1)
a) 0,(8) = \(\frac{8}{9}\)
b) 3,(5) = 3 + 0,(5) = 3 + \(\frac{5}{9}\) = \(\frac{27}{9}\) + \(\frac{5}{9}\) = \(\frac{32}{9}\)
c) -17,(23) = -17 + -0,(23) = -17 + \(\frac{-23}{99}\) = \(\frac{-1683}{99}\) +\(\frac{-23}{99}\) = \(\frac{-1706}{99}\)
2) A = 10,(3) + 0,(4) - 8,(6)
= 10+ 0,(3) + 0,(4) - 8 +0,(6)
= 10 +\(\frac{3}{9}\) + \(\frac{4}{9}\) - 8+ \(\frac{6}{9}\)
= \(\frac{90}{9}\) + \(\frac{3}{9}\) + \(\frac{4}{9}\) - \(\frac{72}{9}\) + \(\frac{6}{9}\)
= \(\frac{31}{9}\)