\(5x^3-5xy^2+10xy-5x\)

\(=5x\left(x^2-y^2+2y-1\right)\)

\(=5x\left[x^2-y^2+y+y-1\right]\)

\(=5x\left[x^2-y\left(y-1\right)+\left(y-1\right)\right]\)

\(=5x\left[x^2-\left(y+1\right)\left(y-1\right)\right]\)

\(=5x\left[x^2-\left(y^2-1^2\right)\right]\)

\(=5x\left[\left(x-y\right)\left(x+y\right)+1\right]\)

Lâu k làm, sai thông cảm 

Answer:

\(5x^3-5xy^2+10xy-5x\)

\(=5x\left(x^2-y^2+2y-1\right)\)

\(=5x[x^2-\left(y^2-2y+1\right)]\)

\(=5x[x^2-\left(y-1\right)^2]\)

\(=5x\left(x-y+1\right)\left(x+y-1\right)\)

a/ = xy(5y - 6x)

b/ = - (15y² - 2x + 5y - 10xy)

\(=2x\left(x-3y\right)+5\left(x-3y\right)=\left(x-2y\right)\left(2x+5\right)\)

(x−2y)(2x+5)

5x² + 10xy - 4x - 8y

= 5x(x + 2y) - 2(x - 2y)

= (5x - 2)(x + 2y)

=(5x² + 10xy) - (4x + 8y) = 5x.(x + 2y) - 4.(x + 2y) = (5x - 4).(x + 2y)

\(5x^2+10xy-4x-8y=\left(5x^2+10xy\right)-\left(4x+8y\right)=5x\left(x+2y\right)-4\left(x+2y\right)=\left(5x-4\right)\left(x+2y\right)\)

Lời giải:

$A=x^2-8xy+15y^2=x^2-3xy-(5xy-15y^2)$

$=x(x-3y)-5y(x-3y)=(x-3y)(x-5y)$

$B=2x^2-5xy+2y^2=(2x^2-4xy)-(xy-2y^2)$

$=2x(x-2y)-y(x-2y)=(2x-y)(x-2y)$

$C=2x^2-3y^2-xy=(2x^2+2xy)-(3y^2+3xy)$

$=2x(x+y)-3y(y+x)=(x+y)(2x-3y)$

Làm tính nhân

(4x³+3xy²-2y³).(3x²-5xy-6y²)

=12x⁵+12y⁵-20x⁴y-36x²y³-8xy⁴

Phân tích đa thức thành nhân tử

10x³+5x²y-10x²y-10xy²+5y³

=10x³-5x²y-10xy²+5y³

=5(2x³-x²y-2xy²+y³-)