|x−2010|+|x−2012|+|x−2014|=2
nhanh nha
|x−2010|+|x−2012|+|x−2014|=2
Giusp nha
không có kết quả x nào tương ứng nha bạn
\frac{x-10}{2010}+\frac{x-8}{2012}+\frac{x-6}{2014}+\frac{x-4}{2016}+\frac{x-2}{2018}=\frac{x-2018}{2}+\frac{x-2016}{4}+\frac{x-2014}{6}+\frac{x-2012}{8}+\frac{x-2010}{10}
1. Tìm x biết: 2012 = | x-2010 | + | x-2008 |
2. Cho A = | x-2010 | + | x-2012 | | x-2014 |
Tìm x để A đạt GTNN
Tìm x : | x - 2010 | + | x - 2012 | + | x - 2014 | = 2
tìm x biết x^2014+x^2012+x^2010+...+x^2+1=2
Ta có: \(x^{2014}+x^{2012}+x^{2010}+...+x^2+1=0\)
=>\(x^{2014}+x^{2012}+x^{2010}+...+x^2=0-1=\left(-1\right)\)
Vô lí => X không có giá trị .
Tim x biet x^2014 + x^2012 + x^2010 + ... + x^2 + 1=
|x-2010|+|x-2012|+|x-2014|=2
tìm x
Tìm x biết: \(|x-2010|\) + \(|x-2012|\) + \(|x-2014|\) = \(2\)
Giải chi tiết hộ mik vs
Có\(\left|x-2010\right|+\left|x-2012\right|+\left|x-2014\right|\ge\left|x-2010+2014-x\right|+\left|x-2012\right|\ge2\)
mà\(\left|x-2010\right|+\left|x-2012\right|+\left|x-2014\right|=2\)
dấu "=' \(\Leftrightarrow\left\{{}\begin{matrix}x-2012=0\\2010\le x\le2014\end{matrix}\right.\)\(\Rightarrow x=2012\)
Tính nhanh
2/5 x 1/2 -2/5 x 1/3 - 2/5 x 1/6
Tìm x biết
a, 0,5 + ( x- 15/2 ) : 1/2 = 9/2
b. 2012 x X - 2010 x X= 2014
\(\frac{2}{5}\cdot\frac{1}{2}-\frac{2}{5}\cdot\frac{1}{3}-\frac{2}{5}\cdot\frac{1}{6}\)
\(=\frac{2}{5}\cdot\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(=\frac{2}{5}\cdot\frac{0}{6}=\frac{2}{5}\cdot0=0\)
tìm x
a) \(0,5+\left(x-\frac{15}{2}\right):\frac{1}{2}=\frac{9}{2}\)
\(\Rightarrow x=\frac{19}{2}=8,5\)
b) \(2012\cdot x-2010\cdot x=2014\)
\(\Leftrightarrow\left(2012-1010\right)\cdot x=2014\)
\(\Leftrightarrow2x=2014\)
\(\Rightarrow x=\frac{2014}{2}=1007\)
hok tốt .
Tính nhanh:
2/5 x 1/2 - 2/5 x 1/3 - 2/5 x 1/6
= 2/5 x ( 1/2 - 1/3 - 1/6 )
= 2/5 x ( 3/6 - 2/6 - 1/6 )
= 2/5 x 0/6
=0
Tính nhanh :
\(\frac{2}{5}\cdot\frac{1}{2}-\frac{2}{5}\cdot\frac{1}{3}-\frac{2}{5}\cdot\frac{1}{6}\)
= \(\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\cdot\frac{2}{5}\)
= \(\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\cdot\frac{2}{5}\)
= \(0\cdot\frac{2}{5}\)
= \(0\)
Tìm x biết :
a) a, 0,5 + ( x - \(\frac{15}{2}\) ) : \(\frac{1}{2}\)= \(\frac{9}{2}\)
( x - \(\frac{15}{2}\)) : \(\frac{1}{2}\)= \(\frac{9}{2}\)- 0,5
( x - \(\frac{15}{2}\)) : \(\frac{1}{2}\)= 4
( x - \(\frac{15}{2}\)) = 4 x \(\frac{1}{2}\)
x - \(\frac{15}{2}\)= 2
x = 2 + \(\frac{15}{2}\)
x = \(\frac{19}{2}\)
b, 2012 x X - 2010 x X = 2014
( 2012 - 2010 ) x X = 2014
2 x X = 2014
X = 2014 : 2
X = 1007