a) Ta có: \(10^{20}=\left(10^2\right)^{10}=100^{10}\)

Mà \(100^{10}>19^{10}\)

\(\Rightarrow10^{20}>19^{10}\)

b) Ta có: \(\left(-5\right)^{30}=5^{30}=\left(5^3\right)^{10}=125^{10}\)

\(\left(-3\right)^{50}=3^{50}=\left(3^5\right)^{10}=243^{10}\)

Mà: \(125^{10}< 243^{10}\)

\(\Rightarrow\left(-5\right)^{30}< \left(-3\right)^{50}\)

c) Ta có: \(64^8=\left(2^6\right)^8=2^{48}\)

\(16^{12}=\left(2^4\right)^{12}=2^{48}\)

Mà: \(2^{48}=2^{48}\)

\(\Rightarrow64^8=16^{12}\)

a) 10²⁰và 19¹⁰

Ta có: 10²⁰= (10²)¹⁰ và 19¹⁰

                   = 100¹⁰ và 19¹⁰

Vì 100¹⁰>19¹⁰ => 10²⁰>19¹⁰

b) (-5)³⁰ và (-3)⁵⁰

Ta có:

 (-5)30= [(-5)³]¹⁰=(-125)¹⁰ và  (-3)⁵⁰=[(-3)⁵]¹⁰=(-243)¹⁰

Vì -125¹⁰>-243¹⁰ Nên (-5)³⁰>(-3)⁵⁰

 c) 64⁸ và 16¹²  

= (4³)⁸và  (4²)¹²

= 4²⁴ và 4²⁴

=> 64⁸ = 16¹²

a ] Ta có : 10\(^{20}\) = 10\(^{^{ }2.10}\) = [ 10\(^2\) ]\(^{10}\) = 100\(^{10}\) 

Vì 100\(^{10}\) > 19\(^{10}\) Nên => 10\(^{20}\) > 19\(^{10}\)

b ] Ta có : [ -5 ]\(^{30}\) = [ -5 ]\(^{3.10}\) = [ -5\(^3\) ]\(^{10}\) = [ -125 ]\(^{10}\) 

                [ -3 ]\(^{50}\) = [ -3 ]\(^{5.10}\) = [ -3\(^5\) ]\(^{10}\) = [ -243 ]\(^{10}\)

Vì [ -125 ]\(^{10}\) < [ -243 ]\(^{10}\) Nên => [ -5 ]\(^{30}\) < [ -3 ]\(^{50}\)

c ] Ta có : 64\(^8\) = 64\(^{2.4}\) = [ 64\(^2\) ]\(^4\) = 4196\(^4\) 

                16\(^{12}\) = 16\(^{2.6}\) = [ 16\(^2\) ]\(^6\) = 4096\(^4\) 

Vì 4196\(^4\) > 4096\(^4\) Nên => 64\(^8\) > 16\(^{12}\)

a) \(32^{50}\)và \(27^{51}\)

\(32^{50}=\left(32^2\right)^{25}=1024^{25}\)

\(27^{51}=\left(27^2\right)^{25}.27=729^{25}.27\)

Vì \(1024>729\)nên \(1024^{25}>729^{25}.27\)hay \(32^{50}>27^{51}\)

b) \(31^9\)và \(9^{16}\)

\(31^9=\left(91^3\right)^2=273^2\)

\(9^{16}=\left(9^2\right)^4=81^4=\left(81^2\right)^2=6561^2\)

Vì \(6561>273\)nên \(273^2< 6561^2\)hay \(31^9< 9^{16}\).

\(\left(-32\right)^9=-\left(2^5\right)^9=-\left(2^{45}\right)\)

\(\left(-16\right)^{13}=-\left(2^4\right)^{13}=-\left(2^{52}\right)\)

vì -2^45>-2^52hay -16^13>-32^9

a, <

b, <

c, >

d, >

bn làm chi tiết nhé!!!!!!!!!!!!!!!!!!!!!!!!!!

320320 và 

Ta có: 274=(33)4=312<320274=(33)4=312<320

⇒320>274⇒320>274

225225 và 

Ta có:

166=(24)6=224<225166=(24)6=224<225

⇒225>224⇒225>224

534534 và 25.53025.530

Ta có:

25.530=532<53425.530=532<534

⇒534>25.530⇒534>25.530

10301030 và 450450

Ta có:

450=(22)50=2100=(210)10=102410450=(22)50=2100=(210)10=102410

1030=(103)10=100010<1024101030=(103)10=100010<102410

⇒1030<450

lưu ý 27 mà số 4 nhỏ ấy đấy là mũ nhé nhầm

a) ta có: (-32)⁹ = [(-2)⁵ ]⁹ = (-2)⁴⁵ = - (2)⁴⁵ 

(-16)¹³ =  - [ 2⁴ ]¹³ = - (2)⁵²

=> ....

b) ta có: (-5)³⁰ = 5³⁰ = (5³)¹⁰ = 125¹⁰

(-3)⁵⁰ = 3⁵⁰ = (3⁵)¹⁰  = 243¹⁰

=> ....

c) ta có: (-32)⁹ = (-2)⁴⁵ = (-2)¹³ . 2³² 

(-18)¹³ =  [(-2).3² ]¹³ = (-2)¹³ . 3³⁹ 

=> ....

d) ta có: \(\left(-\frac{1}{16}\right)=-\left(\frac{1}{2}\right)^4.\) 

\(\left(-\frac{1}{2}\right)=-\left(\frac{1}{2}\right)^1< -\left(\frac{1}{2}\right)^4\) 

\(\left(\frac{1}{16}\right)^{10}\) và \(\left(\frac{1}{2}\right)^{50}\)

Ta có: \(\left(\frac{1}{2}\right)^{50}=\left[\left(\frac{1}{2}\right)^5\right]^{10}=\left(\frac{1}{32}\right)^{10}\)

Do \(\frac{1}{6}>\frac{1}{32}\Rightarrow\left(\frac{1}{6}\right)^{10}>\left(\frac{1}{32}\right)^{10}\)

Vậy \(\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)

a) \(10^{20}\) và \(9^{10}\)

Vì 10 > 9 ; 20 > 10

nên \(10^{20}>9^{10}\)

Vậy \(10^{20}>9^{10}\)

b) \(\left(-5\right)^{30}\) và \(\left(-3\right)^{50}\)

Ta có: \(\left(-5\right)^{30}=5^{30}=\left(5^3\right)^{10}=125^{10}\)

           \(\left(-3\right)^{50}=3^{50}=\left(3^5\right)^{10}=243^{10}\)

Vì 243 > 125 nên \(125^{10}< 243^{10}\)

Vậy \(\left(-5\right)^{30}< \left(-3\right)^{50}\)

c) \(64^8\) và \(16^{12}\)

Ta có: \(64^8=\left(4^3\right)^8=4^{24}\)

          \(16^{12}=\left(4^2\right)^{12}=4^{24}\)

Vậy \(64^8=16^{12}\left(=4^{24}\right)\)

d) \(\left(\frac{1}{6}\right)^{10}\) và \(\left(\frac{1}{2}\right)^{50}\)

Ta có: \(\left(\frac{1}{6}\right)^{10}=\left[\left(\frac{1}{2}\right)^4\right]^{10}=\left(\frac{1}{2}\right)^{40}\)

Vì 40 < 50 nên \(\left(\frac{1}{2}\right)^{40}< \left(\frac{1}{2}\right)^{50}\)

Vậy \(\left(\frac{1}{16}\right)^{10}< \left(\frac{1}{2}\right)^{50}\)