bằng 140 bạn nhé

4 x 7 x 5

= (4x5) x7

= 20 x 7

140

4 × 7 × 5 = 140

1+5+3+9+5+7=30

Bằng 30 nha

k Đúng cho mình nhá

30 nhe bn

=> 1 - 3 . X=x - 7 hoặc 1 - 3 . X =-(x-7)

*1 - 3x =x - 7                 *1 - 3x = -(x - 7 )

   8         =x + 3x             1 - 3x = -x + 7     

   8         =4x                   -3x+x =7-1

   8 : 4     =x                    -2x    =6

    2          = x                      x   = 6:(-2)

  =>x = 2                            x    = -3

vậy x \(\in\){2; -3}

đúng + x  =1

           x   =1 -đúng 

           x    = thích

<=> B= - ( x² -10x + 25) +32

<=> B= - ( x-5)² + 32

Vì (x-5)² >= 0

<=> -( x-5)² <=0

<=> B<= 32

Dấu "=" xảy ra <=> x=5

MÀY vào câu hỏi tương tự .

Tao không rảnh

Ok?

120 dư 5 nha

845 : 7 = 120 ( dư 5 ) bạn nhé

cần chi lời giải . 120 dư gì đó

1 The meeting was canceled 3 days ago

2 She told me she was watching a film with her sister then

3 I admire the guitarist who is perfroming on the stage

4 Had it not been for Pauline's interest, the project would have been abandoned 

IV. 

1. The meeting was canceled 3 days ago.

2. She told me shewas watching a film with her sister then

3. I admire the guitarist who is performing on the stage

4. Had it not been for Pauline's interest, the project was abandoned. (chắc thế)

a) x¹² + 4 = x¹² + 4x⁶ + 4 - 4x⁶ = (x⁶ + 2)² - (2x³)² 

= (x⁶ - 2x³ + 2)(x⁶ + 2x³ + 2)

b) 4x⁸ + 1 = 4x⁸ + 4x⁴  + 1 - 4x⁴ = (2x⁴ + 1)² - (2x²)² 

= (2x⁴ + 2x² + 1)(2x⁴ - 2x²  + 1)

c) x⁷ + x⁵ - 1 = x⁷ - x + x⁵ + x² - (x² - x  + 1) = x(x⁶ - 1) + x²(x³ + 1) - (x² - x + 1)

= x(x³ - 1)(x³ + 1) + x²(x + 1)(x² - x + 1) - (x2 - x + 1)

= (x⁴ - x)(x + 1)(x² - x + 1) + (x³ + x²)(x² - x + 1) - (x² - x + 1)

= (x⁵ + x⁴ - x² - x + x³ + x² - 1)(x² -x + 1)

= (x⁵ + x⁴ + x³ - x - 1)(x² - x + 1)

d) x⁷ + x⁵ + 1 = x⁷ - x + x⁵ - x² + (x² + x + 1)

= x(x³ - 1)((x³ + 1) + x²(x³ - 1) + (x² + x + 1)

= (x⁴ + x)(x  - 1)(x² + x + 1) + x²(x - 1)((x² + x + 1) + (x² + x + 1)

= (x² + x + 1)(x⁵ - x⁴ + x² - x + x³ - x² + 1)

= (x² + x + 1)(x⁵ - x⁴ + x³ - x + 1)

III. 

A. 

1. B

2. C

3. B

4. A

5. D

B. 

1. C

2. B

3. B

4. A

5. C

1 b c b a d

2 c b b a c nha