Tìm x: biết
a, x/4= 16/128
b, 11/6= -x/5
c, 4,25:8= -3,5:x
Tìm x,biết:
a)11/6= -x/5
b)4,25:8= -3,5:x
\(a,\frac{11}{6}=-\frac{x}{5}\)
\(\Leftrightarrow-x\times6=11\times5\)
\(\Leftrightarrow-6x=55\)
\(\Leftrightarrow x=55:\left(-6\right)\)
\(\Leftrightarrow x=-\frac{55}{6}\)
\(b,4,25:8=-3,5:x\)
\(\Leftrightarrow\frac{17}{32}=--\frac{7}{2}:x\)
\(\Leftrightarrow x=-\frac{7}{2}:\frac{17}{32}\)
\(\Leftrightarrow x=-\frac{112}{17}\)
a) \(\frac{11}{6}=\frac{-x}{5}\)
\(\Rightarrow\frac{55}{30}=\frac{\left(-x\right)\cdot6}{30}\)
\(\Rightarrow55=\left(-x\right)\cdot6\)
\(\Rightarrow-x=\frac{55}{6}\)
\(\Rightarrow x=-\frac{55}{6}\)
b) \(4,25:8=-3,5:x\)
\(\Rightarrow0,53125=-3,5:x\)
\(\Rightarrow x=-3,5:0,53125\)
\(\Rightarrow x=-6,5882...\)
2. Tìm x, biết:
a/ \(\dfrac{x}{4}=\dfrac{16}{128}\) ; b/\(1\dfrac{5}{6}=\dfrac{-x}{5}\) ; c/ 4,25:8= -3,5 : x
a) \(\dfrac{x}{4}=\dfrac{16}{128}\Rightarrow x=\dfrac{4.16}{128}=\dfrac{1}{2}=0,5\)
b)\(1\dfrac{5}{6}=\dfrac{-x}{5}\\ \Leftrightarrow\dfrac{11}{6}=\dfrac{-x}{5}\Rightarrow-x=\dfrac{5.11}{6}=\dfrac{55}{6}\Rightarrow x=-\dfrac{55}{6}\)
c) \(\dfrac{4,25}{8}=\dfrac{-3,5}{x}\Rightarrow x=\dfrac{8.\left(-3,5\right)}{4,25}=-\dfrac{112}{17}\)
a,X/4=16/28
=»x/4=4/7
=4/7.4
=7
b,1/5/6=-x/5
-x/5=11/6
X=11/6.5
X=55/6
Tìm x,biết:
a) \(\dfrac{x}{4}=\dfrac{16}{128};\) b)\(1\dfrac{5}{6}=\dfrac{-x}{5}\); c)4,25:8=\(-3,5:\)x
\(a,\dfrac{x}{4}=\dfrac{16}{128}\\ \Leftrightarrow128x=4.16\\ \Leftrightarrow128x=64\\ \Leftrightarrow x=\dfrac{1}{2}\)
Vậy...
\(b,1\dfrac{5}{6}=\dfrac{-x}{5}\\ \Leftrightarrow-6x=25\\ \Leftrightarrow x=-\dfrac{25}{6}\)
Vậy...
\(c,4,25:8=-3,5:x\\ \Leftrightarrow4,25x=-3,5.8\\ \Leftrightarrow x=-28:4,25\\ \Leftrightarrow x=-\dfrac{112}{17}\)
Vậy...
Tìm x biết:
a) \(\dfrac{x}{4}=\dfrac{16}{128}\)
b) \(1\dfrac{5}{6}=\dfrac{-x}{5}\)
c) 4,25:8=-3,5:x
Câu a :
\(\dfrac{x}{4}=\dfrac{16}{128}\) \(\Leftrightarrow x.128=4.16\) \(\Rightarrow x=\dfrac{1}{2}\)
Câu b :
\(1\dfrac{5}{6}=-\dfrac{x}{5}\) \(\Leftrightarrow11.5=-x.6\) \(\) \(\Rightarrow-x=-\dfrac{55}{6}\)
Câu c :
\(\dfrac{4,25}{8}=\dfrac{-3,5}{x}\) \(\Leftrightarrow4,25.x=8.-3,5\) \(\Rightarrow x=-\dfrac{112}{17}\)
a,Ta có : x.128=16.4
x.128=64
Suy ra : x=1/2
b,\(1\dfrac{5}{6}=\dfrac{11}{6}\)
Ta có ; 11.5=-x.6
-x.6=55
Suy ra : x=-55/6
c,Ta có : 4,25.x=-3,5.8
4,25.x=-28
Suy ra : x=-112/17
Tìm x biết :
a) \(\frac{x}{4}=\frac{16}{128}\)
b) \(1\frac{5}{6}=\frac{-x}{5}\)
c) 4,25 : 8 = -3,5 : x
Mình cần gấp bạn nào nhanh mình tick nhé
a ) x/4 = 16/128
Áp dụng tính chất phân số bằng nhau ta có 4 . 16 = x . 128
64 = x . 128
=> x = 0,5
b ) \(1\frac{5}{6}=\frac{-x}{5}\)
11/6 = -x/5
Áp dụng tính chất phân số bằng nhau ta có 11 . 5 = 6 . -x
=> không tồn tại x ( vì 11 . 5 kết quả là dương , 6 . -x sẽ có kết quả âm , dương không thể bằng âm
c ) 4,25 : 8 = -3,5 : x
4,25 = -3.5 . 17/-14
=> 8 = x . 17/-14
=> x = -112/17
Tìm x, biết:
a) \(\dfrac{x}{4}=\dfrac{16}{128}\)
b) \(1\dfrac{5}{6}=\dfrac{-x}{5}\)
c) \(4,25:8=-3,5:x\)
\(a.\)
\(\dfrac{x}{4}=\dfrac{16}{128}\)
\(\Rightarrow x=\dfrac{16.4}{128}=\dfrac{1}{2}\)
\(b.\)
\(1\dfrac{5}{6}=-\dfrac{x}{5}\)
\(\Rightarrow\dfrac{11}{6}=-\dfrac{x}{5}\)
\(\Rightarrow x=\dfrac{11.\left(-5\right)}{6}=-\dfrac{55}{6}\)
\(c.\)
\(4,25:8=-3,5:x\)
\(\Rightarrow\dfrac{4,25}{8}=\dfrac{-3,5}{x}\)
\(\Rightarrow x=\dfrac{-3,5.8}{4,25}=-\dfrac{112}{17}\)
\(a)\dfrac{x}{4}=\dfrac{16}{128}\)
\(\Rightarrow\dfrac{16}{128}.4=\dfrac{1}{2}\)
\(b)1\dfrac{5}{6}=\dfrac{-x}{5}\)
\(\Rightarrow x=\dfrac{11}{6}.\left(-5\right)=\dfrac{-55}{6}\)
\(c)4,25:8=-3,5:x\)
\(\Rightarrow\dfrac{4,25}{8}=\dfrac{-3,5}{x}\)
\(\Rightarrow x=\dfrac{-3,5.8}{4,25}=\dfrac{-112}{17}\)
Chúc bạn học tốt!
a) \(\frac{x}{4}=\frac{16}{128}\)
b) 1\(\frac{5}{6}=\frac{-x}{5}\)
c) 4,25 : 8= +3,5 :x
a)\(\frac{x}{4}=\frac{16}{128}=\frac{1}{8}\)
\(\Rightarrow x=\frac{4}{8}=\frac{1}{2}\)
b)\(1\frac{5}{6}=\frac{11}{6}=\frac{-x}{5}\)
\(\Rightarrow x=\frac{11\times-5}{6}=\frac{-55}{6}\)
c)\(\frac{4,25}{8}=\frac{3,5}{x}\Rightarrow x=\frac{8\times3,5}{4,25}=\frac{112}{17}\)
Tìm x
a) \(\dfrac{x}{4}=\dfrac{16}{128}\)
b)\(1\dfrac{5}{6}=\dfrac{-x}{5}\)
c) 4,25: 8 = -3,5 : x
a)\(\dfrac{x}{4}=\dfrac{16}{128}\)
\(\Leftrightarrow\dfrac{x}{4}=\dfrac{1}{8}\)
\(\Rightarrow x=\dfrac{1.4}{8}=\dfrac{1}{2}\)
b)\(1\dfrac{5}{6}=\dfrac{-x}{5}\)
\(\Leftrightarrow\dfrac{11}{6}=\dfrac{-x}{5}\)
\(\Rightarrow-x=\dfrac{11.5}{6}=\dfrac{-55}{6}\)
c)\(4,25:8=-3,5:x\)
\(\Leftrightarrow\dfrac{17}{32}=\dfrac{-3,5}{x}\)
\(\Rightarrow x=\dfrac{\left(-3,5\right).32}{17}=-\dfrac{112}{17}\)
Tìm x
a)\(\dfrac{x}{4}\)=\(\dfrac{16}{128}\)
\(\Rightarrow\)x.128=16.4
x.128=64
x=64:128
x=\(\dfrac{1}{2}\)
Vậy x=\(\dfrac{1}{2}\)
b)\(1\dfrac{5}{6}\)=\(\dfrac{-x}{5}\)
\(\dfrac{11}{6}\)=\(\dfrac{-x}{5}\)
-x:5=\(\dfrac{11}{6}\)
-x=\(\dfrac{11}{6}\).5
-x=\(\dfrac{55}{6}\)
\(\Rightarrow\)x=\(\dfrac{-55}{6}\)
Vậy x=\(\dfrac{-55}{6}\)
c)4,25:8 = -3,5:x
-3,5:x=\(\dfrac{17}{4}\)
x=-3,5:\(\dfrac{17}{4}\)
x=\(\dfrac{14}{17}\)
Vậy x=\(\dfrac{14}{17}\)
a, Ta có : \(\dfrac{x}{4}\)= \(\dfrac{16}{128}\)
\(\Rightarrow\)4 . 16 = x . 128
\(\Rightarrow\) x = (4 . 16 ) : 128
\(\Rightarrow\) x = \(\dfrac{1}{2}\)
b, Ta có : 1\(\dfrac{5}{6}\) = \(\dfrac{-x}{5}\)
\(\Leftrightarrow\dfrac{11}{6}\) = \(\dfrac{-x}{5}\)
\(\Rightarrow\)11 . 5 = 6 . ( \(-x\) )
\(\Rightarrow\)\(-x\) = (11. 5) : 6
\(\Rightarrow\) \(-x\) = \(\dfrac{-55}{6}\)
\(\Rightarrow\) \(x\) = \(\dfrac{55}{6}\)
c,Ta có : 4 , 25 : 8 = \(-3,5\) : x
\(\Rightarrow\) \(\dfrac{17}{32}\) = \(\dfrac{-3,5}{x}\)
\(\Rightarrow\) 17 . x = \(-3,5\) . 32
\(\Rightarrow\) x = ( \(-3,5\) . 32 ): 17
\(\Rightarrow\) x = \(\dfrac{-112}{17}\)
Tìm số tự nhiên x biết rằng:
a ) 2 x . 4 = 128 b ) x 15 = x
c ) ( x - 5 ) 4 = ( x - 5 ) 6 d ) x 2018 = x 2