=(x^2-2xy+y^2)-(3x-3y)+2

=(x-y)^2-3(x-y)+2

=(x-y-2)(x-y-1)

\(=3\left(x-y\right)+\left(x-y\right)\left(x+y\right)\)

\(=\left(x-y\right)\left(x+y+3\right)\)

\(=3\left(x-y\right)+\left(x-y\right)\left(x+y\right)=\left(x-y\right)\left(x+y+3\right)\)

3x - 3y + x² - y² 

= (3x - 3y) + (x² - y²)

= 3(x - y) + (x - y)(x + y)

=(3 + x + y)(x - y)

`x^2-y^2-3x+3y`

`=(x^2-y^2) -(3x-3y)`

`=(x-y)(x+y)-3(x-y)`

`=(x-y)(x+y-3)`

\(x^2-y^2-3x+3y\)
\(=\left(x^2-y^2\right)-\left(3x-3y\right)\)
\(=\left(x+y\right)\left(x-y\right)-3\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y-3\right)\)

#)Giải :

\(x^2-y^2+3x-3y=\left(x-y\right)\left(x+y\right)+3\left(x-y\right)=\left(x-y\right)\left(x+y+3\right)\)

\(x^2-y^2+3x-3y\)

\(=\left(x-y\right)\left(x+y\right)+3\left(x-y\right)\)

\(=\left(x-y\right)\left(x+x+3\right)\)

~ Rất vui vì giúp đc bn ~

giải hộ mik câu x^3-2x^2+x-2=0

1, (x-y)(x-3)

2,(x-y)(x+2)

3,(x+1)(x+5y)

a: \(x^2-y^2+3x+3y\)

\(=\left(x^2-y^2\right)+\left(3x+3y\right)\)

\(=\left(x-y\right)\left(x+y\right)+3\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y+3\right)\)

b: Sửa đề: \(x^2-4y^2+4x+4\)

\(=\left(x^2+4x+4\right)-4y^2\)

\(=\left(x+2\right)^2-\left(2y\right)^2\)

\(=\left(x+2+2y\right)\left(x+2-2y\right)\)

b: \(3x+3y-x^2-2xy-y^2\)

\(=3\left(x+y\right)-\left(x+y\right)^2\)

\(=\left(x+y\right)\left(3-x-y\right)\)