Cách 1 : tính bình thường

(187-23)-(20-180)

=164-(-160)

=164+160

=324

Cách 2: phá ngoặc rồi tính 

(187-23)-(20-180)

=187-23-20+180

=164-20+180

=144+180

=324

(187-23)-(20-180)

=164-(-160)

=324

\(\left(187-23\right)-\left(20-180\right)\)

\(=187-23-20+180\)

\(=164-20+180\)

\(=144+180\)

\(=324\)

(187-23)-(20-180)

=164-(-160)

=164+160

=324

tick nha

7: =-1+8=7

6: \(=-\left(8\cdot125\right)\cdot\left(2\cdot5\right)\cdot\left(25\cdot4\right)=-1000000\)

5: =-50+19+143+79-25-48

=-75+98+95

=23+95

=118

4: =37x9+17x9-35x9-35x11

=18+153-385

=-214

3: =187-23-20+180

=367-43

=324

4: \(=37\cdot9+17\cdot9-35\cdot9-35\cdot11=19\cdot9-385\)

\(=171-385=-214\)

5: =-50+19+143+79-25-48

=-75+94+95

=20+94

=114

3 ; 324

4 ; -214

5 ; 118

6 ; - 1 000 000

7 ; 7

học tốt

Trả lời:

b.(-50+19+143)-(-79+25+48)

= 112 - (-6)

=118

a.(187-23)-(20-180)

= 164- (-160)

=324

         ~Học tốt~

1) 125.(-24) + 24.225.

\(=24\left(-125+225\right)=24.100=2400.\)

2) 512.(2 – 128) – 128. (-512).

\(=512\left(2-128+128\right)=512.2=1024.\)

a) ( -125) + 100 + 80 + 125 + 20

= [ ( -125)+125] + ( 80+20) + 100

= 0 + 100 + 100 = 200

b) 27 + 55 + (-17) + ( - 55)

= [ 27+(-17)] +[ 55+(-55)]

= 10 + 0 = 10

c) (-92) + (-251) + (-8) + 251

= [ (-92) + (-8)] + [ (-251)+251]

= (-100) + 0 = -100.

d) (-31) + (-95) +131 + (-5)

= [ (-31)+131] +[ (-95)+(-5)] = 100 + (-100) = 0

e) (187 - 23) - (20-180)

= 187 - 23 - 20 + 180 = (187-180) - (23-20) = 7 - 3 = 4

g) (-50+19+143) - (-79+25+48)

= -50+19+143 + 79 - 25 - 48

= [ -50-25] + (19 + 79) + 143 - 48

= -75 + 98 + 143 - 48 = 143 - 75 + ( 98 -48)

= 68 + 50 = 118

\(B=\left(17+\dfrac{1}{25}-16-\dfrac{11}{15}\right)\cdot\dfrac{75}{23}+\dfrac{75}{23}\cdot\dfrac{23}{75}\)

\(=\dfrac{23}{75}\cdot\dfrac{75}{23}+1=1+1=2\)