 1/6x+1/10x-4/15x+1=0
(1/6+1/10-4/15)x+1=0
0x+1=0
0x=-1
x=-1/0
Vậy không có x (vì không có số nào chia cho 0)
a)1/6x + 1/10x - 4/15x + 1=0
b)(1/7x - 2/7)(-1/5x + 3/5)(1/3x + 4/3)=0
c)(x - 1/3)(y - 1/2)(z - 5)=0 và x + 2=y + 1=z + 3
Tìm x
a) (2x - 3)(x^2 + 2) - 2(x + 1)^3 - 9x^2 = -5
b) 3(x - 2) - x^2 + 4 = 0
c) x^3 - 5x^2 - 10x= -50
d) x^3 + 9x= 6x^2
e) 2x^2 - 5x + 3 = 0
f) x^2 - x - 2= 0
Tìm x
a, (x+2)^3 - x(x^2+6x-3)=0
b,(x+4)^3 - x(x+6)^2=7
c, (x-1)^3 - x(x^2-3x-2)=0
d,1000x^3+90x(10x+3)+27=0
e,125x^3+15x(5x+1)= -1
f, 27x^3+45x(3x+5)+133=0
a, \(\left(x+2\right)^3-x\left(x^2+6x-3\right)=0\Leftrightarrow x^3+4x^2+4x+2x^2+8x+8-x^3-6x^2+3x=0\)
\(\Leftrightarrow15x+8=0\Leftrightarrow x=-\frac{8}{15}\)
b, \(\left(x+4\right)^3-x\left(x+6\right)^2=7\Leftrightarrow12x+64=0\Leftrightarrow x=-\frac{19}{4}\)làm tắt:P
Tự làm nốt nhé
Bài 1: tìm x
a)2x4+5x2+2=0
b)x3-6x2+11x-6=0
c)x4+6x3+11x2+6x+1=0
d)(x2+10x)(x2+10x+24)=-128
Làm cụ thể hộ mình nhé =(((
b)x^3 - 6x^2 +11x-6=0
<=>x^3 - x^2 - 5x^2 +5x + 6x - 6=0
<=>x^2(x - 1) - 5x(x - 1) +6(x - 1)=0
<=>(x-1).(x^2 - 5x + 6)=0
<=>(x - 1).(x^2 - 2x - 3x + 6)=0
<=>(x - 1).[(x(x-2)-3(x-2)]=0
<=>(x-1)(x-2)(x-3)=0
<=>x-1=0hoac x-2=0 hoac x-3=0
<=>x=1hoac x=2 hoac x=3
bạn mua cái máy tính vinacal xog giải nghiệm ra hết thui
Bài 1: tìm x
a)2x4+5x2+2=0
b)x3-6x2+11x-6=0
c)x4+6x3+11x2+6x+1=0
d)(x2+10x)(x2+10x+24)=-128
Em cần giải cụ thể ạ =(((
Tìm x
a) (x+8)(x+6) -x^2 =104
b) 6x^2 -(2x-3)(3x+2) -1=0
c) (x+4)^2 +(x+3)^2 -5(x+7)=0
d) (10x+9)x -(5x -1)(2x+3) =8
\(a,\left(x+8\right)\left(x+6\right)-x^2=104\)
\(\Rightarrow x^2+14x+48-x^2=104\)
\(\Rightarrow14x=56\)
\(\Rightarrow x=4\)
Vậy x=4