64x^3 + 1 - 64x^3 + 80x =17

80x                              =16

   x                               =3/10

64x^3 + 1 -64x^3 + 80x = 17

80x                             = 16

   x                              = 3/10

64x^3 + 1 - 64x^3 + 80x = 17

80x                               = 16

   x                                = 3/10

\(p=\left(x+1\right)\left(x^2-x+1\right)+x-\left(x-1\right)\left(x^2+x+1\right)+2010\)\(=\left(x^3+1\right)+x-\left(x^3-1\right)+2010=x^3+1+x-x^3+1+2010=x+2012\)Với \(x=-2010\Rightarrow p=-2010+2012=2\)

\(q=16x\left(4x^2-5\right)-\left(4x+1\right)\left(16x^2-4x+1\right)=64x^3-80x-64x^3-1=-80x-1\)Với \(x=\dfrac{1}{5}\Rightarrow q=-80.\dfrac{1}{5}-1=-17\)

\(\left(4x+1\right)\left(1-4x+16x^2\right)-16x\left(4x^2-5\right)=17\)

\(\Leftrightarrow4x-16x^2+64x^2+1-4x+16x^2-64x^2+80x-17=0\)

\(\Leftrightarrow\left(-16x^2+16x^2\right)+\left(64x^2-64x^2\right)+\left(4x-4x\right)+80x+1-17=0\)

\(\Leftrightarrow80x=16\)

\(\Leftrightarrow x=\dfrac{1}{5}\)

giải

5x-(4-2x+x^2)(x+2)+x(x-1)(x+1)=0

5x-(4x+8-2x^2-4x+x^3+2x^2)+x(x^2-1)=0

5x-4x-8+2x^2+4x-x^3-2x^2+x^3-1x=0

(5x-4x+4x-1x)+(-8)+(2x^2-2x^2)+(-x^3+x^3)=0

4x+(-8)=0

4x=0+8

4x=8

x=8:4

x=2

D)(4x+1)(16x^2-4x+1)-16x(4x^2-5)=17

64x^3-16x^2+4x+16x^2-4x+1-64x^3+80x=17

80x+1=17

80x=17-1

80x=16

x=1/5

\(5x-\left(4-2x+x^2\right)\left(x+2\right)+x\left(x-1\right)\left(x+1\right)=0\)

\(\Rightarrow5x-\left(4x-2x^2+x^3+8-4x+2x^2\right)+\left(x^2-x\right)\left(x+1\right)=0\)

\(\Rightarrow5x-\left(4x-2x^2+x^3+8-4x+2x^2\right)+\left(x^3+x-x^2-x\right)=0\)

\(\Rightarrow5x-4x+2x^2-x^3-8+4x-2x^2+x^3+x-x^2-x=0\)

\(\Rightarrow4x-8=0\Rightarrow4x=8\Rightarrow x=2\)

Bài 3: 

\(K=\left(a-1\right)\left(a^2+a+1\right)\left(a+1\right)\left(a^2-a+1\right)\)

\(=\left(a^3+1\right)\left(a^3-1\right)\)

\(=a^6-1\)

Bài 2: 

\(\Leftrightarrow64x^3+1-64x^3+80x=17\)

=>80x=16

hay x=1/5