\(3\left(x-2\right)+4=5x-2\left(x-1\right)\\ \Leftrightarrow3x-6+4=5x-2x+2\\ \Leftrightarrow0x=4\left(vôlý\right)\)

Vậy pt vô nghiệm

\(2\left(x-2\right)-3\left(1-2x\right)=5\\ \Leftrightarrow2x-4-3+6x=5\\ \Leftrightarrow8x=12\\ \Leftrightarrow x=\dfrac{3}{2}\)

- Ta có: \(\left(x^2-1\right).\left(x+2\right).\left(x-3\right)=\left(x-1\right).\left(x^2-4\right).\left(x+5\right)\)

      \(\Leftrightarrow\left(x-1\right).\left(x+1\right).\left(x+2\right).\left(x-3\right)=\left(x-1\right).\left(x-2\right).\left(x+2\right).\left(x+5\right)\)

      \(\Leftrightarrow\left(x-1\right).\left(x+1\right).\left(x+2\right).\left(x-3\right)-\left(x-1\right).\left(x-2\right).\left(x+2\right).\left(x+5\right)=0\)

      \(\Leftrightarrow\left(x-1\right).\left(x+2\right).\left[\left(x+1\right).\left(x-3\right)-\left(x-2\right).\left(x+5\right)\right]=0\)

      \(\Leftrightarrow\left(x-1\right).\left(x+2\right).\left[\left(x^2-2x-3\right)-\left(x^2+3x-10\right)\right]=0\)

      \(\Leftrightarrow\left(x-1\right).\left(x+2\right).\left(x^2-2x-3-x^2-3x+10\right)=0\)

      \(\Leftrightarrow\left(x-1\right).\left(x+2\right).\left(-5x+7\right)=0\)

+ \(x-1=0\)\(\Leftrightarrow\)\(x=1\left(TM\right)\)

+ \(x+2=0\)\(\Leftrightarrow\)\(x=-2\left(TM\right)\)

+ \(-5x+7=0\)\(\Leftrightarrow\)\(-5x=-7\)\(\Leftrightarrow\)\(x=\frac{7}{5}\left(TM\right)\)

Vậy \(S=\left\{-2,1,\frac{7}{5}\right\}\)

tim x biet n cong 5 chia het n cong 1

ai nhanh minh h cho heng

có: x(x+3)(x^2+3x+4)=-4

\(\Leftrightarrow\)(x^2+3x)(x^2+3x+4)+4=0

\(\Leftrightarrow\)(x^2+3x)\(^2\)+4(x^2+3x)+4=0

\(\Leftrightarrow\)(x^2+3x+2)\(^2\)=0

\(\Leftrightarrow\)x\(^2\)+3x+2=0

\(\Leftrightarrow\)(x+1)(x+2)=0

\(\Leftrightarrow\)x+1=0 hoặc x+2=0

*) Nếu x+2=0\(\Leftrightarrow\)x=-2

*) Nếu x+1=0\(\Leftrightarrow\)x=-1

Vậy S={ 2;-1}

<=> x(x³+3³)=-4 <=> x⁴+27x+4=0 <=> 

2( x - 1 ) - 5 = 3( 5 - 3x)

2x - 2 - 5 = 15 - 9x

2x - 7 = 15 - 9x

2x + 9x = 15 + 7

11x = 22

x = 2

Vậy x = 2 

\(2\left(x-1\right)-5=3\left(5-3x\right)\)

\(\Leftrightarrow2x-2-5=15-9x\)

\(\Leftrightarrow2x-\left(2+5\right)=15-9x\)

\(\Leftrightarrow2x-7=15-9x\)

\(\Leftrightarrow2x+9x=15+7\)

\(\Leftrightarrow11x=22\)

\(\Leftrightarrow x=22\div11\)

\(\Leftrightarrow x=2\)

\(\text{Vậy }x=2\)

2( x - 1 ) - 5 = 3( 5 - 3x)

    2x - 2 - 5 = 15 - 9x

         2x - 7 = 15 - 9x

      2x + 9x = 15 + 7

            11x = 22

                x = 2

x² - 5x + 4 + x² - 5x + 6 = 2

<=> 2x² - 10x + 8 = 0

<=> x² - 5x + 4 = 0

<=> x = 1 hoặc x = 4

X^2-4x-x+4+x^2-2x-3x+6=2                                                                                                                                                               rút gọn và chuyển vế  : 2x^2-10x+8=0                                                                                                                                                bấm máy tính ; x=4 và x=1        

\(\left(x-1\right)\left(x-4\right)+\left(x-3\right)\left(x-2\right)=2\)

\(< =>x^2-4x-x+4+x^2-2x-3x+6=2\)

\(< =>2x^2-10x+10-2=0\)

\(< =>2x^2-10x+8=0\)

\(< =>x^2-5x+4=0\)

\(< =>x^2-x-4\left(x-1\right)=0\)

\(< =>\left(x-4\right)\left(x-1\right)=0\)

\(< =>\orbr{\begin{cases}x=1\\x=4\end{cases}}\)