tim x
x+1/5=20/x+1
Tim X
a,X - 20/11 x 13 - 20/13 x 15 - 20/15 x 17 -...-20/53 x 55 = 3/11
b,1/21 + 1/28 +1/36 + ... +2/Xx(x + 1) = 2/9
Ta có : A=20/11×13 + 20/13×15 +20/15×17+...+20/53×55
A = 10 ×( 2/11×13+2/13×15+...12/53×55)
A = 10 ×(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)
A = 10 × (1/11-1/55)
A =10 × 4/55
A = 8/11
Tìm X
X-3/20 = X+1/5
=>5(x-3)=20(x+1)
=>5x-15=20x+20
=>-15x=35
hay x=-7/3
\(x-\dfrac{3}{20}=x+\dfrac{1}{5}\)
\(\Leftrightarrow0=\dfrac{1}{5}+\dfrac{3}{20}\left(voli\right)\)
Vậy pt vô nghiệm
\(\Leftrightarrow\dfrac{x-3}{20}=\dfrac{4\left(x+1\right)}{20}\)
\(\Leftrightarrow x-3=4x+4\)
\(\Leftrightarrow3x=-7\Leftrightarrow x=-\dfrac{7}{3}\)
X+20%xX=7.2
tim x
X + 0,2 x X = 7,2
1,2 x X = 7,2
X = 7,2 : 1,2
X = 6
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Ta có: \(x+20\%x=7,2\)
<=>\(x+0,2x=7,2\)
<=>\(x\left(1+0,2\right)=7,2\)
<=>\(1,2x=7,2\)
<=>\(x=7,2:1,2\)
<=>\(x=6\)
Vậy:\(x=6\)
Tim x thuoc N sao cho \(\frac{2xx+5}{xx+1}\)(2x+5\x+1) la so tu nhien
CAC BAN GIUP MINH NHA thank you so much
\(\frac{2x+5}{x+1}\in N\\ \Leftrightarrow2x+5⋮x+1\\ \Rightarrow2\left(x+1\right)+3⋮x+1\\ \Rightarrow3⋮x+1\)
tim x;y de -xx(2-y)=10 (1-x)x(1+y)=-15
tim nghiem da thuc
3xx+x
xx-5x-6
2xx+10x-12
xxx-xx+x-1
3xx+x = 0
xx-5x-6 = -6
2xx+ 10x -12 = -12
xxx-xx+x -1 =-1
2*x+1/2*x+6*x+1/6*x+12*x+1/12*x+20*x+1/20*x=5.Tim x
Tim x biet : 20 . 2^x + 1 = 10.4^2 + 1
Tim x : ( 4-x:2)^3 - 1 = 2 . (2^3 - 5 : 2^0 )
20 . 2^x + 1 = 10.4^2 + 1
20 . 2^x + 1 = 10 . 16 + 1
20 . 2^x + 1 = 161
20 . 2^x = 161 - 1
20 . 2^x = 160
2^x = 8
2^x = 2^3
=> x = 3
( 4 - x : 2 )^3 - 1 = 2 . ( 2^3 - 5 : 2^0 )
( 4 - x : 2 )^3 - 1 = 2 . ( 8 - 5 : 1 )
( 4 - x : 2 )^3 - 1 = 2 . 3
( 4 - x : 2 )^3 - 1 = 6
( 4 - x : 2 )^3 = 7
=> ko tìm đc x
Tim x:
a)\(xx+x+5=125\) b)\(xxx-xx-x-25=4430\)
\(xxx+xx+x+x=992\) \(xxx+xx+x+x+x+1=1001\)
\(4725+xxx+xx+x=54909\)\(35655-xxx-xx-x=5274\)
Cac bn giup mik nha ! :))
a, \(\overline{xx}+x+5=125\)
\(x\times11+x=120\)
\(x\left(1+11\right)=120\)
\(x=120\div12\)
\(x=10\)
Vậy x = 10
\(\overline{xxx}+\overline{xx}+x+x=992\)
\(x\times111+x\times11+x\times2=992\)
\(x\left(111+11+2\right)=992\)
\(x=992\div124\)
\(x=8\)
Vậy x = 8
\(4725+\overline{xxx}+\overline{xx}+x=54909\)
\(x\times111+x\times11+x=50184\)
\(x\left(111+11+1\right)=50184\)
\(x\times123=50184\)
\(x=408\)
Vậy x = 408
b, \(\overline{xxx}-\overline{xx}-x-25=4430\)
\(x\times111-x\times11-x=4455\)
\(x\left(111-11-1\right)=4455\)
\(x=4455\div99\)
\(x=45\)
Vậy x = 45
\(\overline{xxx}+\overline{xx}+x+x+x+1=1001\)
\(x\times111+x\times11+x\times3=1000\)
\(x\left(111+11+3\right)=1000\)
\(x=1000\div125\)
\(x=8\)
Vậy x = 8
\(35655-\overline{xxx}-\overline{xx}-x=5274\)
\(x\times111+x\times11+x=30381\)
\(x\left(111+11+1\right)=30381\)
\(x=30381\div123\)\
\(x=247\)
Vậy \(x=247\)