Giai các hệ bất phương trình sau :

a/ \(\left\{{}\begin{matrix}x^2+x+5< 0\\x^2-6x+1>0\end{matrix}\right.\)

b/ \(\left\{{}\begin{matrix}2x^2+x-6>0\\3x^2-10x+3\ge0\end{matrix}\right.\)

c/ \(\left\{{}\begin{matrix}-2x^2-5x+4< 0\\-x^2-3x+10>0\end{matrix}\right.\)

d/ \(\left\{{}\begin{matrix}x^2+4x+3\ge0\\2x^2-x-10\le\\2x^2-5x+3>0\end{matrix}\right.0}\)

e/ \(-4\le\dfrac{x^2-2x-7}{x^2+1}\le1\)

f/ \(\left\{{}\begin{matrix}-x^2+4x-7< 0\\x^2-2x-1\ge0\end{matrix}\right.\)

Tìm m để hệ bất phương trình : có nghiệm, vô nghiệm

a)\(\left\{{}\begin{matrix}x-1>0\\mx-3>0\end{matrix}\right.\)

b)\(\left\{{}\begin{matrix}x+4m^2\le2mx+1\\3x+2>2x-1\end{matrix}\right.\)

c)\(\left\{{}\begin{matrix}7x-2\ge-4x+19\\2x-3m+2< 0\end{matrix}\right.\)

d)\(\left\{{}\begin{matrix}mx-1>0\\\left(3m-2\right)x-m>0\end{matrix}\right.\)

GIUPS EM ĐI MÀ NĂN NỈ ĐÓ

giải các hệ bất phương trình sau :

a, \(\left\{{}\begin{matrix}2x^2+9x+7>0\\x^2+x-6< 0\end{matrix}\right.\)

b,\(\left\{{}\begin{matrix}2x^2+x-6>0\\3x^2-10x+3\ge0\end{matrix}\right.\)

c.\(\left\{{}\begin{matrix}-x^2+4x-7< 0\\x^2-2x-1\ge0\end{matrix}\right.\)

d,\(\left\{{}\begin{matrix}-2x^2-5x+4< 0\\-x^2-3x+10>0\end{matrix}\right.\)

xin giúp mình -.-

Tìm m để  hệ bất phương trình vô nghiệm

a) \(\left\{{}\begin{matrix}3x+4>x+9\\1-2x\le m-3x+1\end{matrix}\right.\)

b) \(\left\{{}\begin{matrix}2x+7\ge8x+1\\m+5< 2x\end{matrix}\right.\)

c) \(\left\{{}\begin{matrix}\left(x-3\right)^2\ge x^2+7x+1\\2m\le8+5x\end{matrix}\right.\)

d) \(\left\{{}\begin{matrix}3x+5\ge x-1\\\left(x+2\right)^2\le\left(x-1\right)^2+9\\mx+1>\left(m-2\right)x+m\end{matrix}\right.\)

e) \(\left\{{}\begin{matrix}2\left(x-3\right)< 5\left(x-4\right)\\mx+1\le x-1\end{matrix}\right.\)

1.Giải hệ phương trình:

a.\(\left\{{}\begin{matrix}2\sqrt{2}x+y=2\sqrt{2}\\7x-3y=7\end{matrix}\right.\)

b.\(\left\{{}\begin{matrix}7x+y=-\frac{1}{7}\\-\frac{4}{3}x-2y=1\frac{1}{3}\end{matrix}\right.\)

c.\(\left\{{}\begin{matrix}2\sqrt{5}x+3y=\sqrt{2}\\\sqrt{5}x-y=3\sqrt{2}\end{matrix}\right.\)

d.\(\left\{{}\begin{matrix}\frac{2}{x}+\frac{3}{y}=-5\\\frac{3}{x}-\frac{4}{y}=1\end{matrix}\right.\)

e.\(\left\{{}\begin{matrix}-\frac{5}{3x+1}+\frac{7}{2x+1}=\frac{5}{7}\\\frac{1}{3x+1}-\frac{1}{2y-3}=\frac{2}{7}\\\end{matrix}\right.\)

g.\(\left\{{}\begin{matrix}2x^2+5y^2=129\\-3x^2+y^2=13\end{matrix}\right.\)

giải các hệ BPT sau:

a) \(\left\{{}\begin{matrix}5x-2>4x+5\\5x-4< x+2\end{matrix}\right.\)

b) \(\left\{{}\begin{matrix}2x+1>3x+4\\5x+3\ge8x-9\end{matrix}\right.\)

c) \(\left\{{}\begin{matrix}\frac{5x+2}{3}\ge4-x\\\frac{6-5x}{13}< 3x+1\end{matrix}\right.\)

d) \(\left\{{}\begin{matrix}\frac{4x-5}{7}< x+3\\\frac{3x+8}{4}>2x-5\end{matrix}\right.\)

e) \(\left\{{}\begin{matrix}6x+\frac{5}{7}< 4x+7\\\frac{8x+3}{2}< 2x+5\end{matrix}\right.\)

f) \(\left\{{}\begin{matrix}15x-2>2x+\frac{1}{3}\\2\left(x-4\right)< \frac{3x-14}{2}\end{matrix}\right.\)

g) \(\left\{{}\begin{matrix}x-1\le2x-3\\3x< x+5\\5-3x\le2x-6\end{matrix}\right.\)

h) \(\left\{{}\begin{matrix}2x+\frac{3}{5}>\frac{3\left(2x-7\right)}{3}\\x-\frac{1}{2}< \frac{5\left(3x-1\right)}{2}\end{matrix}\right.\)

j) \(\left\{{}\begin{matrix}\frac{3x+1}{2}-\frac{3-x}{3}\le\frac{x+1}{4}-\frac{2x-1}{3}\\3-\frac{2x+1}{5}>x+\frac{4}{3}\end{matrix}\right.\)

hệ phương trình

1 ,\(\left\{{}\begin{matrix}\frac{2x-3}{2y-5}=\frac{3x+1}{3y-4}\\2\left(x-3\right)-3\left(y+2\right)=-16\end{matrix}\right.\)

2, \(\left\{{}\begin{matrix}\frac{x}{y}=\frac{3}{2}\\3x-2y=5\end{matrix}\right.\)

3, \(\left\{{}\begin{matrix}\frac{x^2-y-6}{x}=x-2\\x+3y=8\end{matrix}\right.\)

4, \(\left\{{}\begin{matrix}\frac{x}{y}=\frac{2}{3}\\x+y=10\end{matrix}\right.\)

5, \(\left\{{}\begin{matrix}\frac{y^2+2x-8}{y}=y-3\\x+y=10\end{matrix}\right.\)

6 , \(\left\{{}\begin{matrix}\frac{x+1}{y-1}=5\\3\left(2x-2\right)-4\left(3x+4\right)=5\end{matrix}\right.\)

7, \(\left\{{}\begin{matrix}2x+y=4\\\left|x-2y\right|=3\end{matrix}\right.\)

8 , \(\left\{{}\begin{matrix}\frac{2x}{x+1}+\frac{y}{y+1}=3\\\frac{x}{x+1}-\frac{3y}{y+1}=-1\end{matrix}\right.\)

9 , \(\left\{{}\begin{matrix}y-\left|x\right|=1\\2x-y=1\end{matrix}\right.\)

10 , \(\left\{{}\begin{matrix}\sqrt{x+3y}=\sqrt{3x-1}\\5x-y=9\end{matrix}\right.\)