\(A=\frac{1}{3}\)

\(B=\frac{25}{11}.\frac{13}{12}.\left(-2,2\right)=\frac{-65}{12}\)

\(C=\frac{11}{20}.\left(-\frac{2}{5}\right)=-\frac{11}{50}\)

tự sắp xếp nha

A= 2/3 +3/4  . -4/9

  = 2/3 - 1/3

  = 1/3

B=\(2\frac{3}{11}.1\frac{1}{12}.\left(-2,2\right)\)

  = 25/11.13/12.-11/5

  = (25/11.-11/5).13/12

  = -5 . 13/12

  = -65/12

C= (3/4-0,2)(0,4-4/5)

  = (0,75 - 0,2)( 0,4 - 0,8)

  = 0,55 . -0,4

  = -0,22 = -11/50

Ta có: A= 1/3 ; B=-65/12 ; C= -11/50

=> -65/12 < -11/50 < 0 

Mà 1/3 > 0 => -65/ 12 < -11/50 < 1/3

Vậy b<c<a

\(A=\frac{2}{3}+\frac{3}{4}.\left(-\frac{4}{9}\right)\)

    \(=\frac{2}{3}.\left(-\frac{1}{3}\right)\) 

    \(=-\frac{2}{9}\)

\(B=2\frac{3}{11}.1\frac{1}{12}.\left(-2,2\right)\)

    \(=\frac{25}{11}.\frac{13}{12}.\left(-\frac{11}{5}\right)\)

    \(=\frac{325}{132}.\left(-\frac{11}{5}\right)\)

    \(=-\frac{65}{12}\)

\(C=\left(\frac{3}{4}-0,2\right).\left(0,4-\frac{4}{5}\right)\)

    \(=\frac{11}{20}.\left(-\frac{2}{5}\right)\)

     \(=-\frac{11}{50}\)

Giá trị của các biểu thức sắp sếp từ nhỏ đến lớn là:

        B<C<A

hay: \(-\frac{65}{12}< -\frac{11}{50}< -\frac{2}{9}\)

 ^...^ ^_^

\(A=\frac{2}{3}+\frac{3}{4}.\left(-\frac{4}{9}\right)=\frac{2}{3}+-\frac{1}{3}=\frac{1}{3}\)

\(B=2\frac{3}{11}.1\frac{1}{12}.\left(-2,2\right)=\frac{25}{11}.\frac{13}{12}.\left(-\frac{11}{5}\right)=\frac{325}{132}.\left(-\frac{11}{5}\right)=-\frac{65}{12}\)

\(C=\left(\frac{3}{4}-0,2\right).\left(0,4-\frac{4}{5}\right)=\left(\frac{3}{4}-\frac{1}{5}\right).\left(\frac{2}{5}-\frac{1}{5}\right)=\frac{11}{20}.\frac{1}{5}=\frac{11}{100}\)

Từ 3 kết quả ta so sánh được:        

Vì: \(-\frac{65}{12}

a)\(A=\frac{2}{3}+\frac{3}{4}.-\frac{4}{9}\)

   \(A=\frac{2}{3}-\frac{1}{3}\)

     \(A=\frac{1}{3}\)

b)\(B=2\frac{3}{11}.1\frac{1}{12}.\left(-2,2\right)\)

    \(B=\frac{325}{132}.\left(-2,2\right)\)

      \(B=-\frac{65}{12}\)

c)\(C=\left(\frac{3}{4}-0,2\right).\left(0,4-\frac{4}{5}\right)\)

    \(C=\frac{11}{20}.-\frac{2}{5}\)

     \(C=-\frac{11}{50}\)

              Ta có:\(A=\frac{1}{3}=\frac{100}{300}\)

                        \(B=-\frac{65}{12}=-\frac{1625}{300}\)

                         \(C=-\frac{11}{50}=-\frac{660}{300}\)

                                  Vì \(-\frac{1625}{300}< -\frac{660}{300}< \frac{100}{3}\)

      Vậy \(B< C< A\)

A= 2/3-1/3=1/3 = 0,333..

B=25/11.13/12.(-2,2)= -65/12= -5,41666...

C= 11/20.(-2/5) =-11/50=-0,22

=> B < C < A

\(A=\dfrac{5}{4}\cdot\dfrac{15-4}{3}\cdot\dfrac{-1}{11}=\dfrac{5}{4}\cdot\dfrac{11}{3}\cdot\dfrac{-1}{11}=\dfrac{-5}{12}\)=-50/120

\(B=\dfrac{3}{4}\cdot\dfrac{-1}{12}\cdot\dfrac{-2}{3}=\dfrac{3\cdot2}{4\cdot12\cdot3}=\dfrac{2}{4\cdot12}=\dfrac{1}{24}\)=5/120

\(C=\dfrac{5}{4}\cdot\dfrac{-1}{15}\cdot\dfrac{-2}{5}=\dfrac{2}{4\cdot15}=\dfrac{1}{30}\)=4/120

\(D=3\cdot\dfrac{8-15}{12}\cdot\dfrac{-1}{7}=\dfrac{1}{4}\)=30/120

Vì -50<4<5<30

nên A<C<B<D

A=\(\dfrac{5}{4}\).(5-\(\dfrac{4}{3}\)).(\(-\dfrac{1}{11}\))

= \(\dfrac{5}{4}\).\(\dfrac{11}{3}\).(\(-\dfrac{1}{11}\))

=\(\dfrac{5}{4}\).[\(\dfrac{11}{3}.\left(-\dfrac{1}{11}\right)\text{]}\)

=\(\dfrac{5}{4}.\dfrac{1}{3}\)

=\(\dfrac{5}{12}\) (1)

B=\(\dfrac{3}{4}:\left(-12\right).\left(-\dfrac{2}{3}\right)\) =\(\dfrac{3}{4}:\text{[}\left(-12\right).\left(-\dfrac{2}{3}\right)\text{]}\)

=\(\dfrac{3}{4}:8\) =\(\dfrac{3}{4}.\dfrac{1}{8}\)=\(\dfrac{3}{32}\)(2)

C=\(\dfrac{5}{4}:\left(-15\right).\left(-\dfrac{2}{5}\right)\) =\(\dfrac{5}{4}:\text{[}\left(-15\right).\left(-\dfrac{2}{5}\right)\text{]}\)

=\(\dfrac{5}{4}:6=\dfrac{5}{4}.\dfrac{1}{6}=\dfrac{5}{24}\left(3\right)\)

D=(-3).\(\left(\dfrac{2}{3}-\dfrac{5}{4}\right):\left(-7\right)\) =(-3).\(\left(-\dfrac{7}{12}\right)\):(-7)=\(\dfrac{7}{4}:\left(-7\right)\)=\(\dfrac{7}{4}\).\(\left(\dfrac{-1}{7}\right)\)=\(\dfrac{-1}{4}\) (4)

Từ (1),(2),(3)và(4)=>Ta có thể sắp xếp các kết quả trên theo thứ tự tăng dần là:

(Bạn tự làm nhé! mình bận đi học rồi)

qwertyuiopasdfgggggghjkllzxcvbnmm,.//234567890-=`

\(A=\dfrac{5}{4}\left(5-\dfrac{4}{3}\right)\left(-\dfrac{1}{11}\right)\)

\(A=\dfrac{5}{4}.\dfrac{11}{3}.\left(-\dfrac{1}{11}\right)\)

\(A=-\dfrac{5}{12}\)

\(B=\dfrac{3}{4}:\left(-12\right).\left(-\dfrac{2}{3}\right)\)

\(B=\dfrac{3}{4}.\left(-\dfrac{1}{12}\right).\left(-\dfrac{2}{3}\right)\)

\(B=\dfrac{1}{24}\)

\(C=\dfrac{5}{4}:\left(-15\right).\left(-\dfrac{2}{5}\right)\)

\(C=\dfrac{5}{4}.\left(-\dfrac{1}{15}\right).\left(-\dfrac{2}{5}\right)\)

\(C=\dfrac{1}{30}\)

\(D=\left(-3\right)\left(\dfrac{2}{3}-\dfrac{5}{4}\right):\left(-7\right)\)

\(D=\left(-3\right)\left(-\dfrac{7}{12}\right)\left(-\dfrac{1}{7}\right)\)

\(D=-\dfrac{1}{4}\)

Sắp xếp theo thứ tự tăng dần:

\(A,D,C,B\)

A = (1 - 2/3 + 4/3) - (4/5 - 1) + (7/5 + 2)

A= (3/3 - 2/3 + 4/3) - (4/5 - 5/5) + (7/5 + 10/5)

A= 5/3 + 1/5 + 17/5

A= 5/3 +18/5

A= 25/15 + 54/15

A= 79/15

B= (-3 + 3/4 - 1/3 ) : (5 + 2/5 - 2/3)

B= (-36/12 + 9/12 - 4/12) : (75/15 + 6/15 - 10/15)

B= -31/12 : 71/15

B= -155/284

C= (3/5 - 4/5 ) . (2/7 - 3/14) - (5/9 - 7/27) . (1 - 3/5) + (1 - 11/12) . (1-11/12)

C= -1/5 . 1/14 - 8/27 . 2/5 + 1/12 . 1/12

C=-1/70 - 16/135 + 1/144

C=-216/15120 - 1792/15120 + 105/15120

C=-1903/15120

Vì A= \(\frac{605}{36}\)

B=\(\frac{-1}{24}\)

C=\(\frac{-1}{30}\)

D= \(\frac{-1}{4}\)

tức là  : A= \(\frac{6050}{360}\)

B=\(\frac{-15}{360}\)

C=\(\frac{-12}{360}\)

D=\(\frac{-90}{360}\)

nÊN được sắp xếp theo thứ tự tăng dần là B < C  < D < A

D=