20/34 + 7/21 + 19/34 - 20/15 + 3/7=?
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15/34 + 7/21 + 19/34 - 20/15 + 3/7
\(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-\frac{20}{15}+\frac{3}{7}\)
\(=\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{7}{21}-\frac{20}{15}\right)+\frac{3}{7}\)
\(=1+1+\frac{3}{7}=2\frac{3}{7}=\frac{17}{7}\)
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15 phần 34 + 7 phần 21 +19 phần 34 - 20 phần 15 +3 phần 7 = ?
\(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-\frac{20}{15}+\frac{3}{7}\)
\(\frac{15}{34}+\frac{1}{3}+\frac{19}{34}+\left(-\frac{4}{3}\right)+\frac{3}{7}\)
\(\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{1}{3}-\frac{4}{3}\right)+\frac{3}{7}\)
\(1+\left(-1\right)+\frac{3}{7}\)
\(=0+\frac{3}{7}=\frac{3}{7}\)
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\(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-\frac{20}{15}+\frac{3}{7}\)
\(=\)\(\frac{15}{34}+\frac{1}{3}+\frac{19}{34}+\left(-\frac{4}{3}\right)+\frac{3}{7}\)
\(=\)\(\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{1}{3}-\frac{4}{3}\right)+\frac{3}{7}\)
\(=\)\(1+\left(-1\right)+\frac{3}{7}\)
\(=\)\(0+\frac{3}{7}\)
\(=\)\(\frac{3}{7}\)
15/34+7/21+19/34-20/15
=15/34+19/34+1/3-4/3
=1-1
=0
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19 /34 + 7/21 + 15/34 - 20/15 +3/7 = ?
Tính giá trị của biểu thức:
a, 15/34 +7/21+19/34-20/15+3/7
b, 12-8×(3/2)^3
c,(1/9)^2005×9^2005-96^2÷24^2
\(a,\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-\frac{20}{15}+\frac{3}{7}\)
\(=>\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{7}{21}+\frac{3}{7}\right)-\frac{20}{15}\)
\(=>1+\frac{16}{21}-\frac{20}{15}\)
\(=>\frac{37}{21}-\frac{20}{15}\)
\(=>\frac{3}{7}\)
\(b,12-8\cdot\left(\frac{3}{2}\right)^3\)
\(=>12-8\cdot\frac{27}{8}\)
\(=>12-27\)
\(=>-15\)
\(c,\left(\frac{1}{9}\right)^{2005}\cdot9^{2005}-96^2:24^2\)
\(=>\left(\frac{1^{2005}^{ }}{9^{2005}}\cdot9^{2005}\right)-\left(96^2:24^2\right)\)
\(=>\left(1^{2005}\right)-16\)
\(=>1-16\)
\(=>-15\)
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\(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-\frac{20}{15}+\frac{1}{6}\)
Giúp mình với mình bị trừ điểm hỏi đáp rồi
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\(\frac{15}{31}+\frac{7}{21}+\frac{19}{34}-\frac{20}{15}+\frac{1}{6}\)
\(=\frac{15}{31}+\frac{1}{3}+\frac{19}{34}-\frac{20}{15}+\frac{1}{6}\)
\(=\frac{76}{93}+\frac{19}{34}-\frac{20}{15}+\frac{1}{6}\)
\(=1,37602783-\frac{20}{15}+\frac{1}{6}\)
\(=1,37602783-\frac{4}{3}+\frac{1}{6}\)
\(=0,04269449667+\frac{1}{6}\)
\(=0,2093611633\)
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\(Câu 1) \dfrac {15} {34} + \dfrac {7} {21} + \dfrac {19} {34}-1\dfrac {15} {17}+\dfrac {3} {5} Câu 2) \dfrac {(5)^{4}.(20)^{4}} {(24)^{4}.45}\)
Câu 1:
\(=\dfrac{15}{34}+\dfrac{19}{34}-1-\dfrac{15}{17}+\dfrac{1}{3}+\dfrac{3}{5}\)
\(=-\dfrac{15}{17}+\dfrac{14}{15}=\dfrac{13}{255}\)
Câu 2:
\(=\dfrac{5^4\cdot5^4\cdot2^8}{4^4\cdot6^4\cdot3^2\cdot5}=\dfrac{5^7}{6^4\cdot3^2}\)
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I. thực hiện phép tính
a. \(\dfrac{15}{34}+\dfrac{7}{21}+\dfrac{19}{34}-\dfrac{20}{15}+\dfrac{3}{7}\)
b. \(\dfrac{27}{25}+\dfrac{4}{21}-\dfrac{2}{25}+\dfrac{17}{21}-\dfrac{1}{2}\)
a, \(\dfrac{15}{34}+\dfrac{7}{21}+\dfrac{19}{34}-\dfrac{20}{15}+\dfrac{3}{7}\)
= \(\left(\dfrac{15}{34}+\dfrac{19}{34}\right)+\left(\dfrac{7}{21}+\dfrac{3}{7}\right)-\dfrac{20}{15}\)
= 1 + \(\dfrac{16}{21}-\dfrac{20}{15}\)
= \(\dfrac{3}{7}\)
b, \(\dfrac{27}{25}+\dfrac{4}{21}-\dfrac{2}{25}+\dfrac{17}{21}-\dfrac{1}{2}\)
= \(\left[\dfrac{27}{25}+\left(-\dfrac{2}{25}\right)\right]+\left(\dfrac{4}{21}-\dfrac{7}{21}\right)-\dfrac{1}{2}\)
= 1 + \(\left(\dfrac{-1}{7}\right)-\dfrac{1}{2}\) = \(\dfrac{5}{14}\)
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Giúp mình với mà đúng mới like nhé
A/ 15/34+7/21+19/37-20/15+3/7
B/ 3/8.27/1/5-51/1/5.3/8+19
C/ -2/7.21/8.-7/2
Answer:
\(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-\frac{20}{15}+\frac{3}{7}\) (Mình đã sửa đề nhé.)
\(=\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{7}{21}+\frac{3}{7}\right)-\frac{20}{15}\)
\(=1+\left(-1\right)+\frac{3}{7}\)
\(=\frac{3}{7}\)
\(\frac{3}{8}.27\frac{1}{5}-51\frac{1}{5}.38+19\)
\(=\frac{3}{8}\left(-24\right).38+19\)
\(=-342+19\)
\(=-323\)
\(-\frac{2}{7}.\frac{21}{8}.-\frac{7}{2}\)
\(=\left(\frac{-2}{7}.\frac{-7}{2}\right)\frac{21}{8}\)
\(=\frac{21}{8}\)