Gíup mình bài 3 và 4 với. Mình đang cần gấp
10. Cho n số a1, a2, a3, a4, a5,..., an và mỗi số = 1 hoặc -1. CMR Sn = a1.a2 + a2.a3 + a3.a4 + a4.a5 + a5.a6 +...+ an.a1 = 0 khi và chỉ khi n ⋮ 4.
Gíup mình với mình đang cần gấp!
Cảm ơn mn nhiều!
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Các Bạn Gíup mình vs ạ, mình đang cần khá gấp, cảm ơn ạ
AI giúp mình bài 3+4 với. Mình đang cần gấp
Bài 3:
b: Ta có: CD=CN
mà CN=BM
nên CD=BM
Xét ΔABC có
\(\dfrac{BM}{BA}=\dfrac{CD}{CA}\)
nên MD//BC
Xét tứ giác BMDC có MD//BC
nên BMDC là hình thang
mà \(\widehat{MBC}=\widehat{DCB}\)
nên BMDC là hình thang cân
Ai giúp mình bài 3+4 với. Mình đang cần gấp
Bài 3:
b: Ta có: CD=CN
mà CN=BM
nên CD=BM
Xét ΔABC có
\(\dfrac{BM}{BA}=\dfrac{CD}{CA}\)
nên MD//BC
Xét tứ giác BMDC có MD//BC
nên BMDC là hình thang
mà \(\widehat{MBC}=\widehat{DCB}\)
nên BMDC là hình thang cân
Xx1/3:2/5=4/3 giúp mình bài kia với bài này mình đang cần gấp
` x xx 1/3 : 2/5 =4/3`
`=> x xx 1/3 = 4/3 xx 2/5`
`=> x xx 1/3 = 8/15`
`=> x= 8/15 :1/3`
`=> x= 8/15 xx 3`
`=> x= 24/15`
`=> x= 8/5`
Dùng một ròng rọc cố định để kéo một vật có trọng lượng 200N lên cao.Khi kéo dây một đoạn 12m thì vật lên cao được bao nhiêu?
Gíup mình với mình đang cần gấp
Trung bình cộng của 4 số là 46.Số thứ hai và thứ tư bầng nhau và kém số thứ thứ nhât 16 đơn vị.Số thú nhất hơn số thứ ba 8 đơn vị.Tìm số thứ hai?
GÍUP MÌNH NHA!
MÌNH ĐANG CẦN GẤP!
Tổng của bốn số là:
\(46\times4=184\)
Số thứ ba hơn số thứ hai là:
\(16-8=8\)
Bốn lần số thứ hai là:
\(184-16-8=160\)
Số thứ hai là:
\(160\div4=40\)
giải hộ mình với không cần làm bài 4 đâu ạ
mình đang cần gấp
Bài 3:
1: Ta có: \(P=\dfrac{\sqrt{x}+1}{\sqrt{x}-2}+\dfrac{2\sqrt{x}}{\sqrt{x}+2}-\dfrac{5\sqrt{x}+2}{x-4}\)
\(=\dfrac{x+3\sqrt{x}+2+2x-4\sqrt{x}-5\sqrt{x}-2}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}\)
\(=\dfrac{\sqrt{x}}{\sqrt{x}+2}\)