S= 10/56+10/140+.....+10/1400

S= 5/28+5/70+.....+5/700

S= 5/4.7+5/7.10+......+5/25.28

S=5/3( 1/4-1/7+1/7-1/10+......+1/25-1/28)

S= 5/3.(1/4-1/28)

S= 5/3. 3/14

S= 15/42

VẬY S= 15/ 42

M = 10/56+10/140+10/260+10/1400

M= 5/28+5/70+5/130+5/700

3M/5=1/4-1/7+1/7-1/10+1/10-1/13+...+1/25

3M/5 = 3/14

M= 3/14+5/3=5/14

Mình ghi nhầm

ai k mình thì nói cho mình biết để mình k lại

\(=\frac{5}{28}+\frac{5}{70}+\frac{5}{130}+...+\frac{5}{700}\)

\(=\frac{5}{3}\left(\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{25.28}\right)\)

\(=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{25}-\frac{1}{28}\right)\)

\(=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{28}\right)\)

\(=\frac{5}{3}\times\frac{3}{14}\)

\(=\frac{5}{14}\)

Dat A=10/56+10/140+.....+10/1400

=> A=5/28+5/70+.....+5/700

A=5/4.7+5/7.10+.....+5/25.28

3A=5/3.(1/4-1/7+1/7-1/10+.....+1/25-1/28)

3A=5/3.(1/4-1/28)

3A=5/3.3/14

3A=5/14

A=5/13:3

A=5/39    

\(\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+...+\frac{10}{1400}\)

\(=\frac{5}{28}+\frac{5}{70}+\frac{5}{130}+...+\frac{5}{700}\)

\(=\frac{5}{4.7}+\frac{5}{7.10}+\frac{5}{10.13}+....+\frac{5}{25.28}\)

\(=\frac{5}{3}.\left(\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+....+\frac{3}{25.28}\right)\)

\(=\frac{5}{3}.\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{25}-\frac{1}{28}\right)\)

\(=\frac{5}{3}.\left(\frac{1}{4}-\frac{1}{28}\right)=\frac{5}{14}\)

Ta có : 

\(S=3+\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^9}\)

\(2S=6+3+\frac{3}{2}+...+\frac{3}{2^8}\)

\(2S-S=\left(6+3+\frac{3}{2}+...+\frac{3}{2^8}\right)-\left(3+\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^9}\right)\)

\(S=6-\frac{3}{2^9}\)

\(S=\frac{2^{10}.3-3}{2^9}\)

Vậy \(S=\frac{2^{10}.3-3}{2^9}\)

vận dụng 3S lên

xong tìm S nha bn ok

tại k có thời gian nên chỉ giúp thế thôi

B = 10/56 + 10/140 + 10/260 + ...+ 10/1400      

B= 5/28 + 5/70 +.....+10/700 
= 5/(4.7)+5/(7.10)+....5/(25.28) 
3B= 5( 1/4 - 1/7 +1/7-1/10+......+1/25-1/28) 
3B = 5 (1/4-1/28) 
3B=15/14 
B = 15/14 : 3 

B = 5/14

Doãn Hải Anh mk lớp 7 nên quên òi 

Ta có:\(\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+...+\frac{10}{1400}\)

       =\(\frac{5}{3}\times\left(\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+...+\frac{3}{700}\right)\)  

      =\(\frac{5}{3}\times\left(\frac{3}{4\times7}+\frac{3}{7\times10}+\frac{3}{10\times13}+...+\frac{3}{25\times28}\right)\)  

      =\(\frac{5}{3}\times\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{25}-\frac{1}{28}\right)\)

      =\(\frac{5}{3}\times\left(\frac{1}{4}-\frac{1}{28}\right)\)

      =\(\frac{5}{3}\times\frac{3}{14}\)

      =\(\frac{5}{14}\)

Ko bít có đúng ko nhưng cứ thử nhé

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