Tính A=\(\left(\frac{1.5+1-0.75}{2.5+\frac{5}{3}-1.25}+\frac{0.375-0.3+\frac{3}{11}+\frac{3}{12}}{-0.625+0.5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)
Giúp mk vs nka
Tính : A=\(\frac{0.375-0.3+\frac{3}{11}+\frac{3}{12}}{-0.625-0.5-\frac{5}{11}-\frac{5}{12}}+\frac{1.5+1-0.75}{2.5+\frac{5}{3}-1.25}\) Hộ mình cái!!!!!!!!!!!!!!!!!!!!!!!!!
Tính \(A=\frac{0.375-0.3+\frac{3}{11}+\frac{3}{12}}{-0.265+0.5-\frac{5}{11}-\frac{5}{12}}+\frac{1.5+1-0.75}{2.5+\frac{5}{3}-1.25}\)
\(\frac{0.375-0.3+\frac{3}{11}+\frac{3}{12}}{-0.265+0.5-\frac{5}{11}-\frac{5}{12}}+\frac{1.5+1-0.75}{2.5+\frac{5}{3}-1.25}\)
Sửa đề: \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
Ta có: \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
\(=\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{-5}{8}+\frac{5}{10}-\frac{5}{11}-\frac{5}{12}}+\frac{\frac{3}{2}+\frac{3}{3}-\frac{3}{4}}{\frac{5}{2}+\frac{5}{3}-\frac{5}{4}}\)
\(=\frac{-3\left(\frac{-1}{8}+\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\right)}{5\left(\frac{-1}{8}+\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\right)}+\frac{3\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\right)}{5\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\right)}\)
\(=\frac{-3}{5}+\frac{3}{5}=0\)
Tính
a)\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2012}}{\frac{2011}{1}+\frac{2010}{2}+\frac{2009}{3}+....\frac{1}{2011}}\)
b)\(\frac{0.375-0.3+\frac{3}{11}+\frac{3}{12}}{-0.265+0.5-\frac{5}{11}-\frac{5}{12}}+\frac{1.5+1-0.75}{2.5+\frac{5}{3}-1.25}\)
tính nhanh
\(\frac{0.375-0.3+\frac{3}{11}+\frac{3}{12}}{0.625-0.5+\frac{5}{11}+\frac{5}{12}}\)
\(\frac{0.375-0.3+\frac{3}{11}+\frac{3}{12}}{0.625-0.5+\frac{5}{11}+\frac{5}{12}}\)
\(=\frac{0.075+\frac{3}{11}+\frac{3}{12}}{0.125+\frac{5}{11}+\frac{5}{12}}\)
\(=\frac{\frac{3}{40}+\frac{3}{11}+\frac{3}{12}}{\frac{5}{40}+\frac{5}{11}+\frac{5}{12}}\)
\(=\frac{3.\left(\frac{1}{40}+\frac{1}{11}+\frac{1}{12}\right)}{5.\left(\frac{1}{40}+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)
\(\frac{0.375-0.3+\frac{3}{11}+\frac{3}{12}}{0.625-0.5+\frac{5}{11}+\frac{5}{12}}\)
\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{5}{8}-\frac{1}{2}+\frac{5}{11}+\frac{5}{12}}=\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{5}{8}-\frac{5}{10}+\frac{5}{11}+\frac{5}{12}}\)
\(=\frac{3\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}{5\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}=\frac{\frac{263}{440}}{\frac{263}{264}}=\frac{3}{5}\)
Số chẳng đẹp gì cả.
Tính:
\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)
\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)
\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right)\div\frac{1890}{2005}+115\)
\(A=\left(\frac{3\left(0,5+\frac{1}{3}-0,25\right)}{5\left(0,5+\frac{1}{3}-0,25\right)}+\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{-5\left(0,125-0,1+\frac{1}{11}+\frac{1}{11}\right)}\right)\div\frac{1890}{2005}+115\)
\(A=\left(\frac{3}{5}+\frac{-3}{5}\right)\div\frac{1890}{2005}+115\)
\(A=0\div\frac{1890}{2005}+115\)
\(A=115\)
\(\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)
Ta có : \(\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)
\(=\left(\frac{3\left(0,5+\frac{1}{3}-0,25\right)}{5\left(0,5+\frac{1}{3}-0,25\right)}+\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{-5\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}\right).\frac{2005}{1890}+115\)
\(=\left(\frac{3}{5}-\frac{3}{5}\right).\frac{2005}{1890}+115=0+115=115\)
= ( \(\frac{\frac{3}{2}+\frac{3}{3}-\frac{3}{4}}{\frac{5}{2}+\frac{5}{3}-\frac{5}{4}}\)+ \(\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{-5}{8}+\frac{5}{10}-\frac{5}{11}-\frac{5}{12}}\)) x \(\frac{2005}{1890}\)+ 115
= ( \(\frac{3(\frac{1}{2}+\frac{1}{3}-\frac{1}{4})}{5(\frac{1}{1}+\frac{1}{3}-\frac{1}{4})}\)+ \(\frac{3(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12})}{-5(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12})}\)) x \(\frac{2005}{1890}\)+ 115
=( \(\frac{3}{5}\)+\(\frac{3}{-5}\)) x \(\frac{2005}{1890}\)+115 = 0 +115 = 115
mk đánh máy nhầm chỗ \(\frac{1}{1}\) bạn đổi thành \(\frac{1}{2}\)hộ mk vs nhé. chúc bạn học tốt!