1. Viet cac so sau duoi dang phanso
a, 0,(8)
b, 3,(5)
c, -17,(23)
2. Tinh
A=10,(3)+0,(4)-8,(6)
nho cac ban giup minh nhe
1.tim x thuoc N biet:
a)(2x+1)mu 3=125 b)(x-5)mu 4=(x-5)mu 6 c)2 mu x-15=17 d)(7x-11)mu 3=2 mu 5. 5mu 2+200
2.viet cac tich sau hoac thuong duoi dang luy thua cua mot so:
a)2 mu 5 . 8 mu 4 b)25.125 c)25 mu 5:25 mu 7
3.viet cac tich, thuong sau duoi dang luy thua:
a) 2 mu 10:8 mu 3 b)12 mu 7:6 mu 7 c)5 mu 8:25 mu 2
4.tinh gia tri cac bieu thuc sau:
a mu3 . a mu 9 (a mu 5)mu7 (a mu 6)mu 4. a mu 12 4.5 mu 2-2.3 mu 2
Bài 1 :
a) (2x + 1)3 = 125
=> (2x + 1)3 = 53
=> 2x + 1 = 5
=> 2x = 5 - 1
=> 2x = 4
=> x = 2
b) (x - 5)4 = (x - 5)6
Với hai mũ khác nhau , ta chỉ có thể tìm được giá trị biểu thức bằng 1 hoặc 0 (giá trị của chúng bằng nhau)
+) (x - 5)4 = (x - 5)6 = 0
=> (x - 5)4 = 0
=> (x - 5)4 = 04
=> x - 5 = 0 => x = 0 + 5 = 5
+) (x - 5)4 = (x- 5)6 = 1
=> (x - 5)4 = 1
=> (x - 5)4 = 14
=> x - 5 = 1
=> x = 1 + 5
=> x = 6
Bài 4 :
a3 . a9 = a3 + 9 = a12
(a5)7.(a6)4 .a12 = a35 . a24 . a12 = a35 + 24 + 12 = a71
4.52 - 2.32 = 4.25 - 2.9
= 100 - 18
= 82
mong cac ban giup, minh can gap lam,tuy minh trinh bay hoi xau nhung mong cac ban giup
3.viet cac tich, thuong sau duoi dang luy thua:
a) \(\dfrac{2^{10}}{8^3}\)
\(=\dfrac{2^{10}}{\left(2^3\right)^3}\)
\(=\dfrac{2^{10}}{2^9}\)
\(=2^1\)
để viet so 0,0(3)duoi dang phan so ta lam nhu sau:
theo cach tren hay viet cac so thap phan sau day duoi dang phan so :
0,0(8); 0,1(2); 0,1(23)
Viet cac so (0,25)^8 va (0,125)^4 duoi dang cac luy thua cua co so 0 ,5
1.viet gon cac tich cac thuong sau duoi dang 1 luy thua
a,2 mũ 4 . 3 mũ 5 :6 mũ 4
2 tinh gia tri
a,5 mũ 3.8 b, 2 mũ 5 - 2019 mũ 0 c, 3 mũ 3 +2 mũ .5 - 1 mũ 10 d, 9 mũ 2 .33 -81 .23+5 mũ 2 g,[ 2 mũ 2 +6 mũ 2 ] :5 +11 mũ 2 h,14.3 mũ 10 -5.3 mũ 10 trên 3 mũ 12
làm nhanh mình tick cho nha
a,\(2^4\cdot3^5:6^4\)
\(=\frac{2^4\cdot3^6}{\left(2\cdot3\right)^4}\)
\(=\frac{2^4\cdot3^6}{2^4\cdot3^4}\)
\(=3^2\)
Bài 2
\(a,5^3\cdot8=5^3\cdot2^3=10^3=1000\)
\(b,2^5-2019^0=32-1=31\)
\(c,3^3+2^5-1^{10}=27+32-1=58\).
\(d,9^2\cdot33-81\cdot23+5^2=81\cdot33-81\cdot23+25\)
\(=81\cdot\left(33-23\right)+25\)
\(=810+25=835\)
\(g,\left[2^2+6^2\right]:5+11^2\)
\(=\left[4+36\right]:5+121\)
\(=40:5+121=8+121\)
\(=129\)
\(d,\frac{14\cdot3^{10}-5\cdot3^{10}}{3^{12}}\)
\(=\frac{3^{10}\cdot\left(14-5\right)}{3^{12}}\)
\(=\frac{3^{10}\cdot9}{3^{12}}\)
\(=\frac{3^{10}\cdot3^2}{3^{12}}=\frac{3^{12}}{3^{12}}\)
\(=1\)
Viet ket qua moi phep tinh sau duoi dang mot luy thua
a 11^8:11^3
b 17^11:17^9
c 4^3:2^2
d a^5:a(a khac 0)
viet cac tich hoac thuong sau duoi dang luy thua cua 1 so
a/25.84
b/256.1253
c/6255:257
d/123.33
a, 25 . 84 = 25 . (23)4 = 25 . 212 = 25+12 = 217
b, 256 . 1253 = (52)6 . (53)3 = 512 . 59 = 512+9 = 521
c, 6255 : 257 = (54)5 : (52)7 = 520 : 514 = 520-14 = 56
d, 123 . 33 = ( 3 . 22 )3 . 33 = 33 .26 . 33 = 33+3 . 26 = 36 . 26 = (3.2)6 = 66
Viet cac so sau duoi dang phan so:
a, 2,(14) b,-2,(15)
c,-4,3(2) d,0,14(8)
Tim cac so nguyen to a, b co 1 chu so de so x bang 5 x a phan 6 x b viet duoc duoi dang:a, so thap phan huu hanb, so thap phan vo han tuan hoanviet cac so sau duoi dang luy thua cua 1 so:
\(a)-\frac{8}{27}\)
\(b)\frac{81}{625}\)
viet cac tich sau duoi dang luy thua cua 1 so:
\(a)27.81\)
\(b)\frac{2}{5}.\frac{8}{125}.\frac{16}{625}\)
1.
a) \(-\frac{8}{27}=-\left(\frac{2}{3}\right)^3\)
b) \(\frac{81}{625}=\left(\frac{3}{5}\right)^4\)
2.
a) 27.81=2187=37
b) sai đề
viet cac tich hoac thuong sau duoi dang luy thua cua 1 so
22.84 ;256.1253 ; 6256 :257 ;123.33