\(x=10\)

\(26+8x=6x+46\)

\(\Rightarrow8x-6x=46-26\)

\(\Rightarrow2x=20\)

\(\Rightarrow x=10\)

26 + 8x = 6x + 46 

<=> 8x - 6x = 46 - 26 

<=> 2x = 20 

<=> x = 20 : 2 

<=> x = 10 

Vậy x = 10

\(26+8x=6x+46\)

\(\Leftrightarrow2x=20\)

\(\Leftrightarrow x=10\)

 26 + 8x = 6x + 46  

<=> 8x - 6x = 46 - 26 

<=> ( 8 - 6 )x = 20

<=>     2x       = 20

<=>      x        = 10 

26 + 8x = 6x + 46

26 - 46 = 6x - 8x

-20 = -2x

x = ( -20 ) : ( -2 )

x = 10

~ Hok tốt ~

\(26+8x=6x+46\)

\(\Rightarrow8x-6x=46-26\)

\(\Rightarrow x\left(8-6\right)=20\)

\(\Rightarrow2x=20\)

\(\Rightarrow x=20:2\)

\(\Rightarrow x=10\)

Vậy x = 10.

~Study well~

#Seok_Jin#

Ta có: \(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x-5\right)=\left(x+2\right)-\left(x-5\right)\)

\(\Leftrightarrow6x^2+21x-2x-7-6x^2+5x-6x+5=x+2-x+5\)

\(\Leftrightarrow18x-2=7\)

\(\Leftrightarrow18x=9\)

hay \(x=\dfrac{1}{2}\)

(2x+3)(4x²-6x+9)-2(4x³-1)

=8x³-12x²+18x+12x²-18x+27-8x³+2

=8x³-8x³-12x²+12x²+18x-18x+2+27

=29

(2x+3)(4x²-6x+9)-x(x²+2)

=8x³-12x²+18x+12x²-18x+27-x³-2x

=7x³-2x+27

Mình nghĩ ra câu C rồi bạn nào giúp mình nghĩ nốt câu A,B hộ mình nhé mình cảm ơn!

a:6x-5-9x^2

=-(9x^2-6x+5)

=-(9x^2-6x+1+4)

=-(3x-1)^2-4<=-4

=>A>=2/-4=-1/2

Dấu = xảy ra khi x=1/3

b: \(B=\dfrac{4x^2-6x+4-1}{2x^2-3x+2}=2-\dfrac{1}{2x^2-3x+2}\)

2x^2-3x+2=2(x^2-3/2x+1)

=2(x^2-2*x*3/4+9/16+7/16)

=2(x-3/4)^2+7/8>=7/8

=>-1/2x^2-3x+2<=-1:7/8=-8/7

=>B<=-8/7+2=6/7

Dâu = xảy ra khi x=3/4

a)26+8x=6x+46

26-46=6x-8x

-20=-2x

=>x=10

b)3600:[(5x+335):x]=50

(5x+335):x=3600:50

(5x+335):x=72
=>5x+335=72x

=>335=67x

=>x=5