Thể tích của hình trụ là: \(V=S.h=m^2\pi h\).

Thể tích của hình nón là: \(V=\dfrac{1}{3}S.h=\dfrac{1}{3}m^2\pi h\).

Do đó độ cao trong hình trụ là \(\dfrac{1}{3}h\).

b: \(\sqrt{8^2+6^2}-\sqrt{16}+\dfrac{1}{2}\sqrt{\dfrac{4}{25}}\)

\(=10-4+\dfrac{1}{2}\cdot\dfrac{2}{5}=6+\dfrac{1}{5}=\dfrac{31}{5}\)

4:

a: căn x-1=3

=>căn x=4

=>x=16

b: căn x-3=2

=>căn x=5

=>x=25

c: 5/12*căn x-1/6=1/3

=>5/12*căn x=1/2

=>căn x=1/2:5/12=1/2*12/5=12/10=6/5

=>x=36/25

d: căn x-1-3=0

=>căn x-1=3

=>x-1=9

=>x=10

e: =>căn x+1=1

=>x+1=1

=>x=0

f: =>|3/5*căn x-1/20|=1/5+3/4=19/20

=>3/5*căn x-1/20=-19/20 hoặc 3/5*căn x-1/20=19/20

=>3/5*căn x=1

=>căn x=5/3

=>x=25/9

\(\dfrac{9^{15}.8^{11}}{3^{29}.16^8}=\dfrac{\left(3^2\right)^{15}.\left(2^3\right)^{11}}{3^{29}.\left(2^4\right)^8}=\dfrac{3^{30}.2^{33}}{3^{29}.2^{32}}\)

Ta lấy vễ trên chia vế dưới

\(=3.2=6\)

\(\dfrac{2^{11}.9^3}{3^5.16^2}=\dfrac{2^{11}.\left(3^2\right)^3}{3^5.\left(2^4\right)^2}=\dfrac{2^{11}.3^6}{3^5.2^8}\)

Ta lấy vế trên chia vế dưới

\(=2^3.3=24\)

\(\dfrac{9^{15}.8^{11}}{3^{29}.16^8}=\dfrac{\left(3^2\right)^{15}.\left(2^3\right)^{11}}{3^{29}.\left(2^4\right)^8}=\dfrac{3^{30}.2^{33}}{3^{29}.3^{32}}=3.2=6\)
\(\dfrac{2^{11}.9^3}{3^5.16^2}=\dfrac{2^{11}.\left(3^2\right)^3}{3^5.\left(2^4\right)^2}=\dfrac{2^{11}.3^6}{3^5.2^8}=2^3.3=8.3=24\)

\(\dfrac{9^{15}.8^{11}}{3^{29}.16^8}=\dfrac{3^{30}.2^{33}}{3^{29}.2^{32}}=3.2=6\)

\(\dfrac{2^{11}.9^3}{3^5.16^2}=\dfrac{2^{11}.3^6}{3^5.2^8}=2^3.3=8.3=24\)

what is her mother going to prepare for her bỉthdat party

there are three sticks of butter in the cupboard

i have enough food for the first three day of your stay

\(25+27-48-25-37=\left(25-25\right)+\left(27-37\right)-48\)

\(=0-10-48\)

\(=-58\)

= 25-25+27-37-48

=0+(-10)-48

=-10-48

=-58

25+27-48-25-37

=(25-25)+(27-37)-48

=0+0-48

=-48