\(^{2^5\cdot13^{13}:\left(6^3\cdot27^3\right)}\)
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Tính gíá trị biểu thức :
A= \(\frac{3^{10}\cdot11+\left(3^2\right)^5:5}{24\cdot27}\)
B= \(\frac{2^{10}\cdot13+2^{10}\cdot65}{28\cdot104}\)
AI NHANH MK K CHO
cách làm :
câu B
ta thấy có 2 lần 210 xuất hiện trên 1 phần tử
ta gộp lại như sau :
210 x ( 13 + 65 ) cho dễ
còn câu A
ta không thể tóm gọn nên phải tính như bình thường
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A = 649539 + 45 / 648
A = 1002 . 44444444444444444
hay 649584 / 648
B = 0 + 66560 / 2912
B = 22 . 8571428571
hay 66560 / 2912
Đ/s : .........
nhé !
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cho mình sửa lại câu B
B = 1024 x ( 13 + 65 ) / 2912
B = 79872 / 2912
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\(\frac{-4}{5}\cdot13\frac{1}{3}-\frac{4}{5}\cdot\left(-13\frac{1}{2}\right)\)Tính
\(\frac{-4}{5}.13\frac{1}{3}-\frac{4}{5}.\left(-13\frac{1}{2}\right)\)
\(=\frac{4}{5}.\left(-13\frac{1}{3}\right)-\frac{4}{5}.\left(-13\frac{1}{2}\right)\)
\(=\frac{4}{5}\left[\left(-3\frac{1}{2}\right)-\left(-3\frac{1}{2}\right)\right]\)
\(=\frac{4}{5}.0\)
\(=0\)
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\(\dfrac{-4}{5}\cdot13\dfrac{1}{3}-\dfrac{4}{5}\cdot\left(-13\dfrac{1}{2}\right)\)Tính
\(=\dfrac{-4}{5}\left(13+\dfrac{1}{3}-13-\dfrac{1}{2}\right)=\dfrac{-4}{5}\cdot\dfrac{-1}{6}=\dfrac{4}{30}=\dfrac{2}{15}\)
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Tinh
A=\(\frac{15\cdot3^{11}+4\cdot27^1}{9^7}\)
B=\(\frac{5\cdot2^{13}+4^{11}-1}{\left(3\cdot2^{17}\right)^2}\)
C=\(\frac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\)
\(A=\frac{15.3^{11}+4.27^1}{9^7}\)
\(\Rightarrow A=\frac{3.5.3^{11}+4.3^{3^1}}{\left(3^2\right)^7}\)
\(\Rightarrow A=\frac{3^{12}.5+4.3^3}{3^{14}}\)
\(\Rightarrow A=\frac{3^3.\left(5.3^8+4.3^3\right)}{3^{14}}\)
\(\Rightarrow A=\frac{32805+4}{177147}\)
\(\Rightarrow A=\frac{32809}{177147}\)
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Tínha,frac{2^{10}cdot55+2^{10}cdot26}{2^8cdot27}b,120:{300:[150-(2.53-23.25)]}c,left[left(frac{40}{130}-frac{12}{13}right)cdot40%+0,15right]:frac{-5}{52}d,frac{0,8:left(frac{4}{5}cdot1,25right)}{0,64-frac{1}{25}}+frac{left(1,08-frac{2}{25}right):frac{4}{7}}{left(6frac{5}{9}-3frac{1}{4}right)cdot2frac{2}{17}}+left(1,2+0,5right):frac{1}{5}
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Tính
a,\(\frac{2^{10}\cdot55+2^{10}\cdot26}{2^8\cdot27}\)
b,120:{300:[150-(2.53-23.25)]}
c,\(\left[\left(\frac{40}{130}-\frac{12}{13}\right)\cdot40\%+0,15\right]:\frac{-5}{52}\)
d,\(\frac{0,8:\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)\cdot2\frac{2}{17}}+\left(1,2+0,5\right):\frac{1}{5}\)
Tìm x:
1) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
2) \(2\cdot3^x=10\cdot3^{12}+8\cdot27^4\)
3) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
1) ( 2x -15 )5 = ( 2x - 15 )3
( 2x -15 )5 - ( 2x - 15 )3 = 0
( 2x - 15 )3 . [ ( 2x - 15 )2 - 1 ] = 0
\(\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}}\)
\(\orbr{\begin{cases}2x-15=0\\2x-15=1\end{cases}}\)
\(\orbr{\begin{cases}2x=15\\2x=16\end{cases}}\)
\(\orbr{\begin{cases}x=\frac{15}{2}\\x=8\end{cases}}\)
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1.Tính
a)-1+4-7+10-13+16-...-97+100-103
b)\(\frac{7\cdot\left(27^8-2\cdot9^{11}\right)}{3\cdot\left(81^6-6\cdot13^9\right)}\)
2.Tìm x
(!x!+5).(x2-81)=0
Chú ý ! là giá trị tuyệt đối
=-1+(4-7)+(10-13)+(16-19)+...+(94-97)+(100-103)
=-1+(-3)+(-3)+(-3)+...+(-3)+(-3)(17 cặp)
=-1+(-3)*17
=-1+(-51)
=-52
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\(\dfrac{3}{8}\cdot27\dfrac{1}{5}-51\dfrac{1}{5}\cdot\dfrac{3}{8}+19\)
\(\dfrac{35\dfrac{1}{6}}{\left(\dfrac{-4}{5}\right)}-\dfrac{46\dfrac{1}{6}}{\left(\dfrac{-4}{5}\right)}\)
\(\dfrac{\left(\dfrac{-3}{4}+\dfrac{2}{5}\right)}{\dfrac{3}{7}+\dfrac{\left(\dfrac{3}{5}+\dfrac{-1}{4}\right)}{\dfrac{3}{7}}}\)
a: \(=\dfrac{3}{8}\left(27+\dfrac{1}{5}-51-\dfrac{1}{5}\right)+19\)
\(=-24\cdot\dfrac{3}{8}+19=-9+19=10\)
b: \(=\left(35+\dfrac{1}{6}-46-\dfrac{1}{6}\right):\left(\dfrac{-4}{5}\right)\)
\(=\dfrac{-11\cdot5}{-4}=\dfrac{55}{4}\)
c: \(=\left(\dfrac{-15+8}{20}\right):\left[\dfrac{3}{7}+\dfrac{7}{3}\cdot\dfrac{12-5}{20}\right]\)
\(=\dfrac{-7}{20}:\left(\dfrac{3}{7}+\dfrac{49}{60}\right)\)
\(=-\dfrac{147}{523}\)
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tính
a, \(\left(\dfrac{5}{3}-\dfrac{1}{2}\right):\left(\dfrac{3}{4}-\dfrac{5}{2}\right)\)
b,\(\left(\dfrac{1}{6}+\dfrac{1}{3}\right)^2\cdot\left(1+\dfrac{2}{3}-\dfrac{5}{4}\right)\)
c, \(\dfrac{4^{30}\cdot3^{43}}{2^{57}\cdot27^{15}}\)
c,\(\dfrac{4^{30}.3^{43}}{2^{57}.27^{15}}=\dfrac{\left(2^2\right)^{30}.3^{43}}{2^{57}.\left(3^3\right)^{15}}=\dfrac{2^{60}.3^{43}}{2^{57}.3^{45}}=\dfrac{2^3}{3^2}=\dfrac{8}{9}\)
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a) \(\left(\dfrac{5}{3}-\dfrac{1}{2}\right):\left(\dfrac{3}{4}-\dfrac{5}{2}\right)\)
\(=\left(\dfrac{10}{6}-\dfrac{3}{6}\right):\left(\dfrac{3}{4}-\dfrac{10}{4}\right)\)
\(=\dfrac{7}{6}:\dfrac{-7}{4}\)
\(=\dfrac{7}{6}.\dfrac{4}{-7}\)
\(=-\dfrac{2}{3}\)
b) \(\left(\dfrac{1}{6}+\dfrac{1}{3}\right)^2.\left(1+\dfrac{2}{3}-\dfrac{5}{4}\right)\)
\(=\left(\dfrac{1}{6}+\dfrac{2}{6}\right)^2.\left(\dfrac{12}{12}+\dfrac{8}{12}-\dfrac{15}{12}\right)\)
\(=\left(\dfrac{1}{2}\right)^2.\dfrac{5}{12}\)
\(=\dfrac{1}{4}.\dfrac{5}{12}\)
\(=\dfrac{5}{48}\)
c) \(\dfrac{4^{30}.3^{43}}{2^{57}.27^{15}}\)
\(=\dfrac{4^{30}.27^{40}}{4^{55}.27^{15}}\)
\(=\dfrac{4^{30}.27^{15}.27^{25}}{4^{30}.4^{25}.27^{15}}\)
\(=\dfrac{27^{25}}{4^{25}}\)
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